Problem 26
Question
\(21-28\) Use a Factoring Formula to factor the expression. $$ 1+1000 y^{3} $$
Step-by-Step Solution
Verified Answer
The expression is factored as \((1 + 10y)(1 - 10y + 100y^2)\).
1Step 1: Identify the Type of Expression
The expression given is similar to a sum of cubes. A sum of cubes has the general form \(a^3 + b^3\), and we need to factor this form.
2Step 2: Rewrite the Expression in Sum of Cubes Form
Recognize \(1\) as \((1)^3\) and \(1000y^3\) as \((10y)^3\). So, the original expression \(1 + 1000y^3\) can be rewritten as \((1)^3 + (10y)^3\).
3Step 3: Recall the Sum of Cubes Formula
The sum of cubes formula is given by: \(a^3 + b^3 = (a + b)(a^2 - ab + b^2)\). We will use this formula to factor the expression.
4Step 4: Substitute into the Formula
Using \(a = 1\) and \(b = 10y\), substitute into the sum of cubes formula: \((1 + 10y)((1)^2 - (1)(10y) + (10y)^2)\).
5Step 5: Simplify the Expression
Simplify the expression: \((1 + 10y)(1 - 10y + 100y^2)\). This is the fully factored form of the original expression.
Key Concepts
Sum of Cubes FormulaAlgebraic ExpressionsPolynomial Factorization
Sum of Cubes Formula
Understanding how to factor using the sum of cubes formula is a fundamental technique in algebra. The sum of cubes is an expression in the form of \(a^3 + b^3\). This expression can be factored using a specific formula:
For instance, if you have \(1 + 1000y^3\), you recognize that \(1 = (1)^3\) and \(1000y^3 = (10y)^3\). With this recognition, you identify \(a = 1\) and \(b = 10y\). Substituting these values into the sum of cubes formula allows you to factor the expression successfully.
- \(a^3 + b^3 = (a + b)(a^2 - ab + b^2)\)
For instance, if you have \(1 + 1000y^3\), you recognize that \(1 = (1)^3\) and \(1000y^3 = (10y)^3\). With this recognition, you identify \(a = 1\) and \(b = 10y\). Substituting these values into the sum of cubes formula allows you to factor the expression successfully.
Algebraic Expressions
An algebraic expression consists of numbers, variables, and operation symbols. It's crucial to understand the structure of algebraic expressions to manipulate them correctly. These expressions can range from simple ones like \(x + 2\), to more complex ones like \(1 + 1000y^3\).
When dealing with an algebraic expression that resembles cubes, such as \(1 + 1000y^3\), you're looking for ways to simplify or rewrite it in a usable form—specifically, a factored form. Recognizing patterns in algebraic expressions, like that of cubes, makes it easier to use the appropriate formulas for simplification.
By rewriting the expression as \((1)^3 + (10y)^3\), you can apply the sum of cubes formula, which simplifies the tasks of finding manageable factors. The goal is to break down the complex expression into parts that are easier to handle.
When dealing with an algebraic expression that resembles cubes, such as \(1 + 1000y^3\), you're looking for ways to simplify or rewrite it in a usable form—specifically, a factored form. Recognizing patterns in algebraic expressions, like that of cubes, makes it easier to use the appropriate formulas for simplification.
By rewriting the expression as \((1)^3 + (10y)^3\), you can apply the sum of cubes formula, which simplifies the tasks of finding manageable factors. The goal is to break down the complex expression into parts that are easier to handle.
Polynomial Factorization
Factoring polynomials is an essential skill that allows you to simplify expressions and solve equations more easily. For polynomial factorization, you often look for common patterns or use specific formulas, like the sum of cubes, to achieve your goal.
In our example, \(1 + 1000y^3\), the expression is recognized as a sum of cubes. Factoring this polynomial involves the steps of identifying the cubes, applying the sum of cubes formula, and simplifying the resulting expression. By rewriting it as \((1)^3 + (10y)^3\), and then substituting into the formula, you reveal the factored form: \((1 + 10y)(1 - 10y + 100y^2)\).
This process of breaking down the polynomial into simpler components is what makes polynomial factorization such a powerful tool in algebra. It not only simplifies the expressions but also aids in finding solutions to algebraic equations more effortlessly.
In our example, \(1 + 1000y^3\), the expression is recognized as a sum of cubes. Factoring this polynomial involves the steps of identifying the cubes, applying the sum of cubes formula, and simplifying the resulting expression. By rewriting it as \((1)^3 + (10y)^3\), and then substituting into the formula, you reveal the factored form: \((1 + 10y)(1 - 10y + 100y^2)\).
This process of breaking down the polynomial into simpler components is what makes polynomial factorization such a powerful tool in algebra. It not only simplifies the expressions but also aids in finding solutions to algebraic equations more effortlessly.
Other exercises in this chapter
Problem 25
Use properties of real numbers to write the expression without parentheses. 4\((2 m)\)
View solution Problem 26
Simplify the rational expression. $$ \frac{y^{2}-3 y-18}{2 y^{2}+5 y+3} $$
View solution Problem 26
\(7-28\) Evaluate each expression. $$ \frac{3^{2} \cdot 4^{-2} \cdot 5}{2^{-4} \cdot 3^{3} \cdot 25} $$
View solution Problem 26
\(25-28\) . Evaluate the expression using \(x=3, y=4,\) and \(z=-1\) $$ \sqrt[4]{x^{3}+14 y+2 z} $$
View solution