Problem 26
Question
Evaluate each expression. $$ \frac{_{10} C_{3}}{_6 C_{4}}-\frac{46 !}{44 !} $$
Step-by-Step Solution
Verified Answer
-2069.9984
1Step 1: Calculate the Combinations
First, calculate the combinations separately using the formula \(\frac{n!}{r!(n-r)!}\). The first combination \(_{10}C_{3}=\frac{10!}{3!(10-3)!}=\frac{720}{6*5040}=0.024\). The second combination \(_6C_{4}=\frac{6!}{4!(6-4)!}=\frac{720}{24*2}=15\).
2Step 2: Evaluate the Combination Expression
Next, compute the expression \(\frac{_{10}C_{3}}{_{6}C_{4}}= \frac{0.024}{15}=0.0016\)
3Step 3: Calculate the Factorials
Then, calculate \(46!\) and \(44!\). Remember that \(46!=46*45*44!\). Hence, \(46!/44!=(46*45)=2070\).
4Step 4: Evaluate the Whole Expression
Finally, subtract the result of the factorial from that of the combination expression: \(0.0016-2070=-2069.9984\).
Key Concepts
CombinationsFactorialsEvaluate ExpressionsAlgebraic Expressions
Combinations
Combinations are a fundamental part of combinatorics and are useful when you want to count how many different groups can be formed from a larger set. In mathematics, combinations refer to selecting items from a group, where the order of selection does not matter. To calculate combinations, we use the combination formula: \[ _{n}C_{r} = \frac{n!}{r!(n-r)!} \] Here, \(n\) is the total number of items, and \(r\) represents the number of items to choose. The symbol \(_{n}C_{r}\) denotes the number of combinations.
- For the expression \(_{10}C_{3}\), it means selecting 3 items from 10.
- This uses the formula \(\frac{10!}{3!(10-3)!}\).
Factorials
Factorials are an essential concept when working with combinations or permutations. A factorial, denoted by \(n!\), is the product of all positive integers less than or equal to \(n\). For example, \(5! = 5 \times 4 \times 3 \times 2 \times 1 = 120\). In the context of our exercise, factorials help compute combinations, as seen in the expression: \[_{6}C_{4} = \frac{6!}{4!(6-4)!}\] Not only are factorials useful in combinatorics, but they also appear in various branches of mathematics, such as calculus and algebra. Another critical moment when we used factorials was simplifying \(\frac{46!}{44!}\).
- Here, notice that \(46!\) is broken down as \(46 \times 45 \times 44!\).
- Since \(44!\) is in both numerator and denominator, it cancels out, simplifying the expression to \(46 \times 45\).
Evaluate Expressions
Evaluating expressions is a process that refers to calculating the value of an algebraic expression by using the rules and operations of mathematics. It's like solving a puzzle by following a series of logical steps. In the given problem, we start with evaluating individual parts, such as combinations and factorials, and then combine these results.
- First, we compute \(_{10}C_{3}\) and \(_{6}C_{4}\) separately.
- Next, we evaluate the combination expression \(\frac{_{10}C_{3}}{_{6}C_{4}}\).
- Then, solve the factorial expression \(\frac{46!}{44!}\).
Algebraic Expressions
Algebraic expressions are mathematical phrases that can include numbers, variables, and operations. They form the building blocks of more complex equations and play a significant role in various mathematical computations. In our example, the exercise combines several algebraic concepts:
- Expressions like \(\frac{_{10}C_{3}}{_{6}C_{4}}\) involve combinations which are a core part of algebra.
- Factorial expressions \(\frac{46!}{44!}\) further illustrate how multiplication operates in an algebraic context.
Other exercises in this chapter
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