Problem 26
Question
Find the first five terms of the sequence, and determine whether it is geometric. If it is geometric, find the common ratio, and express the \(n\) th term of the sequence in the standard form \(a_{n}=a r^{n-1}.\) $$a_{n}=(-1)^{n} 2^{n}$$
Step-by-Step Solution
Verified Answer
The sequence is geometric with common ratio -2; the nth term is \(a_n = -2(-2)^{n-1}\).
1Step 1: Find the First Five Terms
To find the first five terms of the sequence given by \( a_n = (-1)^n 2^n \), substitute \( n = 1, 2, 3, 4, \) and \( 5 \) into the formula:- For \( n = 1 \), \( a_1 = (-1)^1 2^1 = -2 \).- For \( n = 2 \), \( a_2 = (-1)^2 2^2 = 4 \).- For \( n = 3 \), \( a_3 = (-1)^3 2^3 = -8 \).- For \( n = 4 \), \( a_4 = (-1)^4 2^4 = 16 \).- For \( n = 5 \), \( a_5 = (-1)^5 2^5 = -32 \).Thus, the first five terms of the sequence are \(-2, 4, -8, 16, -32\).
2Step 2: Check for Geometric Sequence
To check if the sequence is geometric, find the ratio of the consecutive terms. - From \(a_2\) to \(a_1\), the ratio is \( \frac{4}{-2} = -2 \).- From \(a_3\) to \(a_2\), the ratio is \( \frac{-8}{4} = -2 \).- From \(a_4\) to \(a_3\), the ratio is \( \frac{16}{-8} = -2 \).- From \(a_5\) to \(a_4\), the ratio is \( \frac{-32}{16} = -2 \).Since the ratio \(-2\) remains constant, the sequence is geometric with a common ratio of \(-2\).
3Step 3: Express the nth Term in Standard Form
Since the sequence is geometric with common ratio \( r = -2 \) and first term \( a_1 = -2 \), the general form of the nth term can be expressed as:\[ a_n = a_1 r^{n-1} \]Substitute the values:\[ a_n = -2 (-2)^{n-1} \]
Key Concepts
Common RatioSequence TermsGeometric Progression
Common Ratio
A common ratio is a key feature of a geometric sequence. It is the constant factor between each pair of consecutive terms in the sequence. To identify if a series is geometric, we examine this focal point.
Let’s look at the given sequence:
This constant factor confirms that the sequence is geometric.
In a geometric sequence, maintaining the same ratio across terms is essential. It ensures that each term after the first is derived from multiplying the previous term by the common ratio.
Let’s look at the given sequence:
- The first five terms are \, \(-2, 4, -8, 16, -32\).
- To find the common ratio, divide each term by the previous one.
- For example: the ratio from the second term to the first term is \( \frac{4}{-2} = -2 \).
- Check each pair: \( \frac{-8}{4} = -2 \), \( \frac{16}{-8} = -2 \), and \( \frac{-32}{16} = -2 \).
This constant factor confirms that the sequence is geometric.
In a geometric sequence, maintaining the same ratio across terms is essential. It ensures that each term after the first is derived from multiplying the previous term by the common ratio.
Sequence Terms
The sequence terms represent the individual elements of a sequence. In our case, they are derived from the expression \(a_{n} = (-1)^{n} 2^{n}\).
Understanding their calculation is vital to grasp the overall pattern and nature of the sequence. The formula must be followed carefully for each term to ensure precision.
Comprehending these terms enables the analysis of their distribution and behavior over time.
- Each term of the sequence is generated by substituting successive values of \(n\) into the expression.
- For \(n = 1\), the term is \(-2\). For \(n = 2\), it's \(4\), followed by \(-8, 16, -32\) for \(n = 3, 4, 5\), respectively.
- This pattern of alternating positive and negative numbers arises from the \((-1)^{n}\) part of the formula.
Understanding their calculation is vital to grasp the overall pattern and nature of the sequence. The formula must be followed carefully for each term to ensure precision.
Comprehending these terms enables the analysis of their distribution and behavior over time.
Geometric Progression
A geometric progression is a type of sequence where each term is found by multiplying the previous term by a specific non-zero constant. This constant is known as the common ratio.
In our example:
The formula: \[ a_n = a_1 r^{n-1} \]This allows for easy calculations for consecutive terms.
Using the first term \(a_1 = -2\) and the common ratio \(r = -2\), the nth term is given by:\[ a_n = -2 (-2)^{n-1} \]
This standard form simplifies predicting terms farther along the sequence. It demonstrates the layered multiplication effect of the common ratio. Geometric progression is powerful in various mathematical and real-life applications, showcasing repetitive, scaling patterns.
In our example:
- We confirmed that \, \(-2, 4, -8, 16, -32\) is a geometric sequence.
- The consistent multiplication by the common ratio of \(-2\) indicates this progression.
The formula: \[ a_n = a_1 r^{n-1} \]This allows for easy calculations for consecutive terms.
Using the first term \(a_1 = -2\) and the common ratio \(r = -2\), the nth term is given by:\[ a_n = -2 (-2)^{n-1} \]
This standard form simplifies predicting terms farther along the sequence. It demonstrates the layered multiplication effect of the common ratio. Geometric progression is powerful in various mathematical and real-life applications, showcasing repetitive, scaling patterns.
Other exercises in this chapter
Problem 25
Use a graphing calculator to do the following. (a) Find the first ten terms of the sequence. (b) Graph the first ten terms of the sequence. \(a_{n}=\frac{1}{a_{
View solution Problem 26
The first four terms of a sequence are given. Can these terms be the terms of an arithmetic sequence? If so, find the common difference. $$\frac{1}{2}, \frac{1}
View solution Problem 26
Interest Rate Janet's payments on her \(\$ 12,500\) car are \(\$ 420\) a month for 3 years. Assuming that interest is compounded monthly, what interest rate is
View solution Problem 26
A sequence is defined recursively by \(a_{n+1}=3 a_{n}-8\) and \(a_{1}=4 .\) Find an explicit formula for \(a_{n},\) and then use mathematical induction to prov
View solution