Problem 25
Question
Two stable compounds of formula \(\mathrm{C}_{6} \mathrm{H}_{6}\) react with bromine and with \(\mathrm{KMnO}_{4} .\) On hydrogenation with a platinum catalyst at \(25^{\circ}\), both absorb two moles of hydrogen and form cyclohexane. Write possible structures for these substances and explain how electronic spectra may be used to tell which compound is which.
Step-by-Step Solution
Verified Answer
Possible structures are 1,3-cyclohexadiene and 1,4-cyclohexadiene; electronic spectra can differentiate them.
1Step 1: Identify C6H6 Compounds
Both compounds given, with the formula \(\text{C}_6\text{H}_6\), share the same molecular formula as benzene. However, they react differently when subjected to bromine and \(\text{KMnO}_4\). The fact that they both absorb two moles of hydrogen to form cyclohexane suggests they initially contain double bonds that are reduced to form saturated cyclohexane.
2Step 2: Analyze Bromine Reaction
Since both compounds react with bromine, they must have unsaturated bonds. Bromine adds across double bonds, indicating each has at least one such bond that reacts with bromine.
3Step 3: Interaction with KMnO4
\(\text{KMnO}_4\) typically oxidizes carbon-carbon double bonds. The fact that it reacts with the compounds further supports the presence of unsaturated portions within their structures.
4Step 4: Hydrogenation Resulting in Cyclohexane
Each compound absorbs two moles of hydrogen during hydrogenation. This implies the presence of exactly two double bonds within the original \(\text{C}_6\text{H}_6\) molecules, as each mole of hydrogen reduces one double bond. Both must be cyclic structures to form cyclohexane upon complete hydrogenation.
5Step 5: Possible Structures
The structures that meet these criteria with two double bonds are 1,3-cyclohexadiene and 1,4-cyclohexadiene, both cyclohexenes capable of reacting with bromine and \(\text{KMnO}_4\) and absorbing two moles of hydrogen.
6Step 6: Use of Electronic Spectra
To differentiate these compounds, electronic (UV-Vis) spectra can be used. 1,3-cyclohexadiene would typically show a longer absorption maximum due to extended conjugation compared to 1,4-cyclohexadiene, which lacks such conjugation.
Key Concepts
C6H6 CompoundsBromine ReactionKMnO4 OxidationHydrogenationElectronic Spectra
C6H6 Compounds
In organic chemistry, the formula \(\text{C}_6\text{H}_6\) is most famously associated with benzene, a compound consisting of a ring of six carbon atoms with alternating single and double bonds. However, the problem hints at the existence of isomeric forms that retain the same formula but possess different structures. This gives rise to the possibility that our \(\text{C}_6\text{H}_6\) compounds could be different isomers like 1,3-cyclohexadiene and 1,4-cyclohexadiene. These alternative structures are characterized by possessing two carbon-carbon double bonds within a cyclic carbon architecture.
- They maintain the \(\text{C}_6\text{H}_6\) composition but vary significantly in arrangement.
- Isomers like 1,3-cyclohexadiene can have extended conjugation, affecting their reactivity and chemical behavior.
Bromine Reaction
Reactions with bromine can provide insights into the presence of unsaturated bonds within a compound. Bromine readily reacts with alkenes — compounds containing carbon-carbon double bonds — resulting in the addition of bromine across these double bonds. This reaction is useful for identifying the presence of such double bonds.
- Both \(\text{C}_6\text{H}_6\) isomers react with bromine, confirming that they are not purely aromatic like benzene; they have traditional alkene character.
- The addition of bromine helps distinguish these compounds from benzene, which tends to undergo substitution rather than addition.
KMnO4 Oxidation
Potassium permanganate (\(\text{KMnO}_4\)) is a strong oxidizing agent often used to test for the presence of unsaturated bonds, particularly carbon-carbon double bonds. When \(\text{KMnO}_4\) oxidizes these bonds, it typically results in the breakdown of the initial compound, often meaning a color change from purple to colorless.
- If \(\text{KMnO}_4\) reacts, it supports the presence of unsaturated bonds, eliminating the possibility of strictly aromatic structures like benzene.
- The oxidation reaction shines light on structural differences, helping identify which isomers are present.
Hydrogenation
Hydrogenation involves the addition of hydrogen (\(\text{H}_2\)) across double or triple bonds, reducing them to single bonds and saturating the compound. In our \(\text{C}_6\text{H}_6\) substances, hydrogenation leads to the formation of cyclohexane, indicating they originally contained double bonds.
- Each isomer absorbs two moles of hydrogen, reducing two double bonds to form a fully saturated cyclohexane ring.
- This process implies that both 1,3-cyclohexadiene and 1,4-cyclohexadiene structures exist, as these are able to accept two additional moles of hydrogen.
Electronic Spectra
Electronic spectra, specifically UV-Vis spectroscopy, are used to study compounds by examining the absorption of ultraviolet or visible light. This technique can distinguish different structures based on their conjugation — the presence and arrangement of alternating single and double bonds.
- 1,3-cyclohexadiene, with its conjugated system, generally shows longer wavelength absorption maxima than non-conjugated isomers like 1,4-cyclohexadiene.
- The spectra help confirm structural configurations, distinguishing between these \(\text{C}_6\text{H}_6\) isomers.
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