Problem 25
Question
Use the Law of Sines to solve for all possible triangles that satisfy the given conditions. $$ a=26, \quad c=15, \quad \angle C=29^{\circ} $$
Step-by-Step Solution
Verified Answer
There are two possible triangles: one with angles \( 57.1^{\circ}, 93.9^{\circ}, 29^{\circ} \) and sides \( 26, 30.9, 15 \); the other with angles \( 122.9^{\circ}, 28.1^{\circ}, 29^{\circ} \) and sides \( 26, 12.9, 15 \).
1Step 1: Identify Given Values and Setup Equation
We are given \( a = 26 \), \( c = 15 \), and \( \angle C = 29^{\circ} \). We will use the Law of Sines to find \( \angle A \). The Law of Sines states: \( \frac{a}{\sin A} = \frac{c}{\sin C} \). Rearrange this to solve for \( \sin A \): \[ \sin A = \frac{a \cdot \sin C}{c}. \] Substitute the known values: \[ \sin A = \frac{26 \cdot \sin(29^{\circ})}{15}. \]
2Step 2: Calculate \( \sin A \)
Calculate \( \sin(29^{\circ}) \) and then solve for \( \sin A \): \[ \sin A = \frac{26 \cdot 0.4848}{15} = 0.8393. \]
3Step 3: Determine Possible Angles for \( A \)
Since \( \sin A \approx 0.8393 \), \( \angle A \) can be computed as \( A = \sin^{-1}(0.8393) \approx 57.1^{\circ} \). The ambiguous case suggests that \( \angle A \) could also be \( 180^{\circ} - 57.1^{\circ} = 122.9^{\circ} \). Both solutions need to be checked to ensure they produce valid triangles.
4Step 4: Find Possible \( \angle B \) and Check Validity
Using \( \angle A = 57.1^{\circ} \), calculate \( \angle B = 180^{\circ} - 57.1^{\circ} - 29^{\circ} = 93.9^{\circ} \). All angles are positive and less than 180°. Now, check the second case with \( \angle A = 122.9^{\circ} \): \( \angle B = 180^{\circ} - 122.9^{\circ} - 29^{\circ} = 28.1^{\circ} \). Additionally, all angles are positive and less than 180°.
5Step 5: Solve for Side \( b \) in Both Cases
Apply the Law of Sines to find \( b \) for both valid triangle solutions. For \( \angle A = 57.1^{\circ} \), \[ b = \frac{a \cdot \sin B}{\sin A} = \frac{26 \cdot \sin(93.9^{\circ})}{\sin(57.1^{\circ})} \approx 30.9. \] For \( \angle A = 122.9^{\circ} \), \[ b = \frac{a \cdot \sin B}{\sin A} = \frac{26 \cdot \sin(28.1^{\circ})}{\sin(122.9^{\circ})} \approx 12.9. \]
Key Concepts
Triangle SolutionsAngle CalculationAmbiguous CaseTrigonometry
Triangle Solutions
In trigonometry, solving a triangle means finding all its angles and sides. For some triangles, this might involve using the Law of Sines, especially when dealing with non-right triangles. This law is particularly useful when you have certain known values, such as two sides and one angle (SSA scenario), or two angles and one side (AAS or ASA scenarios). In this context, solving a triangle refers to:
- Determining all the missing angles and sides.
- Identifying any possible solutions and ensuring their validity.
- Making use of trigonometric identities to find the values efficiently.
Angle Calculation
Calculating angles in a triangle involves using trigonometric principles, particularly the Law of Sines or Law of Cosines, depending on what information is available. When applying the Law of Sines:
- The formula is used: \( \frac{a}{\sin A} = \frac{c}{\sin C} \).
- To isolate \( \sin A \), rearrange to find the needed value: \( \sin A = \frac{a \cdot \sin C}{c} \).
- Use a calculator to find \( \sin C \) when given \( \angle C \).
Ambiguous Case
The ambiguous case arises when we deal with the SSA configuration of a triangle, where two sides and a non-included angle are known. This situation can potentially lead to:
- No solution.
- One valid triangle.
- Two possible triangles.
- All angles being positive.
- Their sums equaling 180°.
- All sides having positive lengths calculated from the Law of Sines.
Trigonometry
Trigonometry provides tools like the Law of Sines to solve triangles, especially useful for non-right angled situations. It centers around the relationships between angles and sides of triangles.
- The primary functions are Sine, Cosine, and Tangent, crucial in relating angles to side ratios.
- For solving non-right triangles, the Law of Sines helps compute unknown angles and sides when specific parts are given.
- This law is represented as \( \frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C} \).
Other exercises in this chapter
Problem 24
9–32 Find the exact value of the trigonometric function. $$\cos \frac{7 \pi}{3}$$
View solution Problem 24
Evaluate the expression without using a calculator. $$\sin 30^{\circ} \csc 30^{\circ}$$
View solution Problem 25
\(25-30\) me measure of an angle in standard position is given. Find two positive angles and two negative angles that are coterminal with the given angle. $$ 50
View solution Problem 25
9–32 Find the exact value of the trigonometric function. $$\cos \left(-\frac{7 \pi}{3}\right)$$
View solution