Problem 26
Question
15–36 Sketch the graph of the polar equation. $$r=\cos \theta-1$$
Step-by-Step Solution
Verified Answer
The graph of \( r = \cos \theta - 1 \) is a limaçon with an inner loop, symmetric about the x-axis.
1Step 1: Understanding Polar Equations
The given polar equation is \( r = \cos \theta - 1 \). In polar coordinates, \( r \) represents the radial distance from the origin and \( \theta \) is the angle with respect to the positive x-axis.
2Step 2: Determine Key Points
To sketch the graph, identify some points by calculating \( r \) for key angles \( \theta \) such as \( 0, \frac{\pi}{2}, \pi, \frac{3\pi}{2} \).\[ r(0) = \cos(0) - 1 = 0,\] \[ r\left(\frac{\pi}{2}\right) = \cos\left(\frac{\pi}{2}\right) - 1 = -1,\] \[ r(\pi) = \cos(\pi) - 1 = -2,\] \[ r\left(\frac{3\pi}{2}\right) = \cos\left(\frac{3\pi}{2}\right) - 1 = -1.\]
3Step 3: Analyze Symmetry and Shape
Observe that if \( r(\theta) = \cos(\theta) - 1 \), then \( r(-\theta) = \cos(-\theta) - 1 = \cos(\theta) - 1 = r(\theta) \), which indicates that the graph is symmetric about the x-axis. The nature of \( \cos \theta \) suggests that the graph will have a typical sinusoidal pattern displaced vertically.
4Step 4: Sketch the Graph
Using the calculated points and symmetry, plot \( (0,0) \), \( \left(\frac{\pi}{2}, -1\right) \), \( (\pi, -2) \), and \( \left(\frac{3\pi}{2}, -1\right) \). Since \( r \) is negative for some \( \theta \), the points will be in the opposite direction of the angle, effectively reflecting across the origin.
5Step 5: Draw the Complete Locus
Connect the points to form the curve. The wave-like pattern repeats every \( \pi \) units due to the periodic nature of cosine. This results in a graph resembling a shifted limaçon with an inner loop.
Key Concepts
Graphing Polar CoordinatesSymmetry in Polar GraphsLimaçon Curves
Graphing Polar Coordinates
Polar coordinates offer a way to describe the position of a point on a plane using a distance from the origin and an angle. This is different from Cartesian coordinates, which use x and y values. The basic idea is that each point is determined by a radius, \( r \), and an angle, \( \theta \). Here are some essential concepts to grasp:
- \( r \) is the distance from the origin to the point.
- \( \theta \) is the angle measured from the positive x-axis.
- The angle \( \theta \) is measured in radians.
- Positive \( r \): Draw the point in the direction of \( \theta \).
- Negative \( r \): Plot the point in the opposite direction of \( \theta \).
Symmetry in Polar Graphs
Symmetry can often simplify graphing polar equations. When a polar graph is symmetric, it means the graph looks the same when flipped, rotated, or moved in a certain way, and this can happen with respect to the origin or the axes. For the function \( r = \cos \theta - 1 \), symmetry is evident:
- X-axis Symmetry: If replacing \( \theta \) with \( -\theta \) yields the same function, the graph has x-axis symmetry. Here, \( r(-\theta) = \cos(-\theta) - 1 = \cos(\theta) - 1 \), indicating x-axis symmetry.
- Origin Symmetry: Points where both \( r \) and \( \theta \) change signs also suggest symmetry around the origin. This isn't directly seen in our function, but negative \( r \) values do suggest reflections.
Limaçon Curves
Limaçon curves are a unique family of curves derived from equations similar to \( r = a + b \cos \theta \) or \( r = a + b \sin \theta \). These shapes are recognized by their characteristic loop or dimple, depending on the values of \( a \) and \( b \).
In the case of \( r = \cos \theta - 1 \), this is a specific type of limaçon called a "limaçon with an inner loop." Here's why:
In the case of \( r = \cos \theta - 1 \), this is a specific type of limaçon called a "limaçon with an inner loop." Here's why:
- When \( |b| > |a| \), an inner loop forms. In the equation, \( a = -1 \) and \( b = 1 \), so \( |b| > |a| \).
- Inner loops are noticeable by the negative \( r \) values, causing the curve to intersect itself, seen at certain angles where \( r \) switches from positive to negative.
- The curve appears to shrink into the center before looping back outwards, painting the full limaçon arc.
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