Problem 26
Question
Find the standard form of the equation of each parabola satisfying the given conditions. Vertex: \((5,-2) ;\) Focus: \((7,-2)\)
Step-by-Step Solution
Verified Answer
The standard form of the parabolic equation is \((y+2)^2 = 8(x-5)\)
1Step 1: Identify the shift
From the problem, the vertex \((h = 5, k = -2)\) will shift the graph horizontally and vertically.
2Step 2: Identify the direction and compute a
The Focus \((7,-2)\) lies to the right of the vertex which indicates the parabola needs to open to the right. Knowing the vertex and the focus, one can find a as the difference in the x-coordinates of these two points. Thus, a = 7 - 5 = 2.
3Step 3: Write the equation
Using the standard form equation of a horizontal parabola (y - k)² = 4a(x - h), substitute h = 5, k = -2, a = 2 to get the equation of the parabola: \((y + 2)^2 = 4*2*(x - 5)\), which simplifies to \( (y+2)^2 = 8(x-5) \)
Other exercises in this chapter
Problem 25
Find the standard form of the equation of each parabola satisfying the given conditions. Vertex: \((2,-3) ;\) Focus: \((2,-5)\)
View solution Problem 25
Find the standard form of the equation of each ellipse satisfying the given conditions. $$\text { Foci: }(-5,0),(5,0) ; \text { vertices: }(-8,0),(8,0)$$
View solution Problem 26
Find the standard form of the equation of each ellipse satisfying the given conditions. $$\text { Foci: }(-2,0),(2,0) ; \text { vertices: }(-6,0),(6,0)$$
View solution Problem 27
Find the standard form of the equation of each ellipse satisfying the given conditions. $$\text { Foci: }(0,-4),(0,4) ; \text { vertices: }(0,-7),(0,7)$$
View solution