Problem 253
Question
Find the curl of \(\mathbf{F}\) at the given point. \(\mathbf{F}(x, y, z)=x y z \mathbf{i}+y \mathbf{j}+z \mathbf{k}\) at (1,2,1)
Step-by-Step Solution
Verified Answer
The curl of \( \mathbf{F} \) at (1, 2, 1) is \( 0 \mathbf{i} + 2 \mathbf{j} - 1 \mathbf{k} \).
1Step 1: Understand Curl Formula
The curl of a vector field \( \mathbf{F}(x, y, z) = P \mathbf{i} + Q \mathbf{j} + R \mathbf{k} \) is given as \( abla \times \mathbf{F} = \left(\frac{\partial R}{\partial y} - \frac{\partial Q}{\partial z}\right) \mathbf{i} + \left(\frac{\partial P}{\partial z} - \frac{\partial R}{\partial x}\right) \mathbf{j} + \left(\frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y}\right) \mathbf{k} \).
2Step 2: Identify Components P, Q, and R
From the vector field \( \mathbf{F}(x, y, z) = x y z \mathbf{i} + y \mathbf{j} + z \mathbf{k} \), we identify: \( P = x y z \), \( Q = y \), and \( R = z \).
3Step 3: Compute Partial Derivatives
Calculate the necessary partial derivatives: - \( \frac{\partial R}{\partial y} = 0 \).- \( \frac{\partial Q}{\partial z} = 0 \).- \( \frac{\partial P}{\partial z} = x y \).- \( \frac{\partial R}{\partial x} = 0 \).- \( \frac{\partial Q}{\partial x} = 0 \).- \( \frac{\partial P}{\partial y} = xz \).
4Step 4: Substitute in Curl Formula
Plug the partial derivatives into the curl formula to get: \( abla \times \mathbf{F} = \left(0 - 0\right) \mathbf{i} + \left(xy - 0\right) \mathbf{j} + \left(0 - xz\right) \mathbf{k} \).
5Step 5: Simplify the Expression
Simplify the expression to: \( abla \times \mathbf{F} = 0 \mathbf{i} + xy \mathbf{j} - xz \mathbf{k} \).
6Step 6: Evaluate at Given Point
Substitute the point \((1, 2, 1)\) into the simplified curl expression:\( abla \times \mathbf{F} = 0 \mathbf{i} + (1)(2) \mathbf{j} - (1)(1) \mathbf{k} = 0 \mathbf{i} + 2 \mathbf{j} - 1 \mathbf{k} \).
Key Concepts
Curl of a Vector FieldPartial DerivativesVector Field Components
Curl of a Vector Field
The concept of the curl in vector calculus is essential for understanding the behavior of vector fields. In simple terms, the curl measures the tendency of rotation at a given point in a vector field. Consider it as a way to determine how much "twist" a vector field has.
A vector field can be written generally as \( \mathbf{F}(x, y, z) = P \mathbf{i} + Q \mathbf{j} + R \mathbf{k} \), where \( P, Q, \) and \( R \) are the field components in the respective directions. The curl of this field is calculated using the formula:
A vector field can be written generally as \( \mathbf{F}(x, y, z) = P \mathbf{i} + Q \mathbf{j} + R \mathbf{k} \), where \( P, Q, \) and \( R \) are the field components in the respective directions. The curl of this field is calculated using the formula:
- \( abla \times \mathbf{F} = \left( \frac{\partial R}{\partial y} - \frac{\partial Q}{\partial z} \right) \mathbf{i} + \left( \frac{\partial P}{\partial z} - \frac{\partial R}{\partial x} \right) \mathbf{j} + \left( \frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y} \right) \mathbf{k} \)
Partial Derivatives
Partial derivatives are a core component of multivariable calculus, helping us understand how functions change with respect to one of several variables. In the context of the curl, they allow us to calculate how each vector component changes in response to small changes in one direction, while keeping other variables constant.
When finding the curl, you need to compute specific partial derivatives, such as \( \frac{\partial R}{\partial y} \), \( \frac{\partial Q}{\partial z} \), \( \frac{\partial P}{\partial z} \), among others. Each of these derivatives tells us how a component like \( R \) changes with a small change in \( y \), for example.
When finding the curl, you need to compute specific partial derivatives, such as \( \frac{\partial R}{\partial y} \), \( \frac{\partial Q}{\partial z} \), \( \frac{\partial P}{\partial z} \), among others. Each of these derivatives tells us how a component like \( R \) changes with a small change in \( y \), for example.
- Example: For our vector field \( \mathbf{F}(x, y, z) = x y z \mathbf{i} + y \mathbf{j} + z \mathbf{k} \), we calculated \( \frac{\partial R}{\partial y} = 0 \).
Vector Field Components
Breaking down a vector field into its components makes understanding and calculations more manageable. In vector calculus, fields are often represented as a sum of vector components along the \( \mathbf{i}, \mathbf{j}, \mathbf{k} \) axes which correspond to x, y, and z directions.For the vector field \( \mathbf{F}(x, y, z) = x y z \mathbf{i} + y \mathbf{j} + z \mathbf{k} \), we identify three core components:
- \( P = x y z \) as the x-component
- \( Q = y \) as the y-component
- \( R = z \) as the z-component
Other exercises in this chapter
Problem 251
Find the curl of \(\mathbf{F}\) at the given point. \(\mathbf{F}(x, y, z)=x y z \mathbf{i}+y \mathbf{j}+x \mathbf{k}\) at (1,2,3)
View solution Problem 252
Find the curl of \(\mathbf{F}\) at the given point. \(\mathbf{F}(x, y, z)=e^{-x y} \mathbf{i}+e^{x z} \mathbf{j}+e^{y z} \mathbf{k}\) at (3,2,0)
View solution Problem 254
Find the curl of \(\mathbf{F}\) at the given point. \(\mathbf{F}(x, y, z)=e^{x} \sin y \mathbf{i}-e^{x} \cos y \mathbf{j}\) at (0,0,3)
View solution Problem 255
Find the curl of \(\mathbf{F}\) at the given point. Let \(\mathbf{F}(x, y, z)=\left(3 x^{2} y+a z\right) \mathbf{i}+x^{3} \mathbf{j}+\left(3 x+3 z^{2}\right) \m
View solution