Problem 25
Question
The pressure \(p\) of the atmosphere at height \(h\) above ground level is given by \(p=p_{0} \mathrm{e}^{-h / c}\), where \(p_{0}\) is the pressure at ground level and \(c\) is a constant. Determine the rate of change of pressure with height when \(p_{0}=10^{5}\) Pascals and \(c=6.2 \times 10^{4}\) at 1550 metres.
Step-by-Step Solution
Verified Answer
The rate of change of pressure with height at 1550 meters is approximately -1.57 Pascals per meter.
1Step 1: Understand the Formula
We have the formula for atmospheric pressure at height given by \(p = p_0 e^{-h / c}\). Here, \(p_0\) is the pressure at ground level and \(c\) is a constant related to the atmosphere's properties.
2Step 2: Differentiate the Formula
To find the rate of change of pressure with respect to height, we need to differentiate \(p = p_0 e^{-h/c}\) with respect to \(h\). The derivative of \(e^{-h/c}\) with respect to \(h\) is \(-\frac{1}{c} e^{-h/c}\), so:\[\frac{dp}{dh} = p_0 \left( -\frac{1}{c} e^{-h/c} \right) = -\frac{p_0}{c} e^{-h/c}.\]
3Step 3: Substitute Known Values
We substitute the known values: \(p_0 = 10^5\) Pascals, \(c = 6.2 \times 10^4\) m, and \(h = 1550\) m into the derivative to find the rate of change:\[\frac{dp}{dh} = -\frac{10^5}{6.2 \times 10^4} e^{-1550 / 6.2 \times 10^4}.\]
4Step 4: Simplify the Exponent
Calculate the value of the exponent:\[-\frac{1550}{6.2 \times 10^4} \approx -0.025.\]
5Step 5: Calculate the Exponential Term
Compute the value of the exponential term:\[e^{-0.025} \approx 0.9753.\]
6Step 6: Final Rate of Change Calculation
Substitute the value of the exponential term:\[\frac{dp}{dh} = -\frac{10^5}{6.2 \times 10^4} \times 0.9753 \approx -1.57 \, \text{Pascals per meter}.\]
Key Concepts
DifferentiationExponential FunctionsAtmospheric Pressure
Differentiation
Differentiation is a fundamental concept in calculus that describes the rate at which a function changes at any given point. It's like understanding how fast you're driving at a specific moment. This rate of change is what we call the derivative. In mathematical terms, it's the slope of the tangent line to the function at a given point.
When you differentiate a function, you are essentially finding a new function which gives you the slope at any point on the original curve. For linear functions, this is straightforward as the slope is constant. However, for more complex functions, including exponential functions, differentiation is crucial to understand dynamic changes.
When you differentiate a function, you are essentially finding a new function which gives you the slope at any point on the original curve. For linear functions, this is straightforward as the slope is constant. However, for more complex functions, including exponential functions, differentiation is crucial to understand dynamic changes.
- The factor "-1/c" arises from the chain rule applied to exponential functions.
- The final derivative, \(-\frac{p_0}{c} e^{-h/c}\), tells us how the pressure decreases with height.
Exponential Functions
Exponential functions are a type of mathematical function where the variable is an exponent. These functions are widely used in real-world applications because they model growth or decay processes very effectively. Examples include population growth, radioactive decay, and finance.
In the context of atmospheric pressure, exponential functions describe how pressure decreases as you rise higher in altitude. The function \(p = p_0 e^{-h/c}\) is a classic example where pressure decreases exponentially with height.
In the context of atmospheric pressure, exponential functions describe how pressure decreases as you rise higher in altitude. The function \(p = p_0 e^{-h/c}\) is a classic example where pressure decreases exponentially with height.
- The base of the exponential function in this case is e, a mathematical constant approximately equal to 2.718.
- e is the natural base because it naturally arises in contexts involving continuous growth or decay.
Atmospheric Pressure
Atmospheric pressure is the force exerted by the weight of the air in the Earth's atmosphere. At sea level, it's about 101325 Pascals or 1013.25 hPa. As you ascend, the air becomes less dense, and thus the pressure decreases.
This pressure drop with increasing altitude is predictable with an exponential function, where the rate of decrease is influenced by properties like temperature and the composition of the atmosphere.
This pressure drop with increasing altitude is predictable with an exponential function, where the rate of decrease is influenced by properties like temperature and the composition of the atmosphere.
- At 1550 meters, pressure changes can be precisely calculated using the differentiated function.
- Understanding this concept is crucial for fields such as meteorology, aviation, and even personal activities like hiking.
Other exercises in this chapter
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