Problem 25
Question
These problems involve permutations. Seating Arrangements In how many different ways can six of ten people be seated in a row of six chairs?
Step-by-Step Solution
Verified Answer
There are 151200 ways to seat six of ten people in a row.
1Step 1: Understanding Permutations
Permutations involve arranging a certain number of items from a larger set where the order of arrangement matters. In this problem, we're arranging 6 out of 10 people.
2Step 2: Setting Up the Formula
To find the number of ways to arrange 6 people from a set of 10, we use the permutation formula: \[ P(n, r) = \frac{n!}{(n - r)!} \]where \( n \) is the total number of people (10 in this case) and \( r \) is the number of people to arrange (6 in this case).
3Step 3: Calculate Factorials
Calculate the factorials needed: - \(10! = 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1\)- \(4! = 4 \times 3 \times 2 \times 1\)
4Step 4: Compute the Permutation
Plug the factorials into the permutation formula: \[ P(10, 6) = \frac{10!}{(10 - 6)!} = \frac{10!}{4!} \]This simplifies to: \[ P(10, 6) = \frac{10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4!}{4!} \]Since the \(4!\) cancels out, we are left with: \[ 10 \times 9 \times 8 \times 7 \times 6 \times 5 \]
5Step 5: Perform the Multiplication
Calculate the result of the multiplication: \[ 10 \times 9 \times 8 \times 7 \times 6 \times 5 = 151200 \]
6Step 6: Conclude the Calculation
Thus, the number of different ways to seat six of the ten people in a row of six chairs is 151200.
Key Concepts
Seating ArrangementsPermutation FormulaFactorialsCombinatorics
Seating Arrangements
When it comes to seating arrangements, the order in which individuals are seated matters a lot. Imagine having ten friends and wanting to seat six of them in a row. The specific order in which these six friends are arranged leads to different seating combinations. For example, switching the first and second seat changes the entire arrangement. This is why we use permutations, which focus on ordered arrangements. Each unique order is called a permutation.
Permutation Formula
The permutation formula helps us calculate the number of ways to arrange a subset of items from a larger set. It is expressed as \[ P(n, r) = \frac{n!}{(n-r)!} \]where:
- \( n \) is the total number of items to choose from.
- \( r \) is the number of items to arrange.
Factorials
Factorials are essential in calculating permutations. A factorial, denoted by an exclamation mark (!), is the product of all positive integers up to a certain number. For example,
- \(5! = 5 \times 4 \times 3 \times 2 \times 1\)
- \(10! = 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1\)
Combinatorics
Combinatorics is the branch of mathematics dealing with counting, arrangement, and combination of elements in sets. It answers questions like "How many ways can these people be seated?". By understanding combinatorics, we learn to solve problems involving ordering and selecting items. This field uses concepts like permutations and combinations, allowing us to tackle various arrangement puzzles efficiently. Whether it's seating friends or organizing events, combinatorics provides the tools needed to find the best arrangement.
Other exercises in this chapter
Problem 24
Three CDs are picked at random from a collection of 12 \(\mathrm{CDs}\) of which four are defective. Find the probability of the following events. (a) All three
View solution Problem 24
Combination Lock A combination lock has 60 different positions. To open the lock, the dial is turned to a certain number in the clockwise direction, then to a n
View solution Problem 25
Defective Light Bulbs The DimBulb Lighting Company manufactures light bulbs for appliances such as ovens and refrigerators. Typically, 0.5\(\%\) of their bulbs
View solution Problem 25
A five-card poker hand is drawn from a standard 52 -card deck. Find the probability that at least one card is a spade.
View solution