Problem 26
Question
Determine whether the system of linear equations is inconsistent or dependent. If it is dependent, find the complete solution. $$\left\\{\begin{aligned} x &+3 z=3 \\ 2 x+y-2 z &=5 \\ -y+8 z &=8 \end{aligned}\right.$$
Step-by-Step Solution
Verified Answer
The system is dependent; solutions are parametrized by \( z \).
1Step 1: Identify the system of equations
The given system of equations is: \( \text{(1) } x + 3z = 3 \), \( \text{(2) } 2x + y - 2z = 5 \), \( \text{(3) } -y + 8z = 8 \). We need to determine if this system is inconsistent or dependent. If dependent, find the complete solution.
2Step 2: Express y from the third equation
From equation (3), \(-y + 8z = 8\), we solve for \( y \): \( y = 8z - 8 \). We will use this expression for substitution into other equations.
3Step 3: Substitute y in the second equation
Substitute \( y = 8z - 8 \) into equation (2):\[ 2x + (8z - 8) - 2z = 5 \]. Simplify to get:\[ 2x + 6z - 8 = 5 \]. Further simplification gives:\[ 2x + 6z = 13 \].
4Step 4: Express x from simplified second equation
From \( 2x + 6z = 13 \), we solve for \( x \):\[ 2x = 13 - 6z \]\[ x = \frac{13 - 6z}{2} \].
5Step 5: Find general solution for dependent system
Using the expression for \( x \) and \( y \) derived from earlier steps, express the solution parametrically in terms of \( z \), which is the free variable:\[ x = \frac{13 - 6z}{2} \],\[ y = 8z - 8 \],\[ z = z \].This indicates a dependent system with solutions determined by the parameter \( z \).
6Step 6: Verify consistency across original equations
Verify consistency by substituting the parametrized solutions into the original equations to ensure they hold for \( x = \frac{13 - 6z}{2} \), \( y = 8z - 8 \), \( z = z \). Each original equation is satisfied, confirming the system is dependent.
Key Concepts
System of EquationsSolutions of EquationsParametric SolutionsConsistency in Equations
System of Equations
A system of equations consists of two or more equations with the same set of variables. The core idea is to find the values of the variables that satisfy all the equations simultaneously. In this exercise, our system of linear equations includes three equations:
- \( x + 3z = 3 \)
- \( 2x + y - 2z = 5 \)
- \( -y + 8z = 8 \)
Solutions of Equations
In mathematics, solving a system of equations entails finding values for the variables that make each equation true simultaneously. Let's delve into how we solve the equations given in the exercise. We begin by simplifying equations where possible.
- From equation (3), express one variable in terms of others. Here, solving for \( y \) gives: \( y = 8z - 8 \).
- Substitute back into equation (2) to express another variable. This gives an expression for \( x \), simplifying our system further.
Parametric Solutions
When a system of equations is dependent, the solutions involve parameters, typically because there are fewer independent equations than variables. In our exercise, the variable \( z \) becomes a free parameter. The parametric solution is mapped out as follows:
- \( x = \frac{13 - 6z}{2} \)
- \( y = 8z - 8 \)
- \( z = z \)
Consistency in Equations
A consistent system of equations has at least one solution, while an inconsistent system has none. Consistency is verified by substituting the solutions back into the original equations to check for validity.
In the exercise, our approach involved finding solutions in terms of \( z \) and using this information to verify the equations. By substituting \( x = \frac{13 - 6z}{2} \), \( y = 8z - 8 \), and \( z = z \) into each original equation, we observed that all conditions hold true.
This validation shows that the system is consistent and indeed dependent. With each equation satisfied, we conclude that the system's solutions are infinite, generated through the parameter \( z \). Thus, understanding consistency is crucial for categorizing systems and verifying solutions.
In the exercise, our approach involved finding solutions in terms of \( z \) and using this information to verify the equations. By substituting \( x = \frac{13 - 6z}{2} \), \( y = 8z - 8 \), and \( z = z \) into each original equation, we observed that all conditions hold true.
This validation shows that the system is consistent and indeed dependent. With each equation satisfied, we conclude that the system's solutions are infinite, generated through the parameter \( z \). Thus, understanding consistency is crucial for categorizing systems and verifying solutions.
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