Problem 26
Question
Determine the common difference, the fifth term, the \(n\) th term, and the 100 th term of the arithmetic sequence. $$11,8,5,2, \dots$$
Step-by-Step Solution
Verified Answer
The common difference is -3. The fifth term is -1. The nth term is \(14 - 3n\). The 100th term is -286.
1Step 1: Identify the Common Difference
An arithmetic sequence has a constant difference between consecutive terms. To find it, subtract the first term from the second term: \(8 - 11 = -3\). Therefore, the common difference, \(d\), is \(-3\).
2Step 2: Calculate the Fifth Term
The general formula for the \(n\)th term in an arithmetic sequence is \(a_n = a_1 + (n-1)d\). We need to find \(a_5\), the fifth term. Substitute \(a_1 = 11\), \(d = -3\), and \(n = 5\): \[a_5 = 11 + (5-1)(-3) = 11 - 12 = -1\]. Thus, the fifth term is \(-1\).
3Step 3: Determine the General Formula for the nth Term
Use the formula for the \(n\)th term, \(a_n = a_1 + (n-1)d\). Substitute \(a_1 = 11\) and \(d = -3\): \[a_n = 11 + (n-1)(-3) = 11 - 3(n-1)\] This simplifies to: \[a_n = 11 - 3n + 3 = 14 - 3n\]. This is the formula for the \(n\)th term.
4Step 4: Calculate the 100th Term
Using the nth term formula \(a_n = 14 - 3n\), substitute \(n = 100\) to find the 100th term: \[a_{100} = 14 - 3(100) = 14 - 300 = -286\]. Thus, the 100th term is \(-286\).
Key Concepts
Understanding the Common DifferenceExploring the nth Term FormulaPerforming Sequence CalculationsUnderstanding Arithmetic Progression
Understanding the Common Difference
In an arithmetic sequence, the common difference is the distinguishing factor. It's the fixed amount that we add or subtract to the previous term to get the next term in the sequence. This difference is what marks an arithmetic sequence apart from other types of sequences.
To calculate the common difference, we simply subtract the second term from the first term, or any consecutive pair of terms.
To calculate the common difference, we simply subtract the second term from the first term, or any consecutive pair of terms.
- For example, if we have the sequence: 11, 8, 5, 2, ..., the common difference ( d) can be calculated as:\[d = 8 - 11 = -3\]
Exploring the nth Term Formula
The nth term formula allows us to find any term in an arithmetic sequence without listing all the terms. This saves time and effort, especially for larger sequences.
The formula for the nth term ( a_n) is:
The formula for the nth term ( a_n) is:
- \[a_n = a_1 + (n-1)d\]
- a_n is the nth term,
- a_1 is the first term of the sequence,
- n is the term number,
- d is the common difference.
- \[a_n = 11 + (n-1)(-3) = 14 - 3n\]
Performing Sequence Calculations
To perform sequence calculations, first know the common difference and the formula for the nth term. This knowledge allows us to tackle various problems related to arithmetic sequences.
For example, calculating specific terms, like the fifth term, simply involves:
For example, calculating specific terms, like the fifth term, simply involves:
- Substituting the term number into the nth term formula.
- Let's find the fifth term: For n = 5, use the nth term formula:\[a_5 = 14 - 3 imes 5 = 14 - 15 = -1\]
Understanding Arithmetic Progression
Arithmetic progression (AP) involves a sequence of numbers in which each term after the first is derived by adding a constant known as the common difference. This is a straightforward yet powerful mathematical concept.
An AP doesn't change as you move along the sequence; the pattern remains steady:
An AP doesn't change as you move along the sequence; the pattern remains steady:
- The initial term ( a_1) starts the sequence.
- The common difference ( d) drives the progression.
- Every subsequent term can be easily found using the nth term formula:\[a_n = a_1 + (n-1)d\]
Other exercises in this chapter
Problem 25
Determine the common ratio, the fifth term, and the \(n\) th term of the geometric sequence. $$0.3,-0.09,0.027,-0.0081, \ldots$$
View solution Problem 25
Find the \(n\) th term of a sequence whose first several terms are given. $$1,4,7,10, \dots$$
View solution Problem 26
Find the first four terms in the expansion of \(\left(x^{1 / 2}+1\right)^{30}\)
View solution Problem 26
Show that \(x+y\) is a factor of \(x^{2 n-1}+y^{2 n-1}\) for all natural numbers \(n\)
View solution