Problem 26
Question
Divide. $$\frac{m^{2}-6 m-27}{m+3}$$
Step-by-Step Solution
Verified Answer
The simplified expression after dividing \(\frac{m^2-6m-27}{m+3}\) is \(m - 9\).
1Step 1: Identify the quadratic equation in the numerator
The numerator is a quadratic equation: \(m^2 - 6m - 27\).
2Step 2: Factor the quadratic equation
We will try to find two binomials whose product is equal to the quadratic equation. We need two numbers whose product is -27 and whose sum is -6. Those numbers are -9 and +3. So, the quadratic equation can be factored as \((m - 9)(m + 3)\).
Now the expression is:
\(\frac{(m - 9)(m + 3)}{m + 3}\)
Step 2: Simplify the expression
3Step 3: Cancel the common binomial
As both numerator and denominator have a common binomial (m + 3), we can cancel it out.
\(\frac{(m - 9)(m + 3)}{m + 3}\) can be simplified to \(m - 9\), as the (m + 3) cancels out.
The final simplified expression is:
\(m - 9\)
Key Concepts
Factoring QuadraticsSimplifying ExpressionsCommon Binomials
Factoring Quadratics
Quadratic equations are expressions that can be written in the form \( ax^2 + bx + c \), where \( a \), \( b \), and \( c \) are constants. Factoring quadratics involves rewriting the equation as a product of two binomials. The challenge is to find two numbers that multiply to \( ac \) (the product of \( a \) and \( c \)) and add up to \( b \).In the case of the quadratic equation \( m^2 - 6m - 27 \), we need numbers that multiply to -27 and add up to -6. Here, -9 and +3 satisfy these conditions. Therefore, the quadratic equation can be factored as \( (m - 9)(m + 3) \).Factorizing quadratics makes them easier to work with, especially in operations like division or solving equations. This process helps break down complex expressions into simpler, manageable parts.
Simplifying Expressions
Simplifying expressions is all about reducing them to their most straightforward form. This often involves factoring, canceling out terms, and performing basic arithmetic operations.After factoring the quadratic \( m^2 - 6m - 27 \) into \( (m - 9)(m + 3) \), we simplify by cancelling the common binomial \( (m + 3) \) that appears in both the numerator and the denominator. Hence, \( \frac{(m - 9)(m + 3)}{m + 3} \) simplifies to \( m - 9 \).Simplification not only makes expressions easier to understand but also reveals the core elements of a problem or function. It removes redundancies and highlights the essential parts of the expression.
Common Binomials
Common binomials are terms that appear in both the numerator and the denominator of a fraction. Identifying and canceling them is an essential part of simplifying expressions.In this exercise, the term \( (m + 3) \) is a common binomial present in both the numerator and the denominator after factoring the quadratic expression. By canceling out \( (m + 3) \) in \( \frac{(m - 9)(m + 3)}{m + 3} \), we simplify the expression to \( m - 9 \).The process of canceling common binomials relies on the fundamental fact that any non-zero number divided by itself is 1. Recognizing common binomials can greatly simplify the process of working with algebraic fractions, making it easier to identify the solution.
Other exercises in this chapter
Problem 25
Simplify. Assume all variables represent nonzero real numbers. The answer should not contain negative exponents. $$\frac{f^{11}}{f^{7}}$$
View solution Problem 26
Perform the indicated operations and simplify. $$ \begin{array}{l} 3\left(x^{2} y^{2}+x y-2\right)-5\left(x^{2} y^{2}+6 x y-2\right) \\ +2\left(x^{2} y^{2}+6 x
View solution Problem 26
Evaluate each polynomial when \(x=-4\) and \(y=3\) $$\frac{1}{2} x y+x+3 y$$
View solution Problem 26
Simplify. Assume all variables represent nonzero real numbers. The answer should not contain negative exponents. $$\frac{u^{9}}{u^{8}}$$
View solution