Problem 26
Question
Aqueous barium chloride and aqueous potassium carbonate react to produce solid barium carbonate and aqueous potassium chloride.
Step-by-Step Solution
Verified Answer
The balanced chemical equation for the reaction between aqueous barium chloride (BaCl2) and aqueous potassium carbonate (K2CO3) is:
\(BaCl_2(aq) + K_2CO_3(aq) \rightarrow BaCO_3(s) + 2KCl(aq)\)
In this double replacement reaction, solid barium carbonate (BaCO3) and aqueous potassium chloride (2KCl) are the products.
1Step 1: Barium chloride formula
The chemical formula for barium chloride is BaCl2, where Ba represents a Ba^(2+) ion and Cl represents a Cl^(-) ion.
2Step 2: Potassium carbonate formula
The chemical formula for potassium carbonate is K2CO3, where K represents a K^(+) ion and CO3 represents a CO3^(2-) ion.
#Step 2: Write and balance the chemical equation for the reaction#
3Step 3: Double replacement
In a double replacement reaction, the cations and anions of the two reactants switch places to form new products:
BaCl2(aq) + K2CO3(aq) → BaCO3(s) + 2KCl(aq)
Here, Ba^(2+) and Cl^(-) switch places with K^(+) and CO3^(2-), respectively. The coefficients 1 and 2 are used to balance the equation.
#Step 3: Identify the state of matter for each product#
4Step 4: Barium carbonate state
The problem states that barium carbonate is a solid product, so we indicate this with an (s) after its formula.
5Step 5: Potassium chloride state
The problem states that potassium chloride is an aqueous product, so we indicate this with an (aq) after its formula.
#Final Answer: Balanced chemical equation with states of matter#
The balanced chemical equation for the reaction between aqueous barium chloride and aqueous potassium carbonate is:
BaCl2(aq) + K2CO3(aq) → BaCO3(s) + 2KCl(aq)
Key Concepts
Double Replacement ReactionBalancing Chemical EquationsStates of Matter
Double Replacement Reaction
In chemistry, a double replacement reaction involves two compounds that exchange parts, forming two new compounds. These reactions typically occur in solutions where two ionic compounds swap components.
For example, in our exercise, barium chloride \(\text{BaCl}_2\) and potassium carbonate \(\text{K}_2\text{CO}_3\) undergo a double replacement reaction.
Here's how it works:
For example, in our exercise, barium chloride \(\text{BaCl}_2\) and potassium carbonate \(\text{K}_2\text{CO}_3\) undergo a double replacement reaction.
Here's how it works:
- The positive ions (cations) and negative ions (anions) from two different compounds switch places.
- In this case, Ba^(2+) from barium chloride trades places with K^(+) from potassium carbonate.
- The result is the formation of barium carbonate \(\text{BaCO}_3\) and potassium chloride \(\text{KCl}\).
Balancing Chemical Equations
Balancing chemical equations is an essential skill in chemistry. It ensures that the same number of each type of atom is present on both sides of the equation. This balance adheres to the Law of Conservation of Mass, which states that mass cannot be created or destroyed in an ordinary chemical reaction.
For our example reaction: \[\text{BaCl}_2(\text{aq}) + \text{K}_2\text{CO}_3(\text{aq}) \rightarrow \text{BaCO}_3(\text{s}) + 2\text{KCl}(\text{aq})\]
For our example reaction: \[\text{BaCl}_2(\text{aq}) + \text{K}_2\text{CO}_3(\text{aq}) \rightarrow \text{BaCO}_3(\text{s}) + 2\text{KCl}(\text{aq})\]
- The equation starts with the same number of Ba, Cl, K, and CO atoms on both sides.
- By adding the coefficient "2" in front of \(\text{KCl}\), the equation becomes balanced.
States of Matter
The states of matter in a chemical equation indicate the physical form each substance takes during the reaction. These states are crucial for understanding how substances interact in different phases.
In our reaction, we observe:
In our reaction, we observe:
- Aqueous (aq) - Substances dissolved in water, such as barium chloride and potassium carbonate, are in aqueous form.
- Solid (s) - Barium carbonate precipitates out of the solution as a solid, indicated by (s).
- Another aqueous (aq) - Potassium chloride remains dissolved in water.
Other exercises in this chapter
Problem 18
Aluminum oxide(s) decomposes when electricity passes through it.
View solution Problem 19
Nickel( II) hydroxide(s) decomposes to produce nickel( II) oxide(s) and water.
View solution Problem 27
Aqueous sodium oxalate and aqueous lead(II) nitrate react to produce solid lead(II) oxalate and aqueous sodium nitrate.
View solution Problem 28
Challenge Acetic acid \(\left(\mathrm{CH}_{3} \mathrm{COOH}\right)\) and potassium hydroxide react to produce potassium acetate and water.
View solution