Problem 26
Question
Graph the points. Determine whether they are vertices of a right triangle. $$ (5,4),(2,1),(-3,2) $$
Step-by-Step Solution
Verified Answer
By plotting the points on graph paper, calculating the distances between each pair, and checking if those distances satisfy the Pythagorean theorem, we can determine if the given points are vertices of a right triangle.
1Step 1: Plotting the Points
Plot the given points (5,4),(2,1),(-3,2) on the Cartesian plane.
2Step 2: Calculating Euclidean Distances
Calculate the Euclidean distance between each pair of points to determine the lengths of the triangle's sides. The formula for the distance between two points \((x1, y1)\) and \((x2, y2)\) is \( \sqrt{(x2-x1)^2 + (y2-y1)^2} \). So, calculate the distance between points (5,4) and (2,1), points (5,4) and (-3,2), and points (2,1) and (-3,2).
3Step 3: Applying Pythagorean Theorem
Use the Pythagorean theorem, \(a^2 + b^2 = c^2\), where c is the length of the hypotenuse and a and b are the lengths of the other two sides, to check if the points form a right triangle. If they satisfy the equation, then they indeed form a right triangle.
Key Concepts
Cartesian PlaneEuclidean DistancePythagorean Theorem
Cartesian Plane
The Cartesian Plane, or coordinate plane, is a two-dimensional surface where each point is identified by a pair of numerical coordinates. These coordinates determine the position of the point on the plane relative to the horizontal and vertical axes.
To plot a point like (5,4) on the Cartesian Plane:
- The horizontal axis is known as the x-axis.
- The vertical axis is called the y-axis.
To plot a point like (5,4) on the Cartesian Plane:
- Start at the origin \( (0,0) \).
- Move 5 units in the positive direction along the x-axis.
- Then move 4 units up in the positive direction along the y-axis.
Euclidean Distance
Euclidean Distance is a measure of the "straight line" distance between two points in the Cartesian Plane. It is derived from the Pythagorean Theorem and is the most commonly used distance metric in geometry.
The formula for finding the distance \( d \) between two points \( (x1, y1) \) and \( (x2, y2) \) is: \[ d = \sqrt{(x2-x1)^2 + (y2-y1)^2} \]
The formula for finding the distance \( d \) between two points \( (x1, y1) \) and \( (x2, y2) \) is: \[ d = \sqrt{(x2-x1)^2 + (y2-y1)^2} \]
- This formula calculates the hypotenuse of a right triangle formed by the horizontal and vertical differences between two points.
- The differences \( (x2-x1) \) and \( (y2-y1) \) are the horizontal and vertical legs of the right triangle, respectively.
Pythagorean Theorem
The Pythagorean Theorem is a fundamental principle in geometry that defines the relationship between the sides of a right triangle. According to this theorem, in a right triangle with sides \(a\), \(b\), and the hypotenuse \(c\), we have:\[ a^2 + b^2 = c^2 \]The hypotenuse is the longest side of the right triangle, opposite the right angle.
This theorem helps verify if a set of three points forms a right triangle:
This theorem helps verify if a set of three points forms a right triangle:
- Calculate the distances between each pair of points to get the lengths of the sides.
- Identify the longest side; this should be \(c\).
- Check if the sum of the squares of the other two sides equals the square of \(c\).
Other exercises in this chapter
Problem 26
Solve the percent problem. (Lesson 3.9) How much is \(15 \%\) of 15 dollars?
View solution Problem 26
Find the midpoint of the line segment connecting the given points. Then show that the midpoint is the same distance from each point. \((3,0),(-5,4)\)
View solution Problem 26
Find the term that should be added to the expression to create a perfect square trinomial. $$ x^{2}+4 x $$
View solution Problem 26
Evaluate the expression without using a calculator. $$ 4^{3 / 2} $$
View solution