Problem 25
Question
Write a verbal expression to represent each equation. \(y^{2}=4 y\)
Step-by-Step Solution
Verified Answer
y squared equals four times y.
1Step 1: Identifying equation components
The equation given is \(y^2 = 4y\). Let's break it down into two parts: \(y^2\) is 'y squared' and \(4y\) is 'four times y'.
2Step 2: Constructing the verbal expression
Now that we have identified the components, we can write the equation as a verbal expression. Since \(y^2\) appears on the left side and is equal to \(4y\), we say 'y squared equals four times y.'
Key Concepts
EquationsAlgebraic ExpressionsQuadratic Equations
Equations
An equation is a mathematical statement that asserts the equality of two expressions. It consists of two sides separated by an equal sign (=). Each side of the equation represents a mathematical expression, and the basic purpose is to find the values that make the equation true. In the context of the original exercise, the equation is given as \(y^2 = 4y\). Here,
- \(y^2\) is the expression on the left side.
- \(4y\) is the expression on the right side.
Algebraic Expressions
Algebraic expressions are combinations of numbers, variables, and mathematical operators, such as addition, subtraction, multiplication, and division. These expressions form the building blocks of algebraic equations. In the equation \(y^2 = 4y\), both \(y^2\) and \(4y\) are algebraic expressions.
These expressions:
These expressions:
- Can contain constants (like 4 in the expression \(4y\)).
- Include variables (such as \(y\) in both expressions).
- Use operators, like multiplication indicated implicitly in \(4y\) as "four times \(y\)".
Quadratic Equations
Quadratic equations are a type of polynomial equation where the highest degree of the variable is squared. The general form of a quadratic equation is \(ax^2 + bx + c = 0\). In the original exercise, the equation is \(y^2 = 4y\), which can be rearranged to fit the standard form of a quadratic equation:
- By subtracting \(4y\) from both sides, it transforms to \(y^2 - 4y = 0\).
- This makes it evident as a quadratic since there's an \(y^2\) term and the equation equals zero.
Other exercises in this chapter
Problem 25
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