Problem 26
Question
21-26 \(\approx\) Find the first five terms of the sequence, and determine whether it is arithmetic. If it is arithmetic, find the common difference, and express the \(n\) th term of the sequence in the standard form \(a_{n}=a+(n-1) d\) $$ a_{n}=3+(-1)^{n} n $$
Step-by-Step Solution
Verified Answer
The sequence is not arithmetic; first five terms: 2, 5, 0, 7, -2.
1Step 1: Identify pattern of sequence
Given the sequence formula is \( a_n = 3 + (-1)^n n \). To find the first five terms, we will substitute \( n = 1, 2, 3, 4, 5 \) into this formula.
2Step 2: Calculate the first term
Let \( n = 1 \). Substitute \( n \) into the formula: \[ a_1 = 3 + (-1)^1 \times 1 = 3 - 1 = 2 \]So, the first term \( a_1 = 2 \).
3Step 3: Calculate the second term
Let \( n = 2 \). Substitute \( n \) into the formula:\[ a_2 = 3 + (-1)^2 \times 2 = 3 + 2 = 5 \]So, the second term \( a_2 = 5 \).
4Step 4: Calculate the third term
Let \( n = 3 \). Substitute \( n \) into the formula:\[ a_3 = 3 + (-1)^3 \times 3 = 3 - 3 = 0 \]So, the third term \( a_3 = 0 \).
5Step 5: Calculate the fourth term
Let \( n = 4 \). Substitute \( n \) into the formula:\[ a_4 = 3 + (-1)^4 \times 4 = 3 + 4 = 7 \]So, the fourth term \( a_4 = 7 \).
6Step 6: Calculate the fifth term
Let \( n = 5 \). Substitute \( n \) into the formula:\[ a_5 = 3 + (-1)^5 \times 5 = 3 - 5 = -2 \]So, the fifth term \( a_5 = -2 \).
7Step 7: Check if the sequence is arithmetic
The first five terms of the sequence are 2, 5, 0, 7, -2. The differences are calculated as follows:
Positive difference from 2 to 5: 5 - 2 = 3
Decrease from 5 to 0: 0 - 5 = -5
Increase from 0 to 7: 7 - 0 = 7
Decrease from 7 to -2: -2 - 7 = -9
Since these differences are not constant, the sequence is not arithmetic.
Key Concepts
Sequence PatternsCommon Differencenth Term Formula
Sequence Patterns
A sequence is an ordered list of numbers that follow a particular pattern. Understanding patterns in sequences helps predict future terms and understand the structure of the sequence. In sequences, patterns can be either straightforward or complex. A straightforward sequence is one where you repeatedly apply the same operation to generate the next term. For example, adding the same number each time. Complex patterns, like the one in the formula \( a_n = 3 + (-1)^n n \), alternate the operations, creating a sequence that may not seem immediately predictable. In our example, the pattern uses an alternating process, such that:
- When \( n \) is odd, the sequence subtracts the value \( n \).
- When \( n \) is even, the sequence adds the value \( n \).
Common Difference
The concept of a common difference is central to determining if a sequence is arithmetic. The common difference is the value added to each term to reach the next one. When this difference is the same between every consecutive term, the sequence is termed 'arithmetic.'In our exercise, to determine if the sequence \( a_n = 3 + (-1)^n n \) is arithmetic, we calculated differences between consecutive terms:
- First to second term: \( 5 - 2 = 3 \)
- Second to third term: \( 0 - 5 = -5 \)
- Third to fourth term: \( 7 - 0 = 7 \)
- Fourth to fifth term: \( -2 - 7 = -9 \)
nth Term Formula
The nth term formula calculates any term in a sequence without listing all previous terms. This formula is vital for quickly finding specific terms in large sequences. An arithmetic sequence uses the nth term formula \( a_n = a_1 + (n-1) \cdot d \), where:
- \( a_n \) is the nth term.
- \( a_1 \) is the first term.
- \( d \) is the common difference.
Other exercises in this chapter
Problem 25
Use the Binomial Theorem to expand the expression. $$ (x+2 y)^{4} $$
View solution Problem 25
Let \(a_{n+1}=3 a_{n}\) and \(a_{1}=5 .\) Show that \(a_{n}=5 \cdot 3^{n-1}\) for all natural numbers \(n .\)
View solution Problem 26
Find the first five terms of the sequence, and determine whether it is geometric. If is geometric, find the common ratio, and express the \(n\) th term of the s
View solution Problem 26
\(25-32\) . Find the \(n\) th term of a sequence whose first several terms are given. $$ -\frac{1}{3}, \frac{1}{9},-\frac{1}{27}, \frac{1}{81}, \dots $$
View solution