Problem 26
Question
Find \(y^{(4)}=d^{4} y / d x^{4}\) if $$ \text { a. }y=-2 \sin x . \quad \text { b. } \quad y=9 \cos x $$
Step-by-Step Solution
Verified Answer
a. \(y^{(4)} = -2 \sin x\); b. \(y^{(4)} = 9 \cos x\).
1Step 1: Understand the Problem
We are given two different functions for which we need to find the fourth derivative with respect to \(x\). For part (a), we have \(y = -2 \sin x\) and for part (b), \(y = 9 \cos x\).
2Step 2: Derivative of Sine Function
For the function \(y = -2 \sin x\), the first derivative is \(y' = -2 \cos x\).
3Step 3: Successive Derivatives of Sine Function
From \(y' = -2 \cos x\), differentiate to get \(y'' = 2 \sin x\).Differentiate again to get \(y^{(3)} = 2 \cos x\).Differentiate one more time to get the fourth derivative \(y^{(4)} = -2 \sin x\).
4Step 4: Verify Sine Function Fourth Derivative
Observe that taking the fourth derivative of \(y = -2 \sin x\) returns to the original function due to cyclic behavior of sine derivatives: \(y^{(4)} = -2 \sin x\).
5Step 5: Derivative of Cosine Function
For \(y = 9 \cos x\), the first derivative is \(y' = -9 \sin x\).
6Step 6: Successive Derivatives of Cosine Function
From \(y' = -9 \sin x\), differentiate to get \(y'' = -9 \cos x\).Differentiate again to get \(y^{(3)} = 9 \sin x\).Differentiate one more time to get the fourth derivative \(y^{(4)} = 9 \cos x\).
7Step 7: Verify Cosine Function Fourth Derivative
Notice that for the cosine function, the fourth derivative loops back to the original function: \(y^{(4)} = 9 \cos x\).
Key Concepts
Trigonometric FunctionsSine FunctionCosine Function
Trigonometric Functions
Trigonometric functions are essential in mathematics and are frequently used for modeling periodic phenomena. Two of the basic trigonometric functions are the sine and cosine functions. Trigonometric functions can be visualized as unit circle rotations, where each point on the circle represents an angle and its arc length. These functions are periodic, which means their values repeat at regular intervals, specifically every \(2\pi\) radians. This periodic nature is particularly important when working with derivatives. For instance, finding the fourth derivatives of sine and cosine functions illustrates this periodicity because the functions naturally loop back to their original forms. Understanding this concept helps when calculating higher order derivatives.
Sine Function
The sine function, denoted as \( \sin x \), is a fundamental trigonometric function that represents the y-coordinate of a point on a unit circle. When we differentiate \( \sin x \), we observe a cycle of derivative changes:
- The first derivative of \( \sin x \) is \( \cos x \).
- The second derivative of \( \sin x \) is \( -\sin x \).
- The third derivative of \( \sin x \) is \( -\cos x \).
- The fourth derivative takes us back to \( \sin x \).
Cosine Function
The cosine function, denoted as \( \cos x \), is another primary trigonometric function that represents the x-coordinate of a point on a unit circle. Like the sine function, the cosine function also exhibits a cycle of derivatives:
- The first derivative of \( \cos x \) is \( -\sin x \).
- The second derivative of \( \cos x \) is \( -\cos x \).
- The third derivative of \( \cos x \) is \( \sin x \).
- The fourth derivative returns to \( \cos x \).
Other exercises in this chapter
Problem 26
Find the derivatives of the functions in Exercises \(19-38\) $$ y=\frac{1}{x} \sin ^{-5} x-\frac{x}{3} \cos ^{3} x $$
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Use the formula $$ f^{\prime}(x)=\lim _{z \rightarrow x} \frac{f(z)-f(x)}{z-x} $$ to find the derivative of the functions in Exercises \(23-26\) $$ g(x)=1+\sqrt
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