Problem 25

Question

The normal boiling point of \(\mathrm{Br}_{2}(l)\) is \(58.8^{\circ} \mathrm{C}\), and its molar enthalpy of vaporization is \(\Delta H_{\text {vap }}=29.6 \mathrm{kl} / \mathrm{mol}\). (a) When \(\mathrm{Br}_{2}(l)\) boils at its normal boiling point, does its entropy increase or decrease? (b) Calculate the value of \(\Delta S\) when \(1.00\) mol of \(\mathrm{Br}_{2}(l)\) is vaporized at \(58.8^{\circ} \mathrm{C}\)

Step-by-Step Solution

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Answer
(a) The entropy of liquid Bromine increases when it boils at its normal boiling point. (b) The change in entropy when 1.00 mol of liquid Bromine is vaporized at 58.8°C is \(89.12 \, J/mol \cdot K\).
1Step 1: Convert temperature from Celsius to Kelvin
First, we need to convert the temperature from Celsius to Kelvin using the following formula: T(K) = T(°C) + 273.15 T(K) = 58.8 + 273.15 T(K) = 331.95 K
2Step 2: Calculate the change in entropy
Now that we have the temperature in Kelvin, we can proceed to calculate the change in entropy using the formula: ΔS = ΔH_vap / T where ΔH_vap is in J/mol First, convert ΔH_vap from kJ/mol to J/mol by multiplying by 1000: \(ΔH_{vap} = 29.6 \, kJ/mol * 1000 = 29600 \, J/mol\) Now, we can plug in the values we have into the equation: ΔS = 29600 J/mol / 331.95 K ΔS = 89.12 J/(mol K)
3Step 3: Determine if the entropy increases or decreases
Since ΔS is a positive value (89.12 J/mol K), this means that the entropy of Bromine increases when it boils at its normal boiling point. #Answer#: (a) The entropy of liquid Bromine increases when it boils at its normal boiling point. (b) The change in entropy when 1.00 mol of liquid Bromine is vaporized at 58.8°C is 89.12 J/mol K.

Key Concepts

Understanding Entropy in Phase ChangesThe Role of Enthalpy in Phase TransitionsPhase Transition: Boiling of Bromine
Understanding Entropy in Phase Changes
Entropy is a key concept in thermodynamics, representing the degree of disorder or randomness in a system. During a phase change, such as boiling, the system's entropy changes. For instance, when
  • liquid bromine (\(\text{Br}_2(l)\)) boils, it transitions from a more ordered liquid state to a less ordered gas state.
  • Since gases have more freedom of movement, they are more disordered, leading to an increase in entropy.
This is why the change in entropy \(\Delta S\) is positive when bromine boils at its normal boiling point of 58.8°C. The calculated entropy change of 89.12 J/(mol K) confirms that there is an increase in disorder.
The Role of Enthalpy in Phase Transitions
Enthalpy is the total heat content of a system and plays a vital role during phase transitions. When bromine boils, it requires energy to overcome intermolecular forces.
  • This energy change is known as the molar enthalpy of vaporization \(\Delta H_{vap}\).
  • For bromine, \(\Delta H_{vap}\) is 29.6 kJ/mol at its normal boiling point.
This endothermic process absorbs heat from the surroundings, helping bromine transition to a gaseous phase. During boiling, heat is absorbed without changing temperature but increases the enthalpy of the system, facilitating the transition.
Phase Transition: Boiling of Bromine
Phase transitions involve a change of state, and understanding them requires considering both entropy and enthalpy. For bromine:
  • The boiling point is 58.8°C or 331.95 K, where the liquid turns to vapor.
  • During this transition, the entropy increases as the molecules spread out in the gas phase.
The calculated positive \(\Delta S\) indicates increased disorder. The process involves absorbing heat (endothermic), leading to a phase change where enthalpy rises. This dual consideration of entropy and enthalpy helps explain why boiling occurs and its energetic nature.