Problem 25
Question
Under the same reaction conditions, initial concentration of \(1.386 \mathrm{~mol}\) \(\mathrm{dm}^{-3}\) of a substance becomes half in 40 seconds and 20 seconds through first order and zero order kinetics, respectively. Ratio \(\left(k_{1} / k_{0}\right)\) of the rate constant for first order \(\left(k_{1}\right)\) and zero order \(\left(k_{0}\right)\) of the reaction is \(-\) [2008](a) \(0.5 \mathrm{~mol}^{1} \mathrm{dm}^{3}\) (b) \(1.0 \mathrm{~mol} \mathrm{dm}^{3}\) (c) \(1.5 \mathrm{~mol} \mathrm{dm}^{-3}\) (d) \(2.0 \mathrm{~mol}^{-1} \mathrm{dm}^{3}\)
Step-by-Step Solution
Verified Answer
Option (a) 0.5 mol⁻¹ dm³.
1Step 1: Understand the Reaction Half-life for First Order
For first order reactions, the half-life \( t_{1/2} \) is independent of the initial concentration. We use the formula: \[ t_{1/2} = \frac{0.693}{k_1} \] where \( k_1 \) is the rate constant for the first order reaction.
2Step 2: Calculate Rate Constant for First Order Reaction
Given that the half-life \( t_{1/2} \) for the first order reaction is 40 seconds, we can rearrange the formula from Step 1 to find \( k_1 \): \[ k_1 = \frac{0.693}{40} \approx 0.017325 \text{s}^{-1} \]
3Step 3: Understand Zero Order Kinetics
For zero order reactions, the half-life depends on the initial concentration \( [A]_0 \). The formula for half-life is: \[ t_{1/2} = \frac{[A]_0}{2k_0} \] where \( k_0 \) is the rate constant for zero order kinetics.
4Step 4: Calculate Rate Constant for Zero Order Reaction
Given the initial concentration \( [A]_0 = 1.386 \text{ mol} \text{ dm}^{-3} \) and half-life \( t_{1/2} = 20 \text{ seconds} \), we rearrange the formula from Step 3 to find \( k_0 \): \[ k_0 = \frac{[A]_0}{2 \times 20} = \frac{1.386}{40} = 0.03465 \text{ mol dm}^{-3} \text{s}^{-1} \]
5Step 5: Calculate the Ratio of Rate Constants
To find the ratio \( \frac{k_1}{k_0} \), divide the first order rate constant by the zero order rate constant:\[ \frac{k_1}{k_0} = \frac{0.017325}{0.03465} = 0.5 \text{ dm}^{3} \text{ mol}^{-1} \]
6Step 6: Choose the Correct Answer
The correct answer for the ratio \( \frac{k_1}{k_0} \) is option (a) which is \(0.5 \text{ mol}^{-1} \text{ dm}^{3}\).
Key Concepts
First Order KineticsZero Order KineticsReaction Half-life
First Order Kinetics
First order kinetics describes a reaction where the rate is directly proportional to the concentration of one reactant. This means that as the concentration of the reactant decreases, the rate of the reaction also decreases at the same proportion. One of the key characteristics of first order reactions is that the half-life, which is the time it takes for half of the reactant to be consumed, remains constant regardless of the initial concentration. This is significant because it simplifies calculations and predictions regarding the behavior of such reactions.
For first order reactions, the half-life can be calculated using the formula:
For first order reactions, the half-life can be calculated using the formula:
- \( t_{1/2} = \frac{0.693}{k_1} \)
Zero Order Kinetics
Zero order kinetics is quite different from first order kinetics. In zero order reactions, the rate is independent of the concentration of the reactant. This means that the reaction proceeds at a constant rate until the reactant is exhausted. Such behavior is typically observed when there is a constant supply of energy or a saturating catalytic surface, as can occur in certain industrial processes.
For zero order reactions, the half-life is dependent on the initial concentration, and it can be determined by the formula:
For zero order reactions, the half-life is dependent on the initial concentration, and it can be determined by the formula:
- \( t_{1/2} = \frac{[A]_0}{2k_0} \)
Reaction Half-life
Reaction half-life provides a quick way to understand how fast a reaction progresses, by measuring the time it takes for the concentration of a reactant to decrease by half. This concept is integral to kinetics, as it reveals the dynamics of both first and zero order reactions.
In the context of first order kinetics, the half-life is invariant, meaning it doesn’t change regardless of how much reactant you start with. This makes it straightforward to apply in many chemical reactions.
Conversely, in zero order reactions, the half-life depends on the initial concentration of the reactant, offering a different perspective on how the reaction progresses. It illustrates how greater initial concentrations result in longer half-lives. Understanding half-life allows chemists and researchers to plan and adjust reactions efficiently, ensuring the desired progress rate. The distinction between the two helps in selecting the ideal conditions for industrial and laboratory processes, solving practical problems in chemistry and beyond.
In the context of first order kinetics, the half-life is invariant, meaning it doesn’t change regardless of how much reactant you start with. This makes it straightforward to apply in many chemical reactions.
Conversely, in zero order reactions, the half-life depends on the initial concentration of the reactant, offering a different perspective on how the reaction progresses. It illustrates how greater initial concentrations result in longer half-lives. Understanding half-life allows chemists and researchers to plan and adjust reactions efficiently, ensuring the desired progress rate. The distinction between the two helps in selecting the ideal conditions for industrial and laboratory processes, solving practical problems in chemistry and beyond.
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