Problem 258
Question
In the following exercises, solve using rectangle properties. The length of a rectangular poster is 28 inches. The area is 1316 square inches. What is the width?
Step-by-Step Solution
Verified Answer
The width of the poster is 47 inches.
1Step 1: Understand the Given Information
The length of the rectangular poster is 28 inches, and the area is 1316 square inches. We need to find the width of the poster.
2Step 2: Recall the Area Formula
The area of a rectangle is calculated using the formula: \(\text{Area} = \text{Length} \times \text{Width}\).
3Step 3: Set Up the Equation
Using the given information: \(\text{Area} = 28 \text{ inches} \times \text{Width}\). So, the equation is: \(\text{Width} \times 28 = 1316\).
4Step 4: Solve for the Width
To find the width, divide both sides of the equation by 28: \(\text{Width} = \frac{1316}{28} \).
5Step 5: Calculate the Width
Perform the division: \(\text{Width} = \frac{1316}{28} \). So, \(\text{Width} = 47 \text{ inches}\).
Key Concepts
Area of a RectangleDivisionSolving Equations
Area of a Rectangle
In geometry, understanding how to calculate the area of a rectangle is very important. The area is a measure of how much space is enclosed within the rectangle. For a rectangle, the area can be determined using the simple formula: \(\text{Area} = \text{Length} \times \text{Width}\). This formula tells us that to get the area, we multiply the length by the width. It's important because it helps in practical scenarios like finding how much material is needed to cover a surface, like a carpet or a poster.
In our example, the length of the rectangular poster is 28 inches and the area is 1316 square inches. Using the area formula, we can set up an equation to find the unknown width by plugging in the known values.
In our example, the length of the rectangular poster is 28 inches and the area is 1316 square inches. Using the area formula, we can set up an equation to find the unknown width by plugging in the known values.
Division
Division is one of the basic arithmetic operations and is essentially the process of determining how many times one number is contained within another. In the context of our rectangle problem, we use division to isolate the unknown variable (the width). When we set up our equation from the area formula, we have: \( \text{Width} \times 28 = 1316 \).
To solve for the width, we need to divide 1316 by 28: \( \text{Width} = \frac{1316}{28} \). This operation helps us find out how many 28-inch segments fit into 1316 square inches, essentially uncovering the length of the other dimension. Division breaks down a complex problem into simpler, more understandable parts.
To solve for the width, we need to divide 1316 by 28: \( \text{Width} = \frac{1316}{28} \). This operation helps us find out how many 28-inch segments fit into 1316 square inches, essentially uncovering the length of the other dimension. Division breaks down a complex problem into simpler, more understandable parts.
Solving Equations
Solving equations is another critical mathematical skill. An equation is a mathematical statement that asserts the equality of two expressions. To solve an equation means to find the value of the variable that makes the equation true.
In this exercise, solving for the width involves following these steps:
In this exercise, solving for the width involves following these steps:
- We start with the equation derived from the area formula: \( \text{Width} \times 28 = 1316 \).
- To isolate the width, we divide both sides by 28, resulting in the simplified equation: \( \text{Width} = \frac{1316}{28} \).
- Perform the division to find the width: \( \text{Width} = 47 \).
Other exercises in this chapter
Problem 256
In the following exercises, solve using rectangle properties. The area of a rectangle is 782 square centimeters. The width is 17 centimeters. What is the length
View solution Problem 257
In the following exercises, solve using rectangle properties. The width of a rectangular window is 24 inches. The area is 624 square inches. What is the length?
View solution Problem 259
In the following exercises, solve using rectangle properties. Find the length of a rectangle with perimeter 124 and width 38 .
View solution Problem 260
In the following exercises, solve using rectangle properties. Find the width of a rectangle with perimeter 92 and length \(19 .\)
View solution