Problem 25
Question
The value of \(\lim _{x \rightarrow-\infty}\left[\frac{x^{4} \sin (1 / x)+x^{2}}{1+|x|^{3}}\right]\) is (A) 1 (B) \(-1\) (C) 0 (D) \(\infty\)
Step-by-Step Solution
Verified Answer
The limit is 0.
1Step 1: Rewriting the Expression
First, let's rewrite the expression more clearly: \[ \lim_{x \rightarrow -\infty} \left[ \frac{x^4 \sin \left( \frac{1}{x} \right) + x^2}{1 + |x|^3} \right] \]. Here, as \(x\) approaches \(-\infty\), \(x^4\) becomes very large, whereas \(\sin\left(\frac{1}{x}\right)\) remains bounded between \(-1\) and \(1\).
2Step 2: Simplifying by Dominant Terms
The dominant term in the numerator is \(x^4 \sin\left(\frac{1}{x}\right)\), but \(x^4 \sin\left(\frac{1}{x}\right)\) contributes less to the numerator compared to \(x^4\) alone because \(\sin\left(\frac{1}{x}\right)\) is always between \(-1\) and \(1\). Also, observe \( |x| = -x\) since \(x\) is negative. So, simplify as: \( \frac{x^4 \sin\left(\frac{1}{x}\right) + x^2}{1 + x^3} \).
3Step 3: Approximating the Limit's Numerator and Denominator
As \(x\) approaches \(-\infty\), the most significant term in the numerator is \(x^2\) and in the denominator \(x^3\). Thus, the expression becomes approximately \( \frac{x^2}{-x^3} = -\frac{1}{x} \).
4Step 4: Taking the Limit
Find the limit of \(-\frac{1}{x}\) as \(x\) approaches \(-\infty\). Since \(-\frac{1}{x}\) approaches 0 because \(\frac{1}{x}\) approaches 0, the entire limit converges to 0.
Key Concepts
Asymptotic BehaviorInfinity ApproachTrigonometric Limits
Asymptotic Behavior
In mathematics, asymptotic behavior refers to how a function behaves as the input value approaches a significant point, often infinity. When dealing with limits, understanding asymptotic behavior is crucial to grasp what happens when a function stretches to large values or approaches specific input values.
Asymptotic expressions help in determining the dominant terms, thus simplifying complex expressions. For instance, in the given exercise, as the variable \( x \) approaches \(-\infty\), the expression's asymptotic behavior allows us to focus only on the dominant parts.
Asymptotic expressions help in determining the dominant terms, thus simplifying complex expressions. For instance, in the given exercise, as the variable \( x \) approaches \(-\infty\), the expression's asymptotic behavior allows us to focus only on the dominant parts.
- The most significant impact will arise from the highest power of \( x \) in the numerator and denominator.
- This focus results in an approximation that simplifies the evaluation of the limit as \( x \) becomes very large.
Infinity Approach
When we talk about the infinity approach, we refer to the limit analysis as the variable approaches positive or negative infinity. This can often mean understanding how terms grow relative to each other as the input, such as \( x \) in our expression, becomes infinite.
Limits at infinity are especially useful in understanding functions' end behavior. This exercise requires us to examine the function as \( x \) approaches \(-\infty\).
Limits at infinity are especially useful in understanding functions' end behavior. This exercise requires us to examine the function as \( x \) approaches \(-\infty\).
- By recognizing how the terms in our expression behave as \( x \) stretches to very large negative numbers, we can simplify the problem.
- We watch for which terms become negligible and which dominate due to their relative growth rates.
Trigonometric Limits
Trigonometric limits are a specialized area focusing on limits involving trigonometric functions. In the exercise provided, the function \( \sin\left(\frac{1}{x}\right) \) plays a role, given that \( x \) approaches \(-\infty\).
Despite \( x \) changing significantly, \( \sin\left(\frac{1}{x}\right) \) exhibits bounded behavior.
Despite \( x \) changing significantly, \( \sin\left(\frac{1}{x}\right) \) exhibits bounded behavior.
- The sine function's inherent property is its periodicity and its values always remain between \(-1\) and \(1\).
- This bounded nature influences how terms involving sine functions contribute to limits, making expressions with large coefficients like \( x^4 \sin\left(\frac{1}{x}\right) \) manageable.
Other exercises in this chapter
Problem 23
\(\lim _{x \rightarrow 1 \atop y \rightarrow 0} \frac{y^{3}}{x^{3}-y^{2}-1}\) as \((x, y) \rightarrow(1,0)\) along the line \(y=\) \(x-1\) is given by (A) 1 (B)
View solution Problem 24
\(\lim _{n \rightarrow \infty} \frac{1-2+3-4+5-6+\ldots-2 n}{\sqrt{n^{2}+1}+\sqrt{4 n^{2}-1}}\) is equal to (A) \(\frac{1}{3}\) (B) \(-\frac{1}{3}\) (C) \(-\fra
View solution Problem 26
\(\lim _{x \rightarrow 2} \frac{2^{x}+2^{3-x}-6}{2^{-x / 2}-2^{1-x}}\) is equal to (A) 8 (B) 4 (C) 2 (D) None of these
View solution Problem 27
\(\lim _{x \rightarrow 0} \frac{8}{x^{8}}\left(1-\cos \frac{x^{2}}{2}-\cos \frac{x^{4}}{4}+\cos \frac{x^{2}}{2} \cos \frac{x^{2}}{4}\right)\) is equal to (A) \(
View solution