Problem 255
Question
If \(f=g \circ h,\) when reversing the chain rule, \(\frac{d}{d x}(g \circ h)(x)=g^{\prime}(h(x)) h^{\prime}(x), \quad\) should you take \(u=g(x)\) or \(u=h(x) ?\)
Step-by-Step Solution
Verified Answer
Take \(u = h(x)\).
1Step 1: Understanding the Function Composition
The exercise deals with a function composition where \(f = g \circ h\). This means \(f(x) = g(h(x))\). This is important because it defines how the functions are nested.
2Step 2: Analyzing the Chain Rule
The chain rule for differentiation states that if you have a composite function \((g \circ h)(x)\), its derivative is given as \(\frac{d}{d x}(g \circ h)(x)=g^{\prime}(h(x)) h^{\prime}(x)\). This form arises from treating \(h(x)\) as an inner function and \(g(u)\) as the outer function where \(u = h(x)\).
3Step 3: Determining the Variable \(u\)
In the context of the chain rule, \(u\) is typically the inner function when breaking down the differentiation of a composite function. Therefore, given \(f = g \circ h\), the inner function is \(h(x)\), meaning \(u = h(x)\).
4Step 4: Conclusion on Variable Choice
Therefore, since \(h(x)\) is the inner function applied inside \(g\), the correct choice for \(u\) when applying the chain rule in reverse is \(u = h(x)\).
Key Concepts
Composite FunctionsFunction CompositionDifferentiation
Composite Functions
In mathematics, a composite function is a fancy way of linking two functions together. Think of it like nesting one function inside another. If we have two functions, say \(g(x)\) and \(h(x)\), composing them would mean creating a new function \(f(x) = g(h(x))\).
This means we're plugging the value of \(x\) into \(h(x)\) first, and then taking the result and plugging it into \(g(x)\). This is very similar to a two-step process:
This means we're plugging the value of \(x\) into \(h(x)\) first, and then taking the result and plugging it into \(g(x)\). This is very similar to a two-step process:
- First: Calculate \(h(x)\).
- Second: Use the result from \(h(x)\) and find \(g(h(x))\).
Function Composition
Function composition is like following a recipe where the result of one step is needed in the next. When you compose two functions, \(g\) and \(h\), and say it's \(g \circ h\), you're basically saying you want to perform \(h\) first, then \(g\) on the result of \(h\).
Visualizing function composition can help: imagine \(h(x)\) as a machine that modifies \(x\) in a specific way, and then \(g(x)\) further modifies the output from \(h(x)\). The formula for composition, \(f(x) = g(h(x))\), ensures we follow the right order and end up with the correct result.
Visualizing function composition can help: imagine \(h(x)\) as a machine that modifies \(x\) in a specific way, and then \(g(x)\) further modifies the output from \(h(x)\). The formula for composition, \(f(x) = g(h(x))\), ensures we follow the right order and end up with the correct result.
- Start with \(x\).
- Apply \(h\) to \(x\).
- Then, apply \(g\) to the result of \(h(x)\).
Differentiation
Differentiation is a fundamental concept in calculus that involves finding how a function changes as its input changes. For composite functions, the chain rule is a critical tool. It helps in differentiating functions where one function is plugged into another.
Using the chain rule means you need to identify two parts of your composition:
Using the chain rule means you need to identify two parts of your composition:
- The "outer function", \(g\), which comes after.
- The "inner function", \(h\), the one done initially.
- Differentiate the outer function first, while keeping the inner function \(h(x)\) unchanged.
- Next, multiply that by the derivative of the inner function.
Other exercises in this chapter
Problem 253
[T] An athlete runs by a motion detector, which records her speed, as displayed in the following table. The best linear fit to this data, \(\ell(t)=-0.068 t+5.1
View solution Problem 254
Why is \(u\) -substitution referred to as change of variable?
View solution Problem 256
In the following exercises, verify each identity using differentiation. Then, using the indicated \(u\) -substitution, identify \(f\) such that the integral tak
View solution Problem 257
In the following exercises, verify each identity using differentiation. Then, using the indicated \(u\) -substitution, identify \(f\) such that the integral tak
View solution