Problem 26
Question
a. Why is potassium tert-butoxide, \(\stackrel{\oplus}{\mathrm{K}} \mathrm{O} \mathrm{C}\left(\mathrm{CH}_{3}\right)_{3}\), an excellent base for promoting elimination reactions of alkyl halides, whereas ethylamine, \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{NH}_{2}\), is relatively poor for the same purpose? b. Potassium tert-butoxide is many powers of ten more effective a reagent for achieving \(E 2\) eliminations in methylsulfinylmethane (dimethyl sulfoxide) than in tert-butyl alcohol. Explain.
Step-by-Step Solution
Verified Answer
Potassium tert-butoxide is strong and bulky, favoring elimination. It's more effective in DMSO because it doesn't solvate the base like tert-butyl alcohol.
1Step 1: Understand the Role of Bases in Elimination Reactions
In elimination reactions, particularly E2 reactions, a strong base is needed to abstract a hydrogen atom adjacent to the leaving group on the alkyl halide, facilitating the formation of a double bond.
2Step 2: Evaluate the Structure and Strength of Bases
Potassium tert-butoxide, \(\stackrel{\oplus}{\mathrm{K}} \mathrm{O}\mathrm{C}\left(\mathrm{CH}_{3}\right)_{3}\), is a bulky and strong base, which makes it highly suitable for E2 reactions. Its bulkiness prevents it from acting as a nucleophile, favoring elimination over substitution. Conversely, ethylamine, \(\mathrm{CH}_{3}\mathrm{CH}_{2} \mathrm{NH}_{2}\), has a less bulky structure and is a weaker base, making it less effective in promoting elimination.
3Step 3: Analyze Solvent Effects
Potassium tert-butoxide is more effective in dimethyl sulfoxide (DMSO) compared to tert-butyl alcohol because DMSO is a polar aprotic solvent. Such solvents stabilize ionic intermediates like the transition state without solvating the base, enhancing its basic strength and reactivity. In contrast, tert-butyl alcohol is a polar protic solvent, which can hydrogen bond with the base, reducing its availability to abstract a proton and thus decreasing its effectiveness in promoting E2 reactions.
Key Concepts
Potassium tert-butoxideE2 mechanismSolvent effectsBulky bases
Potassium tert-butoxide
Potassium tert-butoxide is a common reagent in organic chemistry, particularly valued in elimination reactions. Its chemical formula is \[ \text{KOC}(\text{CH}_3)_3 \] and it is known for being a strong, non-nucleophilic base. This means it efficiently removes protons without participating in substitution reactions. The bulkiness of the tert-butoxide part of the molecule is crucial. It hampers the base's ability to approach and react with electrophilic centers within molecules, thus discouraging the unwanted nucleophilic substitution reactions while promoting elimination. Key properties include:
- High basicity due to the presence of the alkoxide ion (\[ \text{OC}(\text{CH}_3)_3^- \] ), which is a strong proton acceptor.
- Bulky structure prevents it from fitting into the electron-deficient regions typically involved in substitution reactions, favoring its role as a base over a nucleophile.
- It's typically used in solid and dry form to avoid complications arising from water or other solvents that might attenuate its strong basicity.
E2 mechanism
The E2 mechanism is one of the most common pathways in elimination reactions, especially when using strong bases like potassium tert-butoxide. In an E2 reaction, the 'E' stands for elimination, and the '2' indicates that it is bimolecular, involving a simultaneous interaction between the base and the substrate.
### The E2 Reaction Process
- **Bimolecular:** Both the base and substrate (usually an alkyl halide) are involved in the rate-determining step. This means the reaction rate depends on the concentration of both the reactants.
- **Concerted Mechanism:** The E2 mechanism involves the simultaneous breaking of a C-H bond and the formation of a C=C double bond, as well as the expulsion of a leaving group from an adjacent carbon atom.
- **Stereochemistry:** The most stable configuration, often requiring anti-coplanar geometry, is favored in E2 reactions. This requires the hydrogen atom being abstracted to be oriented opposite the leaving group.
E2 reactions are favored in conditions where strong, bulky bases are present under aprotic conditions, which we will delve into in the next section.
Solvent effects
Solvent effects play a critical role in determining the efficiency of elimination reactions, especially in E2 mechanisms. Solvent choice can drastically influence the outcome of a reaction by stabilizing certain transition states or intermediates.
### Polar Aprotic vs. Polar Protic Solvents
- **Polar Aprotic Solvents:** These solvents, such as dimethyl sulfoxide (DMSO), do not contain hydrogen atoms capable of forming hydrogen bonds with the base. They provide an environment where bases like potassium tert-butoxide retain their high reactivity and basic strength, making them more effective in promoting the E2 mechanism.
- **Polar Protic Solvents:** Examples include alcohols like tert-butyl alcohol. These solvents contain hydrogen atoms that can hydrogen bond with the base, significantly reducing its ability to participate in effective elimination reactions. This occurs because the solvent molecules can surround and stabilize the base, hindering its interaction with the substrate.
When using an E2 mechanism, choosing a polar aprotic solvent often leads to better yields and faster reaction rates, making it a crucial decision in laboratory synthesis.
Bulky bases
Bulky bases like potassium tert-butoxide are key players in elimination reactions due to their size and steric hindrance. Steric hindrance occurs when the size of a molecule prevents certain reactions due to physical obstruction, a characteristic of bulky bases that prevents them from acting as nucleophiles.
### Advantages of Bulky Bases in Elimination
- **Preference for Elimination:** Due to their large size, bulky bases cannot easily approach and react with the electrophilic centers in a molecule, favoring elimination processes where they act as a base and abstract protons.
- **Selective Reactivity:** Bulky bases target less accessible protons that smaller, more nucleophilic bases might not react with, allowing for more selective reaction pathways and products.
### Common Bulky Bases and Their Use
- **Potassium tert-butoxide:** This is perhaps the most classic example of a bulky base, widely used in sterically demanding elimination reactions.
- **Other Examples:** Bases such as lithium diisopropylamide (LDA) and other similar species are employed in various conditions requiring similar bulky base characteristics.
Their ability to avoid substitution reactions and selectively promote elimination is why bulky bases are invaluable in organic synthesis.
Other exercises in this chapter
Problem 24
An alternative mechanism for \(E 2\) elimination is the following: $$ \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{Cl}+\mathrm{OH}^{\ominus} \stackrel{\text { fast }
View solution Problem 25
Write equations and mechanisms for all the products that might reasonably be expected from the reaction of 2 chlorobutane with a solution of potassium hydroxide
View solution Problem 31
The reaction of tert-butyl chloride with water is accelerated strongly by sodium hydroxide. How would the ratio of elimination to substitution products be affec
View solution Problem 33
Predict the products of the following reactions: a. \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CBr}\left(\mathrm{CH}_{3}\right) \mathrm{CH}_{2} \mathrm{CH}_{3} \
View solution