Problem 25
Question
Use the definition of logarithmic function to evaluate the function at the indicated value of \(x\) without using a calculator. (Value) $$x=16$$ $$x=\frac{1}{4}$$ $$x=\frac{1}{1000}$$ $$x=100,000$$ (Function) $$g(x)=\log _{10} x$$
Step-by-Step Solution
Verified Answer
The evaluations of the function at the given values are \(g(16) = 1.204\), \(g(1/4) = -0.602\), \(g(1/1000) = -3\) and \(g(100,000) = 5\).
1Step 1: Evaluate \(g(16)\)
We note that \(16=10^{1.204}\). Therefore, \(g(16)=\log_{10}(16) = \log_{10}(10^{1.204}) = 1.204\)
2Step 2: Evaluate \(g(1/4)\)
Observe that \(1/4 = 10^{-0.602}\). Hence, \(g(1/4)=\log_{10}(1/4) = \log_{10}(10^{-0.602}) = -0.602\)
3Step 3: Evaluate \(g(1/1000)\)
We find that \(1/1000 = 10^{-3}\). So, \(g(1/1000)=\log_{10}(1/1000) = \log_{10}(10^{-3}) = -3\)
4Step 4: Evaluate \(g(100,000)\)
Finally, recognize that \(100,000 = 10^{5}\). As a result, \(g(100,000)=\log_{10}(100,000) = \log_{10}(10^{5}) = 5\)
Key Concepts
Evaluating Logarithms Without a CalculatorProperties of LogarithmsLogarithm Base 10Exponential and Logarithmic Relationships
Evaluating Logarithms Without a Calculator
Mastering the skill of evaluating logarithms without the aid of a calculator is a valuable asset, particularly when working with simple bases such as 10. To achieve this, one must understand that a logarithm, in essence, answers the question: 'To what exponent must we raise the base to obtain a certain number?'
For example, when asked to find \( \log_{10}16 \) without a calculator, you must think in terms of powers of 10. While 16 is not a perfect power of 10, recognizing that \( 10^{1} = 10 \) and \( 10^{2} = 100 \) can guide you to estimate that \( \log_{10}16 \) is slightly more than 1 but less than 2. Similarly, \( \log_{10}\frac{1}{4} \) requires understanding negative exponents and seeing \( \frac{1}{4} \) as \( 10^{-0.602} \) demonstrates this relationship.
Practice with various numbers can sharpen one's ability to recognize these relationships quickly and estimate logarithmic values without digital tools.
For example, when asked to find \( \log_{10}16 \) without a calculator, you must think in terms of powers of 10. While 16 is not a perfect power of 10, recognizing that \( 10^{1} = 10 \) and \( 10^{2} = 100 \) can guide you to estimate that \( \log_{10}16 \) is slightly more than 1 but less than 2. Similarly, \( \log_{10}\frac{1}{4} \) requires understanding negative exponents and seeing \( \frac{1}{4} \) as \( 10^{-0.602} \) demonstrates this relationship.
Practice with various numbers can sharpen one's ability to recognize these relationships quickly and estimate logarithmic values without digital tools.
Properties of Logarithms
Logarithmic Identity
One of the fundamental properties of logarithms is the logarithmic identity: \( \log_{b}(b^{x}) = x \). This property allows for simplification and is pivotal when evaluating logarithms as the exponent can be directly extracted.Product, Quotient, and Power Properties
Additionally, key properties which include the product \( \log_{b}(xy) = \log_{b}(x) + \log_{b}(y) \), quotient \( \log_{b}(\frac{x}{y}) = \log_{b}(x) - \log_{b}(y) \), and power rules \( \log_{b}(x^{n}) = n \cdot \log_{b}(x) \) are invaluable tools for breaking down complex expressions into manageable parts.Logarithm Base 10
The base 10 logarithm, usually referred to as the common logarithm and denoted \( \log \), holds a special place because our number system is based on powers of 10. It represents how many times you must multiply 10 to obtain a certain number.
For instance, \( \log_{10}(1000) = 3 \) because \( 10 \times 10 \times 10 = 1000 \). This particular relationship forms the backbone of many scientific and engineering calculations, as it easily translates orders of magnitude into a linear form, which is easier to comprehend and manipulate.
For instance, \( \log_{10}(1000) = 3 \) because \( 10 \times 10 \times 10 = 1000 \). This particular relationship forms the backbone of many scientific and engineering calculations, as it easily translates orders of magnitude into a linear form, which is easier to comprehend and manipulate.
Exponential and Logarithmic Relationships
Exponential and logarithmic functions are inversely related; the logarithm function is the inverse of the exponential function. This means that if \( y = b^{x} \), then \( x = \log_{b}(y) \). It represents two different perspectives of the same process - one of growth (exponential) and the other of decoding that growth (logarithm).
Understanding this inverse relationship is crucial in solving exponential equations and can be particularly helpful in fields such as compound interest calculations in finance and population dynamics in biology, where exponential growth is frequently encountered.
Understanding this inverse relationship is crucial in solving exponential equations and can be particularly helpful in fields such as compound interest calculations in finance and population dynamics in biology, where exponential growth is frequently encountered.
Other exercises in this chapter
Problem 25
Approximate the logarithm using the properties of logarithms, given the values \(\log _{b} 2 \approx 0.3562\) \(\log _{b} 3 \approx 0.5646,\) and \(\log _{b} 5
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Solve the exponential equation. $$5^{x}=\frac{1}{625}$$
View solution Problem 26
Use the regression feature of a graphing utility to find a logarithmic model \(y=a+b \ln x\) for the data and identify the coefficient of determination. Use the
View solution Problem 26
Approximate the logarithm using the properties of logarithms, given the values \(\log _{b} 2 \approx 0.3562\) \(\log _{b} 3 \approx 0.5646,\) and \(\log _{b} 5
View solution