Problem 26
Question
For each equation, find the slope \(m\) and \(y\) -intercept \((0, b)\) (when they exist) and draw the graph. \(x=2 y+4\)
Step-by-Step Solution
Verified Answer
Slope is \(\frac{1}{2}\), \(y\)-intercept is \((0, -2)\).
1Step 1: Rewrite the Equation in Slope-Intercept Form
Start by rewriting the equation \(x = 2y + 4\) to get it into the slope-intercept form \(y = mx + b\). The slope-intercept form makes it easier to identify the slope \(m\) and the \(y\)-intercept \((0, b)\).First, solve for \(y\) by isolating it:\[x = 2y + 4\]Subtract 4 from both sides:\[x - 4 = 2y\]Divide each term by 2 to solve for \(y\):\[y = \frac{x}{2} - 2\]Now, the equation is in slope-intercept form \(y = \frac{1}{2}x - 2\).
2Step 2: Identify the Slope and Y-Intercept
From the equation \(y = \frac{1}{2}x - 2\), identify the slope \(m\) as the coefficient of \(x\), which is \(\frac{1}{2}\), and the \(y\)-intercept \((0, b)\) as \(-2\). This tells us:- Slope (\(m\)) is \(\frac{1}{2}\).- \(y\)-intercept is \((0, -2)\).
3Step 3: Draw the Graph
To draw the graph, start by plotting the \(y\)-intercept \((0, -2)\) on the coordinate plane. Then, use the slope \(\frac{1}{2}\) to plot another point. From the \(y\)-intercept, move up 1 unit and right 2 units, since the slope \(\frac{1}{2}\) means 'rise over run'. This gives you another point: \((2, -1)\).Draw a line through the two points \((0, -2)\) and \((2, -1)\) to complete the graph.
Key Concepts
Linear EquationsGraphingCoordinate Plane
Linear Equations
Linear equations are mathematical expressions that form a straight line when graphed on a coordinate plane. Each linear equation can be written in different forms, but the most commonly used form is the slope-intercept form, which is: \[ y = mx + b \]Here:
- \( m \) is the slope of the line. It describes how steep the line is. A positive slope means the line ascends, while a negative slope indicates a descending line.
- \( b \) is the y-intercept. This is the point where the line crosses the y-axis.
Graphing
Graphing is a crucial skill in understanding linear equations visually. Once you have a linear equation in the slope-intercept form, you can easily graph it by following these steps:
- Begin by identifying the y-intercept \( b \). This tells you where your line will cross the y-axis. For example, if \( b = -2 \), you place your first point at \((0, -2)\).
- Use the slope \( m \) to plot another point starting from the y-intercept. The slope \( \frac{1}{2} \) suggests a rise of 1 unit for every 2 units run, or right. From the point \((0, -2)\), move up 1 unit and over 2 units to the right, placing the next point at \((2, -1)\).
- To complete the graph, draw a straight line through these points. Extend the line across the grid as desired. This line represents all solutions to the equation \( y = \frac{1}{2}x - 2 \).
Coordinate Plane
The coordinate plane is a two-dimensional surface on which you can graph points, lines, and curves. It consists of a horizontal number line known as the x-axis, and a vertical number line, called the y-axis. These axes intersect at a point called the origin, denoted as \((0, 0)\). When graphing a linear equation, like in our example, this serves as the stage for plotting points and drawing lines:
- Each point on the plane represents a pair of values from the equation \((x, y)\).
- First, locate the y-intercept \((0, b)\), where the line crosses the y-axis.
- Next, use the slope to determine the second point. You can then draw the line to show the full equation.
Other exercises in this chapter
Problem 25
Graph each function "by hand." [Note: Even if you have a graphing calculator, it is important to be able to sketch simple curves by finding a few important poin
View solution Problem 25
$$ \text { Graph each function } $$ $$ f(x)=3^{x} $$
View solution Problem 26
Evaluate each expression without using a calculator. $$ (-27)^{5 / 3} $$
View solution Problem 26
Graph each function "by hand." [Note: Even if you have a graphing calculator, it is important to be able to sketch simple curves by finding a few important poin
View solution