Problem 26
Question
Find all solutions of the equation. $$3-\tan ^{2} \beta=0$$
Step-by-Step Solution
Verified Answer
The solutions are \( \beta = \frac{\pi}{3} + k\pi \) and \( \beta = -\frac{\pi}{3} + k\pi \).
1Step 1: Rearrange the Equation
Start with the provided equation: \[ 3 - \tan^2 \beta = 0 \]To isolate \( \tan^2 \beta \), rearrange the equation by adding \( \tan^2 \beta \) to both sides. This results in the equation:\[ \tan^2 \beta = 3 \]
2Step 2: Solve for \( \tan \beta \)
Take the square root of both sides of the equation to solve for \( \tan \beta \):\[ \tan \beta = \pm \sqrt{3} \]This indicates that \( \tan \beta \) can be either \( \sqrt{3} \) or \( -\sqrt{3} \).
3Step 3: Identify General Solutions for \( \tan \beta = \sqrt{3} \)
The tan function equals \( \sqrt{3} \) at specific angles within the unit circle. The primary angle is:\[ \beta = \frac{\pi}{3} + k\pi \]where \( k \) is any integer. This is because the tangent function has a period of \( \pi \).
4Step 4: Identify General Solutions for \( \tan \beta = -\sqrt{3} \)
The tan function equals \( -\sqrt{3} \) at specific angles:\[ \beta = -\frac{\pi}{3} + k\pi \]where \( k \) is any integer. The periodicity of \( \tan \) allows these angles.
Key Concepts
Tangent FunctionUnit CirclePeriodicity of Trigonometric Functions
Tangent Function
The tangent function has distinct characteristics among trigonometric functions due to its unique relationship with sine and cosine.
- The formula for tangent of an angle is given by \( \tan \theta = \frac{\sin \theta}{\cos \theta} \).
- It is undefined where the cosine function is zero, making it distinctive at angles like \( \frac{\pi}{2} \) and \( \frac{3\pi}{2} \).
Unit Circle
The unit circle is essential for understanding trigonometric equations like the one given. Visualizing the angles that satisfy \( \tan \beta = \sqrt{3} \) or \( \tan \beta = -\sqrt{3} \) becomes straightforward with the unit circle.
- The unit circle is a circle with radius 1, centered at the origin of the coordinate plane.
- Angles on the unit circle can be expressed in radians, which are critical in calculating trigonometric functions.
Periodicity of Trigonometric Functions
The periodicity of the tangent function is what allows us to generate an infinite number of solutions to trigonometric equations. Understanding periodicity is crucial in predicting the behavior of functions beyond their initial cycles.
- The period of the tangent function is \( \pi \), meaning it repeats every \( \pi \) radians.
- This repetition is evident in the general solutions of equations like \( 3 - \tan^2 \beta = 0 \).
Other exercises in this chapter
Problem 26
Verify the identity. \(\tan \theta+\cot \theta=2 \csc 2 \theta\)
View solution Problem 26
Exer. \(25-36:\) Verify the reduction formula. $$\sin \left(x+\frac{\pi}{2}\right)=\cos x$$
View solution Problem 27
Write the expression as an algebraic expression in \(x\) for \(x>0\). $$\sin \left(2 \sin ^{-1} x\right)$$
View solution Problem 27
Use sum-to-product formulas to find the solutions of the equation. $$\sin 5 t+\sin 3 t=0$$
View solution