Problem 26
Question
Describe the relationship between the graphs of \(f\) and \(g .\) Consider amplitudes, periods, and shifts. $$\begin{aligned} &f(x)=\cos 4 x\\\ &g(x)=-2+\cos 4 x \end{aligned}$$
Step-by-Step Solution
Verified Answer
Both \(f(x)\) and \(g(x)\) have the same amplitude of 1 and the same period of \(\frac{2\pi}{4}\). However, \(g(x)\) is \(f(x)\) shifted downward by 2 units.
1Step 1: Identify the Period and Amplitude of Each Function
The period of both functions is the same, it's \(\frac{2\pi}{4}\), because the coefficient of \(x\) in the cosine function determines the period. The amplitude of \(f(x)\) is 1 (the absolute value of the coefficient in front of the cosine), and the amplitude of \(g(x)\) is also 1.
2Step 2: Identify the Shifts
Function \(f(x)\) has no shift because there are no numbers added or subtracted directly to the cosine function. However, function \(g(x)\) is shifted down by 2 units, evidenced by the -2 added to the cosine function.
3Step 3: Describing the Relationship
The amplitude of both functions is the same (i.e., 1), and they have the same period. However, \(g(x)\) is \(f(x)\) shifted down by 2 units.
Key Concepts
Amplitude of Trigonometric FunctionsPeriod of Trigonometric FunctionsVertical Shifts in Trigonometric Graphs
Amplitude of Trigonometric Functions
Imagine a calm sea with waves gently rising and falling. The amplitude in trigonometry is like the height of those waves. It measures how far the peaks and troughs of a trigonometric graph are from the central line, or the 'equilibrium'.
Specifically, for the function
\( f(x) = \text{cos} (ax) \), where \( a \) is a real number, the amplitude is the absolute value of the coefficient in front of the cosine function. In the case of our exercise's function
\( f(x) = \text{cos} (4x) \), the coefficient is 1, indicating an amplitude of 1. This means the graph oscillates 1 unit above and below the line \( y = 0 \).
No matter how the graph stretches or shrinks horizontally (which we'll discuss with the period), the amplitude remains constant, unless there's a vertical stretch factor—a coefficient placed directly in front of the trigonometric function that would amplify the 'wave heights', so to speak.
Specifically, for the function
\( f(x) = \text{cos} (ax) \), where \( a \) is a real number, the amplitude is the absolute value of the coefficient in front of the cosine function. In the case of our exercise's function
\( f(x) = \text{cos} (4x) \), the coefficient is 1, indicating an amplitude of 1. This means the graph oscillates 1 unit above and below the line \( y = 0 \).
No matter how the graph stretches or shrinks horizontally (which we'll discuss with the period), the amplitude remains constant, unless there's a vertical stretch factor—a coefficient placed directly in front of the trigonometric function that would amplify the 'wave heights', so to speak.
Period of Trigonometric Functions
The period of a trigonometric function is akin to the length of one complete cycle of its graph. Take a round trip on a Ferris wheel as an analogy—starting from one point and coming back around to it is one period. For cosine and sine functions, the standard period is
\( 2\text{π} \), but this period can be altered by a coefficient attached to the variable inside the function.
For instance,
\( f(x) = \text{cos} (bx) \) where \( b \) affects the period, making it
\( \frac{2\text{π}}{|b|} \). In our exercise, the period of both
\( f(x) \) and
\( g(x) \) is
\( \frac{2\text{π}}{4} = \frac{\text{π}}{2} \), since the coefficient \( b \) is 4. This shortened period means our 'Ferris wheel' goes around much faster, completing a cycle in just a quarter of the time it usually takes.
\( 2\text{π} \), but this period can be altered by a coefficient attached to the variable inside the function.
For instance,
\( f(x) = \text{cos} (bx) \) where \( b \) affects the period, making it
\( \frac{2\text{π}}{|b|} \). In our exercise, the period of both
\( f(x) \) and
\( g(x) \) is
\( \frac{2\text{π}}{4} = \frac{\text{π}}{2} \), since the coefficient \( b \) is 4. This shortened period means our 'Ferris wheel' goes around much faster, completing a cycle in just a quarter of the time it usually takes.
Vertical Shifts in Trigonometric Graphs
Now, picture you're on a swing—any movement up or down from the resting position is a vertical shift. In trigonometry, a vertical shift moves the entire graph of a function up or down on the coordinate plane.
When a constant is added or subtracted from the trigonometric function
\( f(x) = \text{cos} (x) \), as in
\( g(x) = -2 + \text{cos} (4x) \) from our exercise, the graph is translated vertically. This -2 in
\( g(x) \) means the graph is shifted down by 2 units. It's essential to note that vertical shifts do not affect the amplitude or period; think of it as sliding the whole swing set lower or higher, without changing the swing's range of motion. Thus,
\( g(x) \) experiences a downward shift, creating a visual 'offset' when compared to
\( f(x) \) without altering the swing's amplitude or the speed at which it moves (period).
When a constant is added or subtracted from the trigonometric function
\( f(x) = \text{cos} (x) \), as in
\( g(x) = -2 + \text{cos} (4x) \) from our exercise, the graph is translated vertically. This -2 in
\( g(x) \) means the graph is shifted down by 2 units. It's essential to note that vertical shifts do not affect the amplitude or period; think of it as sliding the whole swing set lower or higher, without changing the swing's range of motion. Thus,
\( g(x) \) experiences a downward shift, creating a visual 'offset' when compared to
\( f(x) \) without altering the swing's amplitude or the speed at which it moves (period).
Other exercises in this chapter
Problem 26
Sketch the graph of the function. (Include two full periods.) Use a graphing utility to verify your result. \(y=\csc (2 x-\pi)\)
View solution Problem 26
The point is on the terminal side of an angle in standard position. Determine the exact values of the six trigonometric functions of the angle. $$(3,-9)$$
View solution Problem 27
Use a calculator to approximate the value of the expression, if possible. Round your answer to the nearest hundredth. arctan (-6)
View solution Problem 27
Sketch the graph of the function. (Include two full periods.) Use a graphing utility to verify your result. \(y=2 \cot \left(x+\frac{\pi}{2}\right)\)
View solution