Problem 26
Question
Find a formula for the general term, \(a_{n},\) of each sequence. $$\frac{4}{5}, \frac{4}{25}, \frac{4}{125}, \frac{4}{625}, \dots$$
Step-by-Step Solution
Verified Answer
The formula for the general term, \(a_{n}\), of the given sequence is:
\[a_{n} = \frac{4}{5} \cdot \left(\frac{1}{5}\right)^{n-1}\]
1Step 1: Determine if the sequence is geometric
Since all the terms are fractions and only the denominators change, we need to find out if the denominators have the same ratio. We can do this by diving each term by the term that comes before it.
\[\frac{\frac{4}{25}}{\frac{4}{5}} = \frac{4}{25} \cdot \frac{5}{4} = \frac{4 \cdot 5}{4 \cdot 25} = \frac{1}{5}\]
\[\frac{\frac{4}{125}}{\frac{4}{25}} = \frac{4}{125} \cdot \frac{25}{4} = \frac{4 \cdot 25}{4 \cdot 125} = \frac{1}{5}\]
Since the ratio of consecutive terms is constant, the sequence is indeed geometric.
2Step 2: Identify the first term and the common ratio
The first term of the sequence is given as \(a_{1}=\frac{4}{5}\), and we have determined that the common ratio, denoted by r, is \(\frac{1}{5}\).
3Step 3: Write the formula for the nth term of a geometric sequence
The general formula for the nth term of a geometric sequence is:
\[a_{n} = a_{1} \cdot r^{n-1}\]
4Step 4: Apply the known values to the formula
We have \(a_{1}=\frac{4}{5}\) and \(r=\frac{1}{5}\). Substitute these values into the formula:
\[a_{n} = \frac{4}{5} \cdot \left(\frac{1}{5}\right)^{n-1}\]
5Step 5: Simplify the formula (if possible)
In this case, the formula for the nth term, \(a_{n}\), of the sequence is already simplified.
So, the formula for the general term, \(a_{n}\), of the given sequence is:
\[a_{n} = \frac{4}{5} \cdot \left(\frac{1}{5}\right)^{n-1}\]
Key Concepts
nth term formulacommon ratiosequence problems
nth term formula
The nth term formula is a shortcut to find any term in a geometric sequence without listing all previous terms. It helps you jump straight to the term you need. In a geometric sequence, this formula looks like this:
- \( a_{n} = a_{1} \cdot r^{n-1} \)
- \( a_{n} \) is the term you're trying to find.
- \( a_{1} \) is the first term of the sequence.
- \( r \) is the common ratio, which we determine by dividing any term by the one before it.
common ratio
The common ratio is a key part of understanding geometric sequences. It helps distinguish geometric sequences from other sequence types. To find the common ratio, you take any term in the sequence and divide it by the previous term.For example, in the sequence \( \frac{4}{5}, \frac{4}{25}, \frac{4}{125}, \frac{4}{625} \), you pick any two consecutive terms:
- Divide the second term \( \frac{4}{25} \) by the first term \( \frac{4}{5} \), and you'll calculate \( \frac{1}{5} \).
- Do the same for \( \frac{4}{125} \) divided by \( \frac{4}{25} \), and you'll also get \( \frac{1}{5} \).
sequence problems
Sequence problems often involve figuring out patterns in a series of numbers and predicting future terms. They test your ability to recognize these patterns and use formulas to find specific terms efficiently, saving you from listing each term one by one.
In sequence problems, you'll often:
- Determine if a sequence is geometric or another type based on how terms change.
- Find the first term and common ratio if it's geometric.
- Use the nth term formula to find specific terms or predict further numbers in the sequence.
Other exercises in this chapter
Problem 26
Evaluate each binomial coefficient. $$\left(\begin{array}{l}3 \\\1\end{array}\right)$$
View solution Problem 26
Find the general term of each geometric sequence. $$-1,4,-16,64, \dots$$
View solution Problem 26
For each arithmetic sequence, find \(a_{n}\) and then use \(a_{n}\) to find the indicated term. $$13,19,25,31,37, \ldots ; a_{30}$$
View solution Problem 27
Evaluate each binomial coefficient. $$\left(\begin{array}{l}5 \\\0\end{array}\right)$$
View solution