Problem 25
Question
You are given one point on a line and the slope of the line. Find the coordinates of three other points on the line. $$(3,2), m=\frac{2}{3}$$
Step-by-Step Solution
Verified Answer
The points are (6, 4), (9, 6), and (0, 0).
1Step 1: Understand the Equation of a Line
The equation of a line in point-slope form is given as \(y - y_1 = m(x - x_1)\), where \((x_1, y_1)\) is a point on the line and \(m\) is the slope. Here, \(x_1 = 3\), \(y_1 = 2\), and \(m = \frac{2}{3}\).
2Step 2: Compute the General Equation of the Line
Substitute \(x_1\), \(y_1\), and \(m\) into the point-slope equation: \(y - 2 = \frac{2}{3}(x - 3)\). Simplify this to get the line equation in slope-intercept form by distributing the slope and solving for \(y\).
3Step 3: Expand and Simplify the Equation
Distribute \(\frac{2}{3}\) in the equation: \(y - 2 = \frac{2}{3}x - 2\). Then add 2 to both sides to get \(y = \frac{2}{3}x\). This is the simplified equation of the line.
4Step 4: Choose Values for \(x\) to Find Corresponding \(y\)
Pick different values for \(x\). Let's choose \(x = 6, 9, 0\). Substitute each \(x\) into the equation \(y = \frac{2}{3}x\) to find \(y\) values.
5Step 5: Compute Coordinates for Chosen \(x\) Values
- For \(x = 6\): \(y = \frac{2}{3} \times 6 = 4\), so point is \((6, 4)\).- For \(x = 9\): \(y = \frac{2}{3} \times 9 = 6\), so point is \((9, 6)\).- For \(x = 0\): \(y = \frac{2}{3} \times 0 = 0\), so point is \((0, 0)\).
Key Concepts
SlopePoint-Slope FormEquation of a Line
Slope
The slope is a fundamental concept in algebra when dealing with lines on a graph. Essentially, the slope measures the steepness or incline of a line. More formally, it shows how much the line rises or falls for each unit of run. In our given exercise, the slope is \( m = \frac{2}{3} \). This means that for every 3 units we move horizontally (to the right on a graph), the line moves 2 units vertically (upwards).
Understanding this ratio helps in visualizing how quickly a line rises or drops as you move along it.
Understanding this ratio helps in visualizing how quickly a line rises or drops as you move along it.
- Rise: The vertical change between two points on the line (in this case, 2).
- Run: The horizontal change between those same two points (in this case, 3).
Point-Slope Form
The point-slope form is a convenient way to write the equation of a line when you know one point on the line and the slope. The general formula is \( y - y_1 = m(x - x_1) \). Here, \((x_1, y_1)\) represents a known point on the line, and \( m \) is the slope we talked about earlier.
In the exercise, the given point is \((3, 2)\), and the slope \( m = \frac{2}{3} \).
In the exercise, the given point is \((3, 2)\), and the slope \( m = \frac{2}{3} \).
- Step 1: Substitute \( x_1 = 3 \), \( y_1 = 2 \), and \( m = \frac{2}{3} \) into the formula to create the equation of our line.
- Step 2: This gives us \( y - 2 = \frac{2}{3}(x - 3) \).
Equation of a Line
Once we have a point-slope equation, it's possible to simplify it to the slope-intercept form \( y = mx + b \) for ease of further computation or graphing. For our exercise, the step-by-step solution guides us to simplify by distributing and combining like terms.
- Expand: Distribute \( \frac{2}{3} \) across \( (x - 3) \) to simplify the right side of \( y - 2 = \frac{2}{3}(x - 3) \).
- Simplify: Solve for \( y \) by adding 2 to both sides, yielding \( y = \frac{2}{3}x \).
Other exercises in this chapter
Problem 25
\(-x+5 y=14\) for \(y\)
View solution Problem 25
Solve each system by using either the substitution or the elimination-by- addition method, whichever seems more appropriate. $$\left(\begin{array}{l}5 x-2 y=1 \
View solution Problem 26
Find the equation of the line with the given slope and \(y\) intercept. Leave your answers in slope-intercept form. (Objective 1a) \(m=4\) and \(b=-3\)
View solution Problem 26
For Problems \(23-32\), find the equation of the line with the given slope and \(y\) intercept. Leave your answers in slope-intercept form. $$ m=4 \text { and }
View solution