Problem 26
Question
Determine the type of conic section represented by each equation, and graph it, provided a graph exists. $$\frac{x^{2}}{4}+\frac{y^{2}}{4}=1$$
Step-by-Step Solution
Verified Answer
The equation represents a circle centered at the origin with a radius of 2.
1Step 1: Recognize the Equation Format
The given equation is \(\frac{x^{2}}{4} + \frac{y^{2}}{4} = 1\). Noticing that both \(x\) and \(y\) terms are squared and are added with each other indicates that this is a conic section equation. Specifically, a circle or an ellipse in the form \(\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1\). Since the denominators are equal, this is specifically an equation of a circle.
2Step 2: Identify the Type of Conic
Since the coefficients are both 1 and equal (as seen from \(\frac{1}{4}\) under both variables after dividing), this confirms that the equation represents a circle. A circle's equation in standard form is \(x^2 + y^2 = r^2\).
3Step 3: Determine Radius and Graph
For a circle, \(x^2/a^2 + y^2/b^2 = 1\) becomes \(x^2/4 + y^2/4 = 1\), which simplifies to \(x^2 + y^2 = 4\). The equation \(x^2 + y^2 = r^2\) where \(r^2 = 4\) indicates that \(r = \sqrt{4} = 2\). This means the radius of the circle is 2. The circle is centered at the origin (0,0) with a radius of 2.
4Step 4: Graph the Circle
Plot the circle on a coordinate plane with the center at the origin (0,0). Use a compass or your plotting tool to make sure the circle's radius is 2. Mark points at (2,0), (-2,0), (0,2), and (0,-2) to help guide the shape.
Key Concepts
CircleGraphingEquation Format
Circle
The concept of a circle is fundamental in understanding the types of conic sections. A circle is a set of points equidistant from a fixed point known as the center. The distance from the center to any point on the circle is the radius. In coordinate geometry, a circle's standard equation centered at the origin
- is written as: \( x^2 + y^2 = r^2 \).
Graphing
Graphing circles is an essential skill to visualize their properties and position on a coordinate plane. To graph a circle, one must first identify the center and the radius from the equation. In the exercise, the equation simplifies to \( x^2 + y^2 = 4 \). This tells us:
- The circle is centered at (0,0), the origin.
- The radius \((r)\) is 2, calculated from \( r = \sqrt{4} \).
- start plotting the center point at the origin.
- Measure the radius in all four directions (up, down, left, right) from the center.
- these radius points are (2,0), (-2,0), (0,2), and (0,-2).
- Using these reference points helps outline the complete circle when connected smoothly.
Equation Format
The equation format gives critical insights to determine the type of conic section represented. For circles and ellipses, the general form is \( \frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1 \).
- If \( a^2 = b^2 \), then the conic section is a circle.
Other exercises in this chapter
Problem 26
Find a rectangular equation. State the appropriate interval for \(x\) or \(y .\) $$x=t+3, y=2 t, \text { for } t \text { in }(-\infty, \infty)$$
View solution Problem 26
Find an equation for each ellipse. \(x\) -intercepts \((\pm 3 \sqrt{2}, 0) ;\) foci \((\pm 2 \sqrt{3}, 0)\)
View solution Problem 26
We can find an equation of a circle if we know the coordinates of the endpoints of a diameter of the circle. First, find the midpoint of the diameter, which is
View solution Problem 27
Find a rectangular equation. State the appropriate interval for \(x\) or \(y .\) $$x=3 t^{2}, y=t+1, \text { for } t \text { in }(-\infty, \infty)$$
View solution