Problem 26
Question
Find the absolute maximum and minimum values of each function on the given interval. Then graph the function. Identify the points on the graph where the absolute extrema occur, and include their coordinates. $$F(x)=-\frac{1}{x},-2 \leq x \leq-1$$
Step-by-Step Solution
Verified Answer
Maximum is 1 at \(x = -1\); Minimum is \(1/2\) at \(x = -2\).
1Step 1: Identify the function and interval
The given function is \( F(x) = -\frac{1}{x} \), and the interval is \([-2, -1]\). We need to find the absolute maximum and minimum values of this function on this interval.
2Step 2: Find critical points
To find the critical points, we first need to find the derivative of \( F(x) \). Calculate \( F'(x) \) by differentiating \( F(x) = -\frac{1}{x} \). The derivative is \( F'(x) = \frac{1}{x^2} \). Critical points occur where \( F'(x) = 0 \) or is undefined. \( F'(x) \) is never zero, but it is undefined at \( x = 0 \), which is not within our interval, so there are no critical points within \([-2, -1]\).
3Step 3: Evaluate function at endpoints
Since there are no critical points within the interval, evaluate \( F(x) \) at the endpoints \( x = -2 \) and \( x = -1 \). Calculate:- \( F(-2) = -\frac{1}{-2} = \frac{1}{2} \),- \( F(-1) = -\frac{1}{-1} = 1 \).
4Step 4: Determine absolute extrema
Compare the values obtained at the endpoints to find the absolute extrema:- The absolute maximum value is \( 1 \) at \( x = -1 \).- The absolute minimum value is \( \frac{1}{2} \) at \( x = -2 \).
5Step 5: Graph the function and identify extrema points
To graph the function, plot \( F(x) = -\frac{1}{x} \) over the interval \([-2, -1]\). Mark the points where the extrema occur:- Point \((-1, 1)\) for the maximum.- Point \((-2, \frac{1}{2})\) for the minimum.
Key Concepts
Absolute ExtremaCritical PointsDerivativeGraphing Functions
Absolute Extrema
Absolute extrema refer to the highest and lowest values that a function can reach on a specific interval. These are known as absolute maximum and absolute minimum. To find these values, we generally look at critical points and the function's endpoints within the interval. The absolute extrema are essential because they tell us which values the function cannot exceed or dip below within the given range.
- First, identify the function and interval.
- Then, locate the critical points, as these are potential candidates for absolute extrema.
- Finally, compare function values at critical points and endpoints to find the absolute max and min.
Critical Points
Critical points of a function are points where the derivative is either zero or undefined. At these points, a function might change direction, indicating potential extrema—either relative or absolute.
To find critical points, follow these steps:
To find critical points, follow these steps:
- Take the derivative of the function.
- Set the derivative equal to zero and solve for x.
- Identify where the derivative is undefined as these are also critical points.
Derivative
A derivative represents the rate at which a function is changing at any point on its graph. It is the slope of the tangent line at any point on the curve. Calculating the derivative is essential to understanding where critical points might occur because they often correspond to points of zero slope or undefined slope.
Here's how you calculate it:
Here's how you calculate it:
- For the function \( F(x) = -\frac{1}{x} \), apply differentiation rules to find the derivative.
- The derivative, \( F'(x) = \frac{1}{x^2} \), is positive as \( x^2 \) is always positive over real numbers.
- This derivative doesn’t equal zero within the interval but identified the point where it's undefined.
Graphing Functions
Graphing is a powerful tool in visualizing and understanding a function's behavior. It helps identify where a function may reach its maximum or minimum values. A graph can provide intuition beyond pure computation.
When graphing a function like \( F(x) = -\frac{1}{x} \), follow these steps:
When graphing a function like \( F(x) = -\frac{1}{x} \), follow these steps:
- Identify and plot key points such as endpoints, and extrema.
- Note the behavior approaching vertical and horizontal asymptotes.
- Understand that graphing over an interval means highlighting only the section of the function in that range.
Other exercises in this chapter
Problem 25
Use I'Hópital's rule to find the limits. $$\lim _{x \rightarrow(\pi / 2)}\left(x-\frac{\pi}{2}\right) \sec x$$
View solution Problem 25
Use the Intermediate Value Theorem from Section 2.5 to show that \(f(x)=x^{3}+2 x-4\) has a root between \(x=1\) and \(x=2\) Then find the root to five decimal
View solution Problem 26
Identify the coordinates of any local and absolute extreme points and inflection points. Graph the function. $$y=\frac{4}{3} x-\tan x, \quad \frac{-\pi}{2}
View solution Problem 26
Find the most general antiderivative or indefinite integral. You may need to try a solution and then adjust your guess. Check your answers by differentiation. $
View solution