Problem 26
Question
By considering the graph of the function but not calculating any limits, give the value of \(f^{\prime}(2)\) for each function. $$f(x)=3 x+4$$
Step-by-Step Solution
Verified Answer
The value of \(f'(2)\) is 3.
1Step 1: Understand the Problem
We are tasked to find the derivative of the function \(f(x) = 3x + 4\) and evaluate it at \(x = 2\), specifically \(f'(2)\).
2Step 2: Identify the Form of the Function
The function \(f(x) = 3x + 4\) is a linear function in the form \(y = mx + b\), where \(m\) is the slope of the line.
3Step 3: Determine the Slope
For the linear function \(f(x) = 3x + 4\), the slope \(m\) is the coefficient of \(x\), which is 3. Since the derivative of a linear function is the slope of the line, \(f'(x) = 3\).
4Step 4: Evaluate the Derivative at \(x=2\)
Since \(f'(x) = 3\) for all \(x\) because it's a linear function, \(f'(2) = 3\) as well.
Key Concepts
Linear FunctionsSlopeEvaluation of DerivativesPrecalculus
Linear Functions
A linear function is a type of function that describes a straight line when graphed on a coordinate plane. It's expressed in the form of \[ y = mx + b \] where:
In this context, our function, \( f(x) = 3x + 4 \), is linear, making it straightforward to analyze and work with.
- \( m \) represents the slope of the line.
- \( b \) is the y-intercept, which is the point where the line crosses the y-axis.
In this context, our function, \( f(x) = 3x + 4 \), is linear, making it straightforward to analyze and work with.
Slope
The slope is a key feature of a linear function, indicating the steepness or incline of the line on a graph. It is defined as the ratio of the change in the y-values to the change in the x-values as you move along the line. In simpler terms, it's often described as "rise over run."
For the function \( f(x) = 3x + 4 \), the slope \( m \) is 3, meaning for every unit increase in \( x \), \( y \) increases by 3 units.
This consistent rate of change is characteristic of linear functions.
Understanding slope helps easily identify how variables in a linear equation relate to one another.
For the function \( f(x) = 3x + 4 \), the slope \( m \) is 3, meaning for every unit increase in \( x \), \( y \) increases by 3 units.
This consistent rate of change is characteristic of linear functions.
- The slope is positive if the line rises to the right.
- It's negative if the line falls to the right.
Understanding slope helps easily identify how variables in a linear equation relate to one another.
Evaluation of Derivatives
Derivatives measure how a function changes as its input changes. They are a fundamental concept in calculus, often representing the slope of a function at any given point. When working with linear functions, their derivatives are particularly easy to evaluate.
Since the derivative of a function describes its instantaneous rate of change, for linear functions like \( f(x) = 3x + 4 \), the derivative \( f'(x) \) is constant. It equals the line’s slope, \( m = 3 \). Thus, no matter where you evaluate the derivative, \( f'(x) = 3 \).
This consistency makes linear functions quite predictable, especially when differentiating, as the slope remains unchanged.
Since the derivative of a function describes its instantaneous rate of change, for linear functions like \( f(x) = 3x + 4 \), the derivative \( f'(x) \) is constant. It equals the line’s slope, \( m = 3 \). Thus, no matter where you evaluate the derivative, \( f'(x) = 3 \).
This consistency makes linear functions quite predictable, especially when differentiating, as the slope remains unchanged.
Precalculus
Precalculus serves as the bridge linking algebra concepts with the more advanced topics tackled in calculus. It prepares students by providing the necessary base and familiarity with functions, slopes, and other key concepts.
Understanding linear functions, their slopes, and derivatives are all foundational elements of precalculus. These concepts empower students with the tools to analyze more complex and dynamic functions encountered in calculus.
In precalculus, students learn to recognize patterns and behaviors of various functions, laying the groundwork for derivative evaluation.
Understanding linear functions, their slopes, and derivatives are all foundational elements of precalculus. These concepts empower students with the tools to analyze more complex and dynamic functions encountered in calculus.
In precalculus, students learn to recognize patterns and behaviors of various functions, laying the groundwork for derivative evaluation.
- Precalculus focuses on pattern recognition and function behavior.
- It builds confidence for handling changes and rates, such as those represented by derivatives.
Other exercises in this chapter
Problem 25
Determine each limit, if it exists. $$\lim _{x \rightarrow-2} \frac{x^{2}-x-6}{x+2}$$
View solution Problem 25
Complete each table and use the results to predict the indicated limit, if it exists. If \(f(x)=\frac{\sqrt{x}-2}{x-1},\) find \(\lim _{x \rightarrow 1} f(x)\)
View solution Problem 26
Use a table and/or graph to find the asymptote\((s)\) of each function. $$f(x)=\frac{x-\cos x}{x+\sin x}$$
View solution Problem 26
Determine each limit, if it exists. $$\lim _{x \rightarrow 5} \frac{x^{2}-3 x-10}{x-5}$$
View solution