Problem 26
Question
For Problems 21-36, use the technique discussed in this section to find the multiplicative inverse (if one exists) of each matrix. $$ \left[\begin{array}{rr} -3 & 1 \\ 3 & -2 \end{array}\right] $$
Step-by-Step Solution
Verified Answer
The inverse of the matrix is \( \begin{bmatrix} \frac{-2}{3} & \frac{-1}{3} \\ -1 & -1 \end{bmatrix} \).
1Step 1: Calculate the Determinant
To find the inverse of a matrix, it must be invertible, which means its determinant should not be zero. The determinant of a 2x2 matrix \( \begin{bmatrix} a & b \ c & d \end{bmatrix} \) is calculated as \( ad - bc \). For the matrix \( \begin{bmatrix} -3 & 1 \ 3 & -2 \end{bmatrix} \), calculate the determinant as follows: \[-3(-2) - (1)(3) = 6 - 3 = 3\].
2Step 2: Check Invertibility
Since the determinant we calculated in Step 1 is 3 (which is not zero), the matrix is invertible. Thus, we can proceed to find its inverse.
3Step 3: Formulate the Inverse Matrix
The formula for finding the inverse of a 2x2 matrix \( \begin{bmatrix} a & b \ c & d \end{bmatrix} \) is \( \frac{1}{ad - bc} \begin{bmatrix} d & -b \ -c & a \end{bmatrix} \). Use this formula for our specific matrix: \[ \frac{1}{3} \begin{bmatrix} -2 & -1 \ -3 & -3 \end{bmatrix} \].
4Step 4: Simplify the Inverse Matrix
Multiply each entry in the matrix by \( \frac{1}{3} \) to simplify:\[ \begin{bmatrix} \frac{-2}{3} & \frac{-1}{3} \ -1 & -1 \end{bmatrix} \]. This is the multiplicative inverse of the original matrix.
Key Concepts
Determinant of a matrix2x2 MatrixMatrix Invertibility
Determinant of a matrix
The determinant of a matrix is a special number that can be calculated from its elements. For a 2x2 matrix, the determinant helps us determine if a matrix is invertible. If the determinant is zero, the matrix cannot be inverted. For any 2x2 matrix, written as:
- \[\begin{bmatrix} a & b \ c & d \end{bmatrix}\]
- \[ad - bc\]
- \[(-3 imes -2) - (1 imes 3) = 6 - 3 = 3\]
2x2 Matrix
A 2x2 matrix is a simple form of a mathematical matrix. It has two rows and two columns, making it straightforward to work with, especially for newcomers to linear algebra. Often represented as:
- \[\begin{bmatrix} a & b \ c & d \end{bmatrix}\]
Matrix Invertibility
Matrix invertibility is the condition that tells us whether a matrix has an inverse. In simpler terms, it's the ability to "reverse" a matrix operation. For a matrix to be invertible, its determinant must be a non-zero value. When dealing specifically with 2x2 matrices, determining invertibility involves:
- Calculating the determinant using the formula: \[ad - bc\]
- Ensuring the result is non-zero.
Other exercises in this chapter
Problem 25
For Problems \(19-26\), compute \(A B\). $$ A=\left[\begin{array}{ll} -2 & -3 \\ -5 & -6 \end{array}\right], \quad B=\left[\begin{array}{r} 5 \\ -2 \end{array}\
View solution Problem 25
For Problems \(13-26\), compute \(A B\) and \(B A\). $$ A=\left[\begin{array}{ll} 5 & 6 \\ 2 & 3 \end{array}\right], \quad B=\left[\begin{array}{rr} 1 & -2 \\ -
View solution Problem 26
For Problems \(19-26\), compute \(A B\). $$ A=\left[\begin{array}{rr} -3 & -5 \\ 4 & -7 \end{array}\right], \quad B=\left[\begin{array}{r} -3 \\ -10 \end{array}
View solution Problem 26
For Problems \(13-26\), compute \(A B\) and \(B A\). $$ A=\left[\begin{array}{rr} -3 & -5 \\ 2 & 4 \end{array}\right], \quad B=\left[\begin{array}{rr} -2 & -\fr
View solution