Problem 26
Question
A combination lock will open when the right choice of three numbers (from \( 1 \) to \( 50 \), inclusive) is selected. How many different lock combinations are possible?
Step-by-Step Solution
Verified Answer
The total number of different lock combinations is \( 50^3 = 125000 \).
1Step 1: Understanding the problem
Consider each number as a distinct choice and presume repetition is allowed. The first number can be any of 50 choices, and so can be the second and third.
2Step 2: Calculation
Calculate the total choices by multiplying the number of choices for each number. As there are 50 choices for the first number, 50 for the second and 50 for the third, the total number of permutations can be represented as \( 50*50*50 \).
3Step 3: Final answer
Executing the multiplication (50*50*50), we can find the total number of different combinations.
Key Concepts
CombinatoricsRepetition AllowedPermutations
Combinatorics
Combinatorics is a branch of mathematics focused on counting, arranging, and combining objects. In the context of combination locks, combinatorics helps determine how many possible ways you can arrange a set of numbers.
It's like playing with different arrangements and selections of numbers.
It's like playing with different arrangements and selections of numbers.
- Combinatorics deals with the study of finite or countable discreet systems, which means systems that can eventually be counted one by one.
- It examines how objects can be selected and arranged in different combinations, either by themselves or in groups.
- Its applications stretch from simple tasks like figuring out lock codes to complex tasks in computer science and cryptography.
Repetition Allowed
The concept of repetition allowed means you can use the same number more than once in a combination. In our lock example, this means any of the numbers from 1 to 50 can appear multiple times in the combination.
For instance, "5-5-5" is a valid combination.
For instance, "5-5-5" is a valid combination.
- This concept hugely increases the number of possible combinations.
- If repetition was not allowed, each of the numbers would have to be different, drastically reducing the possibilities.
- With repetition permitted, each position in a choice can be filled without restriction, allowing greater flexibility and more options.
Permutations
Permutations refer to the arrangement of elements in a particular order. When we consider permutations in combination locks with repetition, each position in the sequence (like our three-number lock) can have any number from 1 to 50.
It's about considering the order of each choice.
It's about considering the order of each choice.
- A permutation considers the importance of sequence, unlike a simple combination where order doesn't matter.
- For our lock, a sequence like "1-2-3" is different from "3-2-1" because the order of numbers affects the result.
- The number of permutations available is calculated by multiplying the number of options per position, which in this case, was found as 50 choices raised to the power of the number of positions (three), so the formula for calculation was \( 50^3 \).
Other exercises in this chapter
Problem 25
In Exercises 9-32, write the first five terms of the sequence. (Assume that \( n \) begins with 1.) \( a_n = \dfrac{(-1)^n}{n^2} \)
View solution Problem 26
In Exercises 25 - 30, find the probability for the experiment of tossing a six-sided die twice. The sum is at least \( 8 \).
View solution Problem 26
In Exercises 19 - 40, use the Binomial Theorem to expand and simplify the expression. \( \left(c + d\right)^3 \)
View solution Problem 26
In Exercises 25 - 30, prove the inequality for the indicated integer values of \( n \). \( \left(\dfrac{4}{3}\right)^n > n, n \ge 7 \)
View solution