Problem 25
Question
Use variation of parameters to solve the given system. \(\mathbf{X}^{\prime}=\left(\begin{array}{rr}1 & -1 \\ 1 & 1\end{array}\right) \mathbf{X}+\left(\begin{array}{l}\cos t \\ \sin t\end{array}\right) e^{t}\)
Step-by-Step Solution
Verified Answer
The solution is a combination of the homogeneous solution with a particular solution obtained via variation of parameters.
1Step 1: Identify the Homogeneous System
We start by considering the homogeneous part of the differential equation: \( \mathbf{X}' = \begin{pmatrix} 1 & -1 \ 1 & 1 \end{pmatrix} \mathbf{X} \). This is the associated homogeneous system of differential equations.
2Step 2: Find the Eigenvalues and Eigenvectors
To find the eigenvalues, solve \( \text{det}(A - \lambda I) = 0 \) where \( A = \begin{pmatrix} 1 & -1 \ 1 & 1 \end{pmatrix} \) and \( I \) is the identity matrix. Calculate \( \text{det}(\begin{pmatrix} 1-\lambda & -1 \ 1 & 1-\lambda \end{pmatrix}) = (1-\lambda)^2 + 1 = 0 \). The solutions \( \lambda = 1 + i\) and \( \lambda = 1 - i \) give the eigenvalues. Using these, find the corresponding eigenvectors to determine the general solution of the homogeneous system.
3Step 3: Solve the Homogeneous System
Using the eigenvalues \(\lambda = 1+i\) and \(\lambda = 1-i\), compute the eigenvectors. For \(\lambda = 1+i\), substitute back into \((A - \lambda I)\mathbf{v}=0\) to find the eigenvector \(\mathbf{v}_1\). Similarly, compute for \(\lambda = 1-i\) to get \(\mathbf{v}_2\). The general solution for the homogeneous system is \( \mathbf{X}_h = c_1 e^{t}(\cos t \mathbf{v}_1 - \sin t \mathbf{v}_2)+ c_2 e^{t}(\sin t \mathbf{v}_1 + \cos t \mathbf{v}_2) \).
4Step 4: Apply Variation of Parameters
The particular solution is given by \( \mathbf{X}_p = \mathbf{X}_h \int \mathbf{X}_h^{-1} \mathbf{g}(t) \, dt \), where \( \mathbf{g}(t) = e^t \begin{pmatrix} \cos t \ \sin t \end{pmatrix} \). Calculate the inverse of the fundamental matrix formed by solutions of the homogeneous system, then integrate the product \( \mathbf{X}_h^{-1} \mathbf{g}(t) \) to find \( \mathbf{X}_p \).
5Step 5: Write the General Solution
The general solution is \( \mathbf{X}(t) = \mathbf{X}_h(t) + \mathbf{X}_p(t) \). Combine the homogeneous and particular solutions obtained to express \( \mathbf{X}(t) \) completely.
Key Concepts
Linear Differential EquationsEigenvalues and EigenvectorsHomogeneous SystemsParticular Solution Calculation
Linear Differential Equations
Linear differential equations form the backbone of many systems in mathematics and engineering. A linear differential equation involves an unknown function and its derivatives. For systems, these equations are often written in matrix form, such as \( \mathbf{X}^{\prime} = A\mathbf{X} \), where \( A \) is a matrix and \( \mathbf{X} \) is a vector.
These equations can describe a wide range of physical systems and phenomena. The solutions to these equations provide insight into the behavior of dynamic systems.
These equations can describe a wide range of physical systems and phenomena. The solutions to these equations provide insight into the behavior of dynamic systems.
- Matrix Form: It allows for the compact representation and manipulation of systems of equations.
- Constant Coefficients: In our exercise, the matrix \( A \) has constant entries.
- Time Variation: The non-homogeneous part varies with time and adds complexity to the solution process.
Eigenvalues and Eigenvectors
Eigenvalues and eigenvectors play a crucial role in solving linear differential equations. For a matrix \( A \), eigenvalues \( \lambda \) are scalars that provide insights into the dynamics of the system.
To find these, we solve the characteristic equation \( \det(A - \lambda I) = 0 \). This can yield real or complex values, and these help form the basis for solution methods.
To find these, we solve the characteristic equation \( \det(A - \lambda I) = 0 \). This can yield real or complex values, and these help form the basis for solution methods.
- Complex Eigenvalues: In the given problem, the eigenvalues are complex (\( 1 + i \) and \( 1 - i \)), indicating oscillatory behavior.
- Eigenvectors: These vectors indicate the direction of the stretching induced by the matrix.
Homogeneous Systems
A homogeneous system is one where there is no external input, simply described as \( \mathbf{X}^{\prime} = A\mathbf{X} \). Here, no forcing functions are involved, which simplifies the analysis.
The solution strategy involves using the derived eigenvalues and eigenvectors to form the general solution. For instance, with eigenvalues like \( 1 + i \), the solution incorporates exponential growth with oscillations.
The solution strategy involves using the derived eigenvalues and eigenvectors to form the general solution. For instance, with eigenvalues like \( 1 + i \), the solution incorporates exponential growth with oscillations.
- General Solution: The solution typically includes terms with \( e^{\lambda t} \), reflecting the system's natural response.
- Superposition Principle: The total solution is a combination of modes corresponding to each eigenvalue.
Particular Solution Calculation
Calculating a particular solution using variation of parameters involves including the non-homogeneous part. Considered a powerful tool, this method expands the solution to account for external influences.
Variation of parameters leverages the homogeneous solution as a baseline and adjusts it based on the non-homogeneous term. The process involves more steps, including inversion and integration.
Variation of parameters leverages the homogeneous solution as a baseline and adjusts it based on the non-homogeneous term. The process involves more steps, including inversion and integration.
- Fundamental Matrix: This is composed of homogeneous solutions.
- Integration: The core task is integrating the modified system, which involves matrix inverse and non-homogeneous parts.
Other exercises in this chapter
Problem 24
In Problems 21-30, find the general solution of the given system. $$ X^{\prime}=\left(\begin{array}{rr} 12 & -9 \\ 4 & 0 \end{array}\right) X $$
View solution Problem 24
In Problems 21-24, verify that the vector \(\mathbf{X}_{p}\) is a particular solution of the given system. $$ \begin{aligned} &\mathbf{X}^{\prime}=\left(\begin{
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Prove that the general solution of $$ \mathbf{X}^{\prime}=\left(\begin{array}{lll} 0 & 6 & 0 \\ 1 & 0 & 1 \\ 1 & 1 & 0 \end{array}\right) \mathbf{X} $$ on the i
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In Problems 21-30, find the general solution of the given system. $$ \begin{aligned} &\frac{d x}{d t}=3 x-y-z \\ &\frac{d y}{d t}=x+y-z \\ &\frac{d z}{d t}=x-y+
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