Problem 26
Question
evaluate each algebraic expression for \(x=2\) and \(y=-5\) $$ |x-y| $$
Step-by-Step Solution
Verified Answer
The evaluated expression for \( |x-y| \) with given values \( x=2 \) and \( y=-5 \) is 7.
1Step 1: Substitute the values of x and y into the expression
The first step is to substitute the provided values for x and y into the expression \(|x-y|\). So the expression becomes \(|2 - (-5)|\).
2Step 2: Simplify the expression inside the absolute value
The next step involves simplifying the expression inside the absolute value sign. The expression inside the absolute value sign is \(2-(-5)\), which simplifies to \(2+5 = 7\). So our expression now becomes \(|7|\).
3Step 3: Evaluate the absolute value
Now, the absolute value of 7 needs to be evaluated. The absolute value of a number is the non-negative value of that number, regardless of its sign. So, the absolute value of 7 is just 7.
Key Concepts
Absolute ValueSubstitution MethodSimplification of Expressions
Absolute Value
The concept of absolute value is quite straightforward once you get the hang of it. Simply put, the absolute value of any number is its distance from zero on the number line. It is always a non-negative number, which means you drop any negative sign that might be in front of the number.
For instance:
For instance:
- The absolute value of 5 is 5, written as \(|5| = 5\).
- Similarly, the absolute value of -5 is also 5, written as \(|-5| = 5\).
Substitution Method
Substitution is a vital method in algebra. It allows us to solve expressions or equations by 'plugging in' values for the variables given in any problem. This method is especially helpful because it simplifies the process of working with variable-heavy equations.
In the original exercise, you were asked to evaluate \(|x-y|\) when \(x=2\) and \(y=-5\). By substituting, we replace each instance of 'x' with 2 and 'y' with -5, making complex algebraic expressions far more manageable.
For example:
In the original exercise, you were asked to evaluate \(|x-y|\) when \(x=2\) and \(y=-5\). By substituting, we replace each instance of 'x' with 2 and 'y' with -5, making complex algebraic expressions far more manageable.
For example:
- Start with the expression \(|x-y|\).
- Substitute the variables: \(|2-(-5)|\).
- Then, simplify further to get a clearer numerical expression.
Simplification of Expressions
Simplification in algebra involves breaking down complex expressions into simpler or more manageable forms. This is a necessary skill as it is used in almost every mathematical problem-solving process.
In our solution, simplification involved a critical step. After substituting for variables, we dealt with the expression \(2-(-5)\).
Here’s how simplification works:
In our solution, simplification involved a critical step. After substituting for variables, we dealt with the expression \(2-(-5)\).
Here’s how simplification works:
- Recognize that subtracting a negative is equivalent to addition. Thus \(2-(-5)\) becomes \(2+5\).
- Compute this addition: \(2+5=7\).
- Finally, our simplified expression under the absolute value was \(|7|\).
Other exercises in this chapter
Problem 25
Use the quotient rule to simplify the expressions in Exercises \(17-26 .\) Assume that \(x>0\) $$\frac{\sqrt{200 x^{3}}}{\sqrt{10 x^{-1}}}$$
View solution Problem 26
Simplify each exponential expression $$ x^{7} y^{0} $$
View solution Problem 26
Find each product. $$(2 x-3)(5 x+3)$$
View solution Problem 26
Multiply or divide as indicated. $$ \frac{x^{2}-4}{x-2} \div \frac{x+2}{4 x-8} $$
View solution