Problem 26
Question
Find the critical numbers of \(f\) (if any). Find the open intervals on which the function is increasing or decreasing and locate all relative extrema. Use a graphing utility to confirm your results. $$ f(x)=x^{4}-32 x+4 $$
Step-by-Step Solution
Verified Answer
The critical number of the function \(f(x) = x^{4} - 32x + 4\) is \(x = 2\). The function is decreasing on the interval \((-\infty, 2)\) and increasing on the interval \((2, \infty)\). The relative minimum is at \(x = 2\).
1Step 1: Find the derivative of the function
The derivative of \(f(x) = x^{4} - 32x + 4\) is \(f'(x) = 4x^{3} - 32\).
2Step 2: Find the critical numbers
Set the derivative equal to zero to find the critical numbers: \(4x^{3} - 32 = 0\). Solving for x, we get \(x = \sqrt[3]{8}\), which is about \(x = 2\). The critical numbers of f are the x values for which f'(x) = 0 and f''(x) exists, so the critical number is \(x = 2\).
3Step 3: Determine the intervals of increase and decrease
Plot the critical number on a number line and use test points to determine where \(f'\) is positive (indicating increase) or negative (indicating decrease). For \(x < 2 \), try \(x = 0\). \(f'(0) = -32 < 0\), so \(f\) is decreasing on \((-\infty, 2)\). For \(x > 2\), try \(x = 3\). \(f'(3) = 68 > 0\), so \(f\) is increasing on \((2, \infty)\).
4Step 4: Find the relative extrema
The relative extremum is where the function changes from increasing to decreasing or vice versa. Here, the function changes from decreasing to increasing at \(x = 2\). So, \(f\) has a relative minimum at \(x = 2\).
5Step 5: Confirm with a graphing utility
A graphing utility can be used to graph the function \(f(x) = x^{4} - 32x + 4\), and it clearly shows the relative minimum at \(x = 2\).
Key Concepts
Intervals of Increase and DecreaseRelative ExtremaGraphing Utilities
Intervals of Increase and Decrease
When working with a function, one of the main tasks is to identify where it is increasing or decreasing. This helps you understand how the function behaves over certain ranges. To find these intervals, we analyze the sign of the derivative of the function.
- First, find the derivative of the function, denoted as \( f'(x) \). In this case, the derivative is \( f'(x) = 4x^3 - 32 \).
- The critical numbers where the function may change behavior are found by setting the derivative to zero \( 4x^3 - 32 = 0 \). This gives us a critical number of \( x = 2 \).
- Use the critical number to divide the number line into intervals: \((-\infty, 2)\) and \((2, \infty)\).
- Select test points within each interval to substitute back into the derivative.
- If \( f'(x) \) is positive, the function is increasing in that interval.
- If \( f'(x) \) is negative, the function is decreasing in that interval.
Relative Extrema
Relative extrema are the points on the graph where the function has a relative minimum or maximum. These are places where the function changes direction from increasing to decreasing or decreasing to increasing.
- A relative minimum occurs where the function changes from decreasing to increasing. This corresponds to the trough of the graph.
- A relative maximum occurs where the function changes from increasing to decreasing, corresponding to the peak of the graph.
Graphing Utilities
A graphing utility is a tool that allows you to visualize the graph of a function, verifying your analytic results by providing a graphical perspective.
- Graphing utilities, like graphing calculators or computer software, can plot the function for you.
- These tools confirm the calculated critical points and intervals of increase and decrease by showing the actual behavior of the function graphically.
Other exercises in this chapter
Problem 26
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