Problem 26
Question
Consider the following formulas of two esters:
Step-by-Step Solution
Verified Answer
The first SMILES represents methyl propanoate, and the second represents ethyl ethanoate.
1Step 1: Identify the structure for each ester
The SMILES notation for the first ester, CCC(=O)OC, represents a molecule with the structure CH3CH2COOCH3, which is methyl propanoate (methyl propionate). The second SMILES, CCOC(C)=O, represents a molecule with the structure CH3COOCH2CH3, which is ethyl ethanoate (ethyl acetate).
2Step 2: Verify the alkyl and acid part of each ester
In the first SMILES, CCC(=O)OC, the propanoate is the acid part (CH3CH2COO-) and the methyl group (-CH3) is the alkyl part. In the second SMILES, CCOC(C)=O, the ethanoate is the acid part (CH3COO-) and the ethyl group (-CH2CH3) is the alkyl part.
3Step 3: Assign the correct name to each structure
Since the first structure's alkyl part is methyl and its acid part is propanoate, it is methyl propanoate (methyl propionate). The second structure, with an ethyl alkyl group and an ethanoate acid part, is ethyl ethanoate (ethyl acetate).
Key Concepts
SMILES NotationOrganic ChemistryFunctional Groups
SMILES Notation
SMILES, which stands for Simplified Molecular Input Line Entry System, is a method of describing a chemical structure in a simplified, text format. It uses a set of rules to represent molecules in a linear string of characters. This makes it particularly useful for storing and communicating information about molecular structures digitally.
- Each type of atom is represented by its elemental symbol (e.g., C for carbon, O for oxygen).
- Chemical bonds are indicated by specific characters: single bonds are implied by adjacency, double bonds are denoted by '=', and triple bonds by '#'.
- Branches of chains are enclosed in parentheses to show how atoms are connected.
- Rings are represented by breaking one bond, which is shown as a digit that matches the atom where the ring joins back up.
Organic Chemistry
Organic chemistry focuses on carbon-based compounds, which are incredibly varied due to carbon's ability to form stable bonds with many elements, including itself. This branch of chemistry is essential to understanding the molecules that make up living organisms as well as synthetic compounds like plastics, pharmaceuticals, and fuels.
Key principles in organic chemistry include:
One of the fundamental understandings in this field is how small changes in molecular structure can lead to significant differences in chemical properties and reactivity.
Key principles in organic chemistry include:
- Understanding how atoms form bonds to create molecules.
- Identifying functional groups that affect chemical reactivity and properties.
- Studying how reactions occur, mechanisms that explain the transformations, and the synthesis of different compounds.
One of the fundamental understandings in this field is how small changes in molecular structure can lead to significant differences in chemical properties and reactivity.
Functional Groups
In organic chemistry, functional groups are specific groups of atoms within molecules that have characteristic properties and reactions. They are key to identifying and understanding the versatility of organic compounds. Functional groups allow chemists to predict the behavior and reactivity of a molecule.
Common functional groups include:
Recognizing functional groups in a compound helps in predicting how it will interact with other chemicals and is crucial for understanding mechanisms in both chemical reactions and biological processes.
Common functional groups include:
- Hydroxyl group (-OH)
- Carbonyl group (>C=O)
- Carboxyl group (-COOH)
- Amino group (-NH2)
- Ester group (-COO-)
Recognizing functional groups in a compound helps in predicting how it will interact with other chemicals and is crucial for understanding mechanisms in both chemical reactions and biological processes.
Other exercises in this chapter
Problem 21
Explain why you wouldn't expect to find a compound with the formula \(\mathrm{CH}_{5}\).
View solution Problem 25
Why would you expect the melting points of the alkanes to increase in the series methane, ethane, propane, and so on?
View solution Problem 33
Write an equation for a possible substitution reaction of ethane, \(\mathrm{C}_{2} \mathrm{H}_{6}\), with \(\mathrm{Cl}_{2}\)
View solution Problem 34
Write an equation for a possible substitution reaction of propane, \(\mathrm{C}_{3} \mathrm{H}_{8}\), with \(\mathrm{Br}_{2}\).
View solution