Problem 26
Question
Express the statement as an equation. Use the given information to find the constant of proportionality. \(H\) is jointly proportional to the squares of \(l\) and \(w .\) If \(l=2\) and \(w=\frac{1}{3},\) then \(H=36\).
Step-by-Step Solution
Verified Answer
The constant of proportionality is 81.
1Step 1: Understand Joint Proportionality
When a quantity is jointly proportional to two or more other quantities, it means the quantity is proportional to the product of those quantities. Here, the statement 'H is jointly proportional to the squares of l and w' means that \( H = k \times l^2 \times w^2 \) where \( k \) is the constant of proportionality.
2Step 2: Formulate the Equation
Using the relationship from step 1, express the relationship as an equation: \( H = k \cdot l^2 \cdot w^2 \). This shows that \( H \) depends on the square of \( l \) and the square of \( w \) with some constant \( k \).
3Step 3: Substitute Given Values
Substitute \( H = 36 \), \( l = 2 \), and \( w = \frac{1}{3} \) into the equation: \( 36 = k \cdot 2^2 \cdot \left( \frac{1}{3} \right)^2 \).
4Step 4: Simplify the Squares
Calculate the squares: \( 2^2 = 4 \) and \( \left( \frac{1}{3} \right)^2 = \frac{1}{9} \). Substitute back into the equation to get \( 36 = k \cdot 4 \cdot \frac{1}{9} \).
5Step 5: Calculate the Constant of Proportionality
Simplify the right side of the equation: \( 4 \cdot \frac{1}{9} = \frac{4}{9} \). Thus, our equation becomes \( 36 = k \cdot \frac{4}{9} \). To solve for \( k \), multiply both sides by \( \frac{9}{4} \): \( k = 36 \cdot \frac{9}{4} \).
6Step 6: Final Calculation
Perform the multiplication: \( 36 \cdot \frac{9}{4} = 81 \). Thus, the constant of proportionality \( k = 81 \).
Key Concepts
Constant of ProportionalityMathematical ExpressionsProportional Relationships
Constant of Proportionality
When working with proportional relationships, a crucial element is the constant of proportionality. This constant, often represented by the letter \( k \), helps define the exact relationship between variables that are deemed to be proportional. In simpler terms, it's the number you multiply by one variable to get the other.For example, if \( y \) is directly proportional to \( x \), the equation would look like this: \( y = kx \). In joint proportionality, as seen in the exercise, the quantity is proportional to the product of multiple variables, such as \( H = k \times l^2 \times w^2 \). Here, \( k \) isn't just some random number—it's the bridge between the variables.Finding this constant involves substituting given values into the equation and simplifying to solve for \( k \). Remember, \( k \) remains constant no matter the specific values of the variables, unless the relationship itself changes.
Mathematical Expressions
Mathematical expressions are like the language of math. They convey relationships using numbers, variables, and mathematical symbols. For the concept of joint proportionality, expressions are used to succinctly describe how one quantity depends on others.In our exercise, the expression says \( H = k \cdot l^2 \cdot w^2 \). This equation packs a lot of information:
- \( H \) is the quantity that depends on other variables.
- \( k \) is the constant that scales the relationship.
- \( l^2 \) and \( w^2 \) indicate that \( H \) is dependent on the square of \( l \) and \( w \).
Proportional Relationships
Proportional relationships describe how quantities increase or decrease together. When one variable changes, another variable changes in response at a constant rate, defined by the constant of proportionality.Let's consider simple direct proportionality: if doubling \( x \) doubles \( y \), they're proportionally related by some constant \( k \). Joint proportionality adds a twist; it involves more than one variable influencing the outcome simultaneously.The exercise dealt with joint proportionality where \( H \) depends on the squares of \( l \) and \( w \). This means:
- As \( l \) or \( w \) increase, \( H \) changes by the square of these increments.
- The relationship doesn’t just have \( l \) added to \( w \); it multiplies the effect each variable has due to their contributions being squared.
Other exercises in this chapter
Problem 26
Multiply the algebraic expressions using the FOIL method and simplify. $$(7 y-3)(2 y-1)$$
View solution Problem 26
Perform the multiplication or division and simplify. $$\frac{x^{2}+2 x-3}{x^{2}-2 x-3} \cdot \frac{3-x}{3+x}$$
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Solve the linear inequality. Express the solution using interval notation and graph the solution set. $$2(7 x-3) \leq 12 x+16$$
View solution Problem 26
Find an equation of the line that satisfies the given conditions. Slope \(\frac{2}{5} ; \quad y\) -intercept 4
View solution