Problem 26
Question
For the following exercises, find the equations of the asymptotes for each hyperbola. $$ \frac{y^{2}}{3^{2}}-\frac{x^{2}}{3^{2}}=1 $$
Step-by-Step Solution
Verified Answer
The equations of the asymptotes are \( y = x \) and \( y = -x \).
1Step 1: Identify the standard form of the hyperbola equation
The given equation is \( \frac{y^2}{3^2} - \frac{x^2}{3^2} = 1 \). This is in the standard form for a vertical hyperbola: \( \frac{y^2}{b^2} - \frac{x^2}{a^2} = 1 \), where \( a = 3 \) and \( b = 3 \).
2Step 2: Recall the formula for the asymptotes of a vertical hyperbola
For a vertical hyperbola \( \frac{y^2}{b^2} - \frac{x^2}{a^2} = 1 \), the asymptotes have the equations \( y = \pm \frac{b}{a} x \).
3Step 3: Substitute the values of a and b into the asymptotes' formula
Substituting \( a = 3 \) and \( b = 3 \) into the formula, we get \( y = \pm \frac{3}{3} x \), which simplifies to \( y = \pm x \).
Key Concepts
Standard Form of a HyperbolaVertical HyperbolaEquation of Asymptotes
Standard Form of a Hyperbola
A hyperbola is a type of conic section that can be represented in a standardized way referred to as its standard form. Understanding the standard form is crucial for determining the properties and characteristics of the hyperbola, including its asymptotes. The standard form of a hyperbola depends on whether it opens vertically or horizontally.
The given exercise features a hyperbola in standard form for vertical orientation:
The given exercise features a hyperbola in standard form for vertical orientation:
- For a vertical hyperbola, the standard form is:\[\frac{y^2}{b^2} - \frac{x^2}{a^2} = 1\]
- This format highlights that the hyperbola opens upwards and downwards from the center.
- The values of \(a\) and \(b\) determine the size and shape of the hyperbola. It's important to distinguish \(a^2\) and \(b^2\) by their respective positions: \(y^2\) over \(b^2\) and \(x^2\) over \(a^2\).
Vertical Hyperbola
In a vertical hyperbola, the main axis along which the hyperbola extends is vertical. This means the hyperbola opens up and down rather than left and right. The standard form for a vertical hyperbola is \( \frac{y^2}{b^2} - \frac{x^2}{a^2} = 1 \).
- In the equation \( \frac{y^2}{9} - \frac{x^2}{9} = 1 \), both \(a^2\) and \(b^2\) are equal, indicating that the hyperbola components are symmetric around both axes.
- This symmetry can provide a simpler equation for asymptotes, as seen with\(a = b\).
Equation of Asymptotes
Asymptotes are lines that a hyperbola approaches but never actually touches. They define the shape of the hyperbola's open ends and can be found using the hyperbola's equation. For a vertical hyperbola, the asymptotes have the formula \( y = \pm \frac{b}{a} x \).
- Substitute \(a\) and \(b\) from the standard equation \( \frac{y^2}{3^2} - \frac{x^2}{3^2} = 1 \). Here, \(a = 3\) and \(b = 3\), so the asymptotes' equation simplifies to \( y = \pm x \).
- These asymptotic lines provide boundaries that the hyperbola gets infinitely close to as it extends along the axes.
- They are crucial for graphing the hyperbola and understanding its orientation and spread.
Other exercises in this chapter
Problem 26
For the following exercises, rewrite the given equation in standard form, and then determine the vertex \((V),\) focus \((F),\) and directrix \((d)\) of the par
View solution Problem 26
For the following exercises, write the equation of an ellipse in standard form, and identify the end points of the major and minor axes as well as the foci. $$
View solution Problem 26
Find the equations of the asymptotes for each hyperbola. \(\frac{y^{2}}{3^{2}}-\frac{x^{2}}{3^{2}}=1\)
View solution Problem 27
For the following exercises, identify the conic with a focus at the origin, and then give the directrix and eccentricity. $$ r(2-\cos \theta)=1 $$
View solution