Problem 26
Question
Factor each trinomial completely. $$5 a^{2}-7 a b-6 b^{2}$$
Step-by-Step Solution
Verified Answer
The trinomial factors to \((5a + 3b)(a - 2b)\).
1Step 1: Identify a, b, and c in the Quadratic Trinomial
The given trinomial is in the form \( ax^2 + bx + c \), where \( a = 5 \), \( b = -7 \), and \( c = -6 \). In terms of variable, it is \( 5a^2 - 7ab - 6b^2 \).
2Step 2: Multiply a and c
Multiply the coefficient of the squared term (5) with the constant term (-6), giving you \( 5 \times (-6) = -30 \).
3Step 3: Find Two Numbers that Multiply to ac and Add to b
We need to find two numbers that multiply to -30 and add to -7. These numbers are -10 and +3 because \( -10 \times 3 = -30 \) and \( -10 + 3 = -7 \).
4Step 4: Rewrite Middle Term Using the Two Numbers
Rewrite the trinomial by splitting the middle term using the two numbers found: \( 5a^2 - 10ab + 3ab - 6b^2 \).
5Step 5: Factor by Grouping
Group the terms: \( (5a^2 - 10ab) + (3ab - 6b^2) \).
6Step 6: Factor Out the Greatest Common Factor from Each Group
In the first group \( (5a^2 - 10ab) \), the greatest common factor is \( 5a \), so factor it out: \( 5a(a - 2b) \). In the second group \( (3ab - 6b^2) \), the greatest common factor is \( 3b \), so factor it out: \( 3b(a - 2b) \).
7Step 7: Combine the Factored Groups
Now that both groups have \( (a - 2b) \), factor this common term out: \((5a + 3b)(a - 2b)\). The completely factored form is \((5a + 3b)(a - 2b)\).
Key Concepts
Quadratic TrinomialGreatest Common FactorFactor by Grouping
Quadratic Trinomial
A quadratic trinomial is an algebraic expression consisting of three terms. It has the general form \( ax^2 + bx + c \), where:
- \( a \), \( b \), and \( c \) are constants, usually real numbers.
- \( x \) is the variable, and \( x^2 \) is its squared term.
Greatest Common Factor
The concept of the greatest common factor (GCF) involves finding the largest factor that is common within two or more numbers or expressions. For factoring purposes, it helps to simplify expressions by pulling out this common factor.
In our exercise, we focus on factoring out the GCF from different grouped terms. When examining the expressions \( (5a^2 - 10ab) \) and \( (3ab - 6b^2) \):
In our exercise, we focus on factoring out the GCF from different grouped terms. When examining the expressions \( (5a^2 - 10ab) \) and \( (3ab - 6b^2) \):
- For \( 5a^2 - 10ab \), the GCF is \( 5a \). By factoring this out, we get \( 5a(a - 2b) \).
- For \( 3ab - 6b^2 \), the GCF is \( 3b \). By factoring this out, we derive \( 3b(a - 2b) \).
Factor by Grouping
Factor by grouping is a strategy used in factoring polynomials, which means reorganizing terms to reveal common factors you can utilize. It’s particularly handy in factorizations of quadratic trinomials or when the polynomial has four terms.
In the step-by-step breakdown used for our initial trinomial example, we:
In the step-by-step breakdown used for our initial trinomial example, we:
- Rewrote and split terms to create two groups: \( (5a^2 - 10ab) \) and \( (3ab - 6b^2) \).
- Found and factored out the GCF from each group. The term \( a - 2b \) appeared in both factored groups.
Other exercises in this chapter
Problem 26
If possible, simplify each radical expression. Assume that all variables represent positive real numbers. $$\sqrt{45}$$
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Perform the indicated operations. Write your answers with only positive exponents. Assume that all variables represent positive real numbers. $$5^{-2} \cdot 5^{
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Find each product or quotient. $$\frac{3 m-15}{4 m-20} \cdot \frac{m^{2}-10 m+25}{12 m-60}$$
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Find each sum or difference. $$\left(6 m^{4}-3 m^{2}+m\right)-\left(2 m^{3}+5 m^{2}+4 m\right)+\left(m^{2}-m\right)$$
View solution