Problem 25
Question
The point is on the terminal side of an angle in standard position. Determine the exact values of the six trigonometric functions of the angle. $$(-3,-\sqrt{7})$$
Step-by-Step Solution
Verified Answer
The exact values of the six trigonometric functions for the angle where the point (-3,-\sqrt{7}) lies on the terminal side are: Sin\(\theta\) = -\sqrt{7}/4, Cos\(\theta\) = -3/4, Tan\(\theta\) = \sqrt{7}/3, Cosec\(\theta\) = -4/\sqrt{7}, Sec\(\theta\) = -4/3, Cot\(\theta\) = 3/\sqrt{7}
1Step 1: Calculate the radius \(r\)
First, calculate the radius or hypotenuse of the triangle formed by \(x\), \(y\), and \(r\). We can use the Pythagorean theorem to calculate \(r\). The formula is \(r = \sqrt{x^2+y^2}\). Here, \(x=-3\) and \(y=-\sqrt{7}\). So, \(r = \sqrt{(-3)^2+(-\sqrt{7})^2} = \sqrt{9+7} = \sqrt{16} = 4.\) So, \(r\) equals to 4.
2Step 2: Calculate the six trigonometric functions
Now use \(x\), \(y\), and \(r\) to calculate the exact value of the six trigonometric functions. In this case: \n1. Sin\(\theta\) = \(y/r = -\sqrt{7}/4\)\n2. Cos\(\theta\) = \(x/r = -3/4\)\n3. Tan\(\theta\) = \(y/x = \sqrt{7}/3\)\n4. Cosec\(\theta\) is the reciprocal of Sin\(\theta\) = \(-4/\sqrt{7}\)\n5. Sec\(\theta\) is the reciprocal of Cos\(\theta\) = \(-4/3\)\n6. Cot\(\theta\) is the reciprocal of Tan\(\theta\) = \(3/\sqrt{7}\)
Key Concepts
Pythagorean TheoremStandard PositionReciprocal IdentitiesExact Values
Pythagorean Theorem
The Pythagorean theorem is a fundamental principle in mathematics, especially in trigonometry. It relates the lengths of the sides of a right triangle. By the theorem, the square of the hypotenuse (the side opposite the right angle) is the sum of the squares of the other two sides.
For a point \(x, y\) on the terminal side in standard position, we use the coordinates as the legs of a right triangle. Therefore, the hypotenuse \(r\) can be calculated by \[ r = \sqrt{x^2 + y^2} \]. Here, the values given are \(x = -3\) and \(y = -\sqrt{7}\).
Plug into the formula:
For a point \(x, y\) on the terminal side in standard position, we use the coordinates as the legs of a right triangle. Therefore, the hypotenuse \(r\) can be calculated by \[ r = \sqrt{x^2 + y^2} \]. Here, the values given are \(x = -3\) and \(y = -\sqrt{7}\).
Plug into the formula:
- \( r = \sqrt{(-3)^2 + (-\sqrt{7})^2} = \sqrt{9 + 7} = \sqrt{16} = 4 \)
Standard Position
Angles in trigonometry are often described in standard position, which means the angle's vertex is at the origin of a coordinate plane, and its initial side lies along the positive x-axis.
This setup helps in defining trigonometric functions using coordinates. When the terminal side of the angle passes through a point like \(-3, -\sqrt{7}\), it forms a triangle with the x-axis and helps determine key values.
Moving to coordinates is a common strategy to visualize angles and makes calculating trigonometric functions possible using the point's location.
This setup helps in defining trigonometric functions using coordinates. When the terminal side of the angle passes through a point like \(-3, -\sqrt{7}\), it forms a triangle with the x-axis and helps determine key values.
Moving to coordinates is a common strategy to visualize angles and makes calculating trigonometric functions possible using the point's location.
Reciprocal Identities
Reciprocal identities are essential in trigonometry, providing an easy way to find three additional functions: cosecant, secant, and cotangent.
- Cosecant \( (\text{csc}) \) is the reciprocal of sine: \( \text{csc}(\theta) = \frac{1}{\sin(\theta)} \).
- Secant \( (\text{sec}) \) is the reciprocal of cosine: \( \text{sec}(\theta) = \frac{1}{\cos(\theta)} \).
- Cotangent \( (\text{cot}) \) is the reciprocal of tangent: \( \text{cot}(\theta) = \frac{1}{\tan(\theta)} \).
- \( \text{csc}(\theta) = -\frac{4}{\sqrt{7}} \)
- \( \text{sec}(\theta) = -\frac{4}{3} \)
- \( \text{cot}(\theta) = \frac{3}{\sqrt{7}} \)
Exact Values
Finding the exact values of trigonometric functions is crucial for precise calculations. These values stem from specific circle points or basic angles.
In our exercise, calculating the functions for the point \(-3, -\sqrt{7}\), with \(x, y,\) and \(r = 4\), we derived:
Accurate calculation of these values assures consistent results in various trigonometric scenarios.
In our exercise, calculating the functions for the point \(-3, -\sqrt{7}\), with \(x, y,\) and \(r = 4\), we derived:
- \( \sin(\theta) = -\frac{\sqrt{7}}{4} \)
- \( \cos(\theta) = -\frac{3}{4} \)
- \( \tan(\theta) = \frac{\sqrt{7}}{3} \)
Accurate calculation of these values assures consistent results in various trigonometric scenarios.
Other exercises in this chapter
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