Problem 26
Question
For Exercises 21 to \(32,\) solve for \(y\). $$2 x+3 y=9$$
Step-by-Step Solution
Verified Answer
The solution to the equation is \(y = 3 - \frac{2}{3}x\).
1Step 1: Isolate the term with 'y'
First, the term with 'y' in the equation \(2x + 3y = 9\) needs to be isolated. This can be achieved by moving the '2x' term to the other side of the equation. It is done by subtracting '2x' from both sides. This gives us the equation \(3y = 9 - 2x\).
2Step 2: Solve for 'y'
We now need to isolate 'y' by dividing both sides of the equation by \(3\). This gives us the equation \(y = \frac{(9 - 2x)}{3}\).
3Step 3: Simplify the equation
Finally, simplify the equation by breaking the fraction into two separate fractions: \(y = \frac{9}{3} - \frac{2x}{3}\) simplifies to \(y = 3 - \frac{2}{3}x\).
Key Concepts
Solving for a VariableIsolating TermsFraction Simplification
Solving for a Variable
When you encounter an equation that requires you to solve for a specific variable, you aim to express that variable in terms of the other variables or constants in the equation. In the original exercise, we needed to solve for the variable 'y' in the equation:
- \(2x + 3y = 9\)
Isolating Terms
Isolating terms means rearranging the equation to get the term of interest by itself on one side of the equation. For the equation:
- \(2x + 3y = 9\)
- \(3y = 9 - 2x\)
Fraction Simplification
Fraction simplification is a critical skill, especially when dealing with linear equations, as it makes the expression cleaner and easier to interpret. In our exercise, once we isolated 'y', we reached the equation:
- \(y = \frac{9 - 2x}{3}\)
- \(y = \frac{9}{3} - \frac{2x}{3}\)
- \(y = 3 - \frac{2}{3}x\)
Other exercises in this chapter
Problem 26
True or false? \(\frac{3}{x-8}+\frac{3}{8-x}=0\)
View solution Problem 26
Solve. $$\frac{2}{3 x-1}=\frac{3}{4 x+1}$$
View solution Problem 26
Find the LCM of the polynomials. $$\begin{aligned} &3 x^{2}-11 x+6\\\ &3 x^{2}+4 x-4 \end{aligned}$$
View solution Problem 26
Simplify. $$\frac{4-y^{2}}{y^{2}-3 y-10}$$
View solution