Problem 26
Question
Find an equation for the hyperbola that has its center at the origin and satisfies the given conditions. Foci \(F(\pm 7,0), \quad\) conjugate axis of length 8
Step-by-Step Solution
Verified Answer
The hyperbola's equation is \(\frac{x^2}{33} - \frac{y^2}{16} = 1\).
1Step 1: Identify the Standard Form of Hyperbola
For a hyperbola centered at the origin with the foci on the x-axis, the standard form of the equation is \( \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \), where \(c\) is the distance from the center to each focus, \(a\) is half the length of the transverse axis, and \(b\) is half the length of the conjugate axis.
2Step 2: Determine Values for c and b
The foci are given as \((\pm 7, 0)\), meaning \(c = 7\). The length of the conjugate axis is 8, so \(b = \frac{8}{2} = 4\).
3Step 3: Use Relationship to Find a
For hyperbolas, the relationship between the axes and the foci is \(c^2 = a^2 + b^2\). Substitute \(c = 7\) and \(b = 4\) into the equation to find \(a\). Therefore, \(49 = a^2 + 16\).
4Step 4: Solve for a^2
Rearrange the equation found in Step 3 to find \(a^2\): \(a^2 = 49 - 16 = 33\).
5Step 5: Write the Hyperbola Equation
Using the values found: \(a^2 = 33\) and \(b^2 = 16\), substitute into the standard form \(\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1\) to get \(\frac{x^2}{33} - \frac{y^2}{16} = 1\).
Key Concepts
Standard Form of HyperbolaFoci of HyperbolaConjugate AxisTransverse Axis
Standard Form of Hyperbola
The concept of the standard form of a hyperbola is fundamental in understanding its equation. A hyperbola is a type of conic section, appearing as a pair of mirrored curves. When its center is at the origin, and the foci lie on the x-axis, the standard form is given by:
- \(\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1\)
Foci of Hyperbola
The foci of a hyperbola are central to its definition and serve as key points of reference. They are two fixed points further apart than any part of the actual hyperbola. In our problem, the foci are given as \((\pm 7, 0)\), which means:
- The foci lie along the x-axis.
- The distance, \(c\), from the center to each focus is 7.
Conjugate Axis
The conjugate axis of a hyperbola provides structural balance and perpendicularity to the transverse axis. This axis is distinct as it doesn't intercept the hyperbola but instead relates to its width. In the given exercise, the length of the conjugate axis is 8, which means:
- The full conjugate axis stretches 8 units long.
- The half-length \(b\) is therefore 4, as calculated by \(b = \frac{8}{2}\).
Transverse Axis
The transverse axis in a hyperbola is the main axis that passes through the foci. It is paramount to the hyperbola's equation and determines the direction and opening of the curves. For a horizontal hyperbola focused along the x-axis, as in this exercise:
- \(a\) is half the length of the transverse axis.
- \(a^2\) is calculated using the equation \(c^2 = a^2 + b^2\).
Other exercises in this chapter
Problem 26
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