Problem 25
Question
Use Descartes's rule of signs to obtain information regarding the roots of the equations. $$x^{3}+5=0$$
Step-by-Step Solution
Verified Answer
No positive real roots; exactly one negative real root.
1Step 1: Convert to Standard Form
The given equation is already in a polynomial form: \(x^3 + 5 = 0\). To use Descartes’s Rule of Signs, express it as \(x^3 + 0x^2 + 0x + 5 = 0\). This way, the polynomial function is \(f(x) = x^3 + 0x^2 + 0x + 5\).
2Step 2: Identify Sign Changes in the Polynomial
Observe the coefficients of the polynomial \(f(x) = x^3 + 0x^2 + 0x + 5\). The coefficients are \(1, 0, 0, 5\). The sign changes from positive to positive (as 0 does not affect changes), so there are no sign changes in \(f(x)\). According to Descartes's rule, the number of positive real roots is zero.
3Step 3: Analyze Roots for Negative Values
To analyze negative roots, consider \(f(-x)\):\(-x^3 + 0x^2 + 0x + 5\). The coefficients are \(-1, 0, 0, 5\), so the signs change from negative to positive once at the transition from \(-1\) to \(5\). So, according to Descartes's Rule, there is one negative real root.
Key Concepts
polynomial equationspositive and negative rootssign changes in polynomials
polynomial equations
Polynomial equations are mathematical expressions that consist of variables raised to whole number exponents and have one or more terms. The form of these equations can range from the simplest to highly complex structures.
In our example, the given equation is a polynomial equation of degree 3, expressed as:
In our example, the given equation is a polynomial equation of degree 3, expressed as:
- \(x^3 + 5 = 0\)
- \(f(x) = x^3 + 0x^2 + 0x + 5\)
positive and negative roots
The roots of a polynomial equation are the solutions that make the equation equal to zero. Descartes's Rule of Signs can predict the number of possible positive and negative roots based on the sign changes in the polynomial.When assessing for positive roots, we look directly at the polynomial as is. In the case of:
- \(f(x) = x^3 + 0x^2 + 0x + 5\)
- \(f(-x) = -x^3 + 0x^2 + 0x + 5\)
sign changes in polynomials
Sign changes in polynomials are examined to determine the potential number of real roots in different sign categories (positive or negative). This approach stems from Descartes's Rule of Signs.For our polynomial \(f(x) = x^3 + 0x^2 + 0x + 5\), when you observe the non-zero coefficients \([1, 0, 0, 5]\) for \(x\) values and \([-1, 0, 0, 5]\) for \(-x\), your focus is on how often the signs change between these coefficients.
- With \(f(x)\), there is:
- With \(f(x)\), there is:
- No change from positive to negative or vice versa, so no positive roots.
- One change from negative to positive.
Other exercises in this chapter
Problem 25
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