Problem 25
Question
Which of the series in Exercises 13 46 converge, and which diverge? Give reasons for your answers. (When you check an answer, remember that there may be more than one way to determine the series' convergence or divergence.) $$ \sum_{n=0}^{\infty} \frac{-2}{n+1} $$
Step-by-Step Solution
Verified Answer
The series diverges, as it resembles the harmonic series (which diverges) multiplied by a constant.
1Step 1: Identify the series
The series given is: \( \sum_{n=0}^{\infty} \frac{-2}{n+1} \). It is a straightforward infinite series where the terms are of the form \( a_n = \frac{-2}{n+1} \).
2Step 2: Check the conditions for divergence
A series \( \sum a_n \) diverges if the general term \( a_n \) does not approach zero as \( n \to \infty \). Calculate \( \lim_{n \to \infty} \frac{-2}{n+1} \).
3Step 3: Calculate the limit
Compute the limit: \( \lim_{n \to \infty} \frac{-2}{n+1} = 0 \). Though these terms approach 0, we need to apply additional tests because this alone does not confirm convergence.
4Step 4: Use Divergence Test
For a series applying the divergence test, if the limit of \( a_n \) does not equal 0, then the series must diverge. Here, \( lim_{n \to \infty} \frac{-2}{n+1} = 0 \), so we need another test.
5Step 5: Recognize the Harmonic Series and its Divergence
Observe that the series \( \sum \frac{-2}{n+1} = -2 \sum \frac{1}{n+1} \) resembles the harmonic series. The harmonic series \( \sum \frac{1}{n} \) is known to diverge. Thus, multiplying it by a constant (\(-2\)) will still result in divergence.
Key Concepts
Infinite SeriesHarmonic SeriesDivergence TestLimit of a Series
Infinite Series
An infinite series is the sum of infinitely many terms that follow a specific pattern. Think of it like a never-ending sequence of numbers added together. In mathematical terms, it is represented as:
- \( \sum_{n=0}^{\infty} a_n \)
Harmonic Series
The harmonic series is a famous example of an infinite series defined as:
- \( \sum_{n=1}^{\infty} \frac{1}{n} \)
Divergence Test
To determine if an infinite series diverges, one common method is the divergence test. The idea is straightforward: if the limit of the terms \( a_n \) as \( n \to \infty \) is not zero, then the series definitely diverges. However, the opposite isn't necessarily true:
- If \( \lim_{n \to \infty} a_n = 0 \), the test is inconclusive.
- In this case, it might still converge or diverge.
Limit of a Series
The limit of a series is an essential concept in determining whether a series converges or diverges. We often look at the limit of the general term \( a_n \) as \( n \to \infty \):
- \( \lim_{n \to \infty} a_n \)
Other exercises in this chapter
Problem 24
Find a formula for the \(n\)th term of the sequence. $$ \frac{1}{25}, \frac{8}{125}, \frac{27}{625}, \frac{64}{3125}, \frac{125}{15,625}, \dots $$
View solution Problem 25
Find the Taylor series generated by \(f\) at \(x=a.\) \(f(x)=x^{3}-2 x+4, \quad a=2\)
View solution Problem 25
Find a polynomial that will approximate \(F(x)\) throughout the given interval with an error of magnitude less than \(10^{-3}.\) \begin{equation} F(x)=\int_{0}^
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Which of the series in Exercises \(17-56\) converge, and which diverge? Use any method, and give reasons for your answers. $$ \sum_{n=1}^{\infty}\left(\frac{n}{
View solution