Problem 26
Question
Calculate \(\Delta E\) for a. the combustion of a gas that releases \(210.0 \mathrm{kJ}\) of heat to its surroundings and does \(65.5 \mathrm{kJ}\) of work on its surroundings. b. a chemical reaction that produces \(90.7 \mathrm{kJ}\) of heat but does no work on its surroundings.
Step-by-Step Solution
Verified Answer
Question: Determine the change in internal energy (∆E) for both situation (a) and situation (b) using the first law of thermodynamics.
Given information:
a. q = -210.0 kJ, w = -65.5 kJ
b. q = 90.7 kJ, w = 0 kJ
Answer:
For situation (a), the change in internal energy (∆E) is -275.5 kJ.
For situation (b), the change in internal energy (∆E) is 90.7 kJ.
1Step 1: Identify given information
For each situation, make sure to have the necessary variables at hand:
a. q = -210.0 kJ, w = -65.5 kJ
b. q = 90.7 kJ, w = 0 kJ
2Step 2: Determine ∆E for situation (a)
Using the first law of thermodynamics equation, ∆E = q + w, plug in the values for situation a:
∆E_a = (-210.0\,\text{kJ}) + (-65.5\,\text{kJ})
3Step 3: Calculate ∆E for situation (a)
Perform the addition for situation (a):
∆E_a = -275.5\,\text{kJ}
The change in internal energy for the combustion of the gas in situation (a) is -275.5 kJ.
4Step 4: Determine ∆E for situation (b)
Using the first law of thermodynamics equation, ∆E = q + w, plug in the values for situation b:
∆E_b = (90.7\,\text{kJ}) + (0\,\text{kJ})
5Step 5: Calculate ∆E for situation (b)
Perform the addition for situation (b):
∆E_b = 90.7\,\text{kJ}
The change in internal energy for the chemical reaction in situation (b) is 90.7 kJ.
Key Concepts
First Law of ThermodynamicsInternal Energy CalculationCombustion Reactions
First Law of Thermodynamics
The first law of thermodynamics is a fundamental principle in physics governing the conservation of energy. This principle asserts that energy cannot be created or destroyed, only transformed from one form to another. In simpler terms, the total energy in a closed system remains constant over time.
This principle is often expressed through an equation:
In a real-world context, if a system releases heat (q is negative) or does work on the surroundings (w is negative), the internal energy of the system decreases. Conversely, when a system absorbs heat or work is done on it, its internal energy increases. This equation allows us to quantify these energy changes effectively.
This principle is often expressed through an equation:
- \( \Delta E = q + w \)
In a real-world context, if a system releases heat (q is negative) or does work on the surroundings (w is negative), the internal energy of the system decreases. Conversely, when a system absorbs heat or work is done on it, its internal energy increases. This equation allows us to quantify these energy changes effectively.
Internal Energy Calculation
Internal energy represents the total energy contained within a system. Calculating changes in internal energy involves understanding how heat and work affect the energy reserves of a system.
To compute \( \Delta E \), you apply the first law of thermodynamics. Let's break it down for clarity:
To compute \( \Delta E \), you apply the first law of thermodynamics. Let's break it down for clarity:
- The formula is \( \Delta E = q + w \).
- If heat flows into the system, \( q \) is positive.
- If the system releases heat to the surroundings, \( q \) is negative.
- Work done on the system makes \( w \) positive.
- Work done by the system on the surroundings makes \( w \) negative.
Combustion Reactions
Combustion is a fundamental chemical process where a substance reacts rapidly with oxygen, releasing energy mainly in the form of heat and light. This reaction is an exothermic process, meaning it releases more energy than it absorbs.
Key characteristics of combustion reactions include:
Key characteristics of combustion reactions include:
- They usually involve hydrocarbons reacting with oxygen.
- They produce carbon dioxide and water as common byproducts.
- The energy released is primarily in the form of heat, making the heat term \( q \) typically negative (indicating a release of heat to the surroundings).
Other exercises in this chapter
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