Problem 26
Question
Explain why the radii of Period 5 and Period 6 transition elements are nearly the same.
Step-by-Step Solution
Verified Answer
Lanthanide contraction causes Period 6 radii to be similar to those in Period 5.
1Step 1: Explain Transition Metals in Periods
Transition metals in Period 5 and Period 6 are in the d-block of the periodic table. These metals have electrons filling their d orbitals, and it is essential to observe the electron configurations and atomic sizes.
2Step 2: Review Lanthanide Contraction
Period 6 elements are more massive than Period 5 elements due to extra electron shells. However, for transition metals, they experience lanthanide contraction. The lanthanide contraction is the result of poor shielding of nuclear charge by 4f electrons, causing electrons to feel more attraction from the nucleus.
3Step 3: Identify Consequence on Atomic Radius
Despite having an extra shell, the lanthanide contraction in Period 6 reduces the effective atomic size. This effect helps Period 6 transition metals maintain similar atomic radii to those of Period 5 metals.
4Step 4: Connect Back to Radii of Transition Elements
The key reason Period 5 and Period 6 transition elements have nearly the same radii is the balancing act between additional electron shells and the substantial impact of lanthanide contraction.
Key Concepts
Periodic TableLanthanide ContractionAtomic Radius
Periodic Table
The periodic table is a chart organizing chemical elements by their atomic number, electronegativity, and electron configuration. The elements are listed in order of increasing atomic number, which refers to the number of protons in an atom's nucleus.
Transition metals, found in the d-block of the periodic table, have unique properties, including the filling of their d orbitals. These elements typically span from groups 3 to 12 and are known for their ability to form diverse oxidation states.
Transition metals, found in the d-block of the periodic table, have unique properties, including the filling of their d orbitals. These elements typically span from groups 3 to 12 and are known for their ability to form diverse oxidation states.
- **Period 5:** This period consists of elements that follow krypton (Kr) and precede xenon (Xe).
- **Period 6:** This includes elements immediately following xenon, represented by heavier elements starting with cesium (Cs).
Lanthanide Contraction
Lanthanide contraction is a phenomenon that affects the periodic trends seen in elements. It refers to the decrease in size of lanthanide series elements despite increasing atomic numbers. This contraction is significant for understanding transition metals, especially those in Periods 5 and 6.
The effect happens due to the poor shielding effect of the 4f electrons. In simple terms, the 4f subshell electrons do not block the increased nuclear charge effectively.
The effect happens due to the poor shielding effect of the 4f electrons. In simple terms, the 4f subshell electrons do not block the increased nuclear charge effectively.
- As a result, electrons in the outer shells feel a stronger pull from the nucleus, resulting in a smaller atomic radius.
- This stronger nuclear attraction compacts the atom despite additional electrons, which would typically increase size.
Atomic Radius
Understanding atomic radius involves the measurements of the size of an atom. The atomic radius can be influenced by several factors including electron shielding, nuclear charge, and electron shell addition.
For transition metals, especially those in consecutive periods like Periods 5 and 6, careful consideration of these factors is essential:
For transition metals, especially those in consecutive periods like Periods 5 and 6, careful consideration of these factors is essential:
- **Electron Shells:** More electron shells generally imply a larger atomic radius.
- **Nuclear Charge:** A stronger nuclear charge can pull electrons closer, reducing the atomic size.
- **Shielding Effect:** Ineffective shielding by inner electrons, as seen with the 4f orbital, leads to a higher effective nuclear charge experienced by outer electrons.
Other exercises in this chapter
Problem 24
Determine the oxidation state of iron in \(\mathrm{KFe}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]\). Explain your answer.
View solution Problem 25
Explain why the atomic radii of transition metals vary less across a period than do main-group elements.
View solution Problem 27
Predict which element in the pair has the larger atomic radius. (a) Cu or Ag (b) \(\mathrm{T} \mathrm{i}\) or \(\mathrm{Cr}\) (c) W or \(\mathrm{Hg}\)
View solution Problem 28
Predict which element in the pair has the smaller atomic radius. (a) \(\mathrm{Pt}\) or \(\mathrm{Ni}\) (b) Ti or \(\mathrm{Ni}\) (c) \(Z r\) or \(\mathrm{Rh}\)
View solution