Problem 25
Question
Use the definition of a logarithm to write the equation in exponential form. For example, the exponential form of \(\log _{5} 125=3\) is \(5^{3}=125\).\(\log _{27} 3=\frac{1}{3}\)
Step-by-Step Solution
Verified Answer
The exponential form of the equation \(\log_{27} 3=\frac{1}{3}\) is \(27^{\frac{1}{3}}=3\).
1Step 1: Identify the base, argument, and logarithm
From the logarithm equation \(\log_{27} 3=\frac{1}{3}\), the base \(b\) is 27, the argument \(a\) is 3, and the logarithm of a to base b (\(c\)) is \(\frac{1}{3}\).
2Step 2: Translate to exponential form
Using the pattern of exponential form, \(b^{c} = a\), substituting the values gives us \(27^{\frac{1}{3}}=3\). So, the exponential form of \(\log_{27} 3 = \frac{1}{3}\) is \(27^{\frac{1}{3}}=3\).
Key Concepts
Exponential FormBase and Argument IdentificationProblem-Solving Steps
Exponential Form
Exponential form is a way of expressing a number using a base and an exponent. In mathematics, we use it to show repeated multiplication of a number. For instance, in the expression \(a = b^c\), \(b\) is the base, \(c\) is the exponent, and \(a\) is the result. This form is particularly useful for simplifying multiplication of the same number over and over.
A logarithm is inherently related to exponents. Specifically, if you know the logarithmic form, you can easily convert it to exponential form. For example, the equation \(\log_b a = c\) can be rewritten as \(b^c = a\). This transformation helps in solving various mathematical problems involving growth or decay, such as compound interest or radioactive decay. It’s crucial to practice changing between logarithmic and exponential form for fluency in recognizing and solving these equations.
A logarithm is inherently related to exponents. Specifically, if you know the logarithmic form, you can easily convert it to exponential form. For example, the equation \(\log_b a = c\) can be rewritten as \(b^c = a\). This transformation helps in solving various mathematical problems involving growth or decay, such as compound interest or radioactive decay. It’s crucial to practice changing between logarithmic and exponential form for fluency in recognizing and solving these equations.
Base and Argument Identification
Understanding logarithms begins with identifying the correct components: the base and the argument. When given a logarithmic equation \(\log_b a = c\), the base \(b\) is the number that is raised to the power \(c\) to get \(a\). The argument \(a\) is the result of this exponential expression. Recognizing these components is essential in evaluating or simplifying logarithms.
In the example \(\log_{27} 3 = \frac{1}{3}\), the base \(b\) is 27, and the argument \(a\) is 3. The number \(c\), which is \(\frac{1}{3}\), represents the power or exponent. Correctly identifying these parts of a logarithmic expression enables you to convert it into exponential form with confidence. By doing so, it becomes easier to solve or analyze the expression further if needed.
In the example \(\log_{27} 3 = \frac{1}{3}\), the base \(b\) is 27, and the argument \(a\) is 3. The number \(c\), which is \(\frac{1}{3}\), represents the power or exponent. Correctly identifying these parts of a logarithmic expression enables you to convert it into exponential form with confidence. By doing so, it becomes easier to solve or analyze the expression further if needed.
Problem-Solving Steps
Efficient problem-solving with logarithms requires a clear understanding of the process. Let’s go through the steps taken to convert the logarithmic equation \(\log_{27} 3 = \frac{1}{3}\) into its exponential form:
- **Step 1:** Identify the Components
Recognize the base, argument, and result of the logarithm. In this case, the base \(b\) is 27, the argument \(a\) is 3, and the exponent or result \(c\) is \(\frac{1}{3}\). - **Step 2:** Apply the Exponential Pattern
Use the template \(b^c = a\) to set up the equation. Here, substitute the known values into the structure: \(27^{\frac{1}{3}} = 3\).
Other exercises in this chapter
Problem 25
Solve the exponential equation algebraically. Approximate the result to three decimal places.\(2\left(3^{x}\right)=16\)
View solution Problem 25
Evaluate the logarithm. Round your result to three decimal places.\(\log _{2} 6\)
View solution Problem 25
Sketch the graph of the function.\(g(x)=4^{-x}-2\)
View solution Problem 26
Solve the exponential equation algebraically. Approximate the result to three decimal places.\(3\left(4^{x}\right)=81\)
View solution